2) The bar shown has a cross-sectional area of 0.001 m² and a modulus of elasticity of 100 GPa. It is subjected to a uniformly distributed axial force q = 50kN/m pointed to the left. An external axial force F= 20 kN, pointed to the left, is applied at the middle of the bar, x = L/2. a. What is the axial force P in the bar as a function of x? b. What is the bar's total change in length? x=L/2 = 0.5 m 9 x=L = 1 m

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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2) The bar shown has a cross-sectional area
of 0.001 m² and a modulus of elasticity of
100 GPa. It is subjected to a uniformly
distributed axial force q = 50kN/m pointed
to the left. An external axial force F= 20
kN, pointed to the left, is applied at the
middle of the bar, x = L/2.
a. What is the axial force P in the bar
as a function of x?
b. What is the bar's total change in
length?
- F
x=L/2
= 0.5 m
- 9
x=L
= 1 m
Transcribed Image Text:2) The bar shown has a cross-sectional area of 0.001 m² and a modulus of elasticity of 100 GPa. It is subjected to a uniformly distributed axial force q = 50kN/m pointed to the left. An external axial force F= 20 kN, pointed to the left, is applied at the middle of the bar, x = L/2. a. What is the axial force P in the bar as a function of x? b. What is the bar's total change in length? - F x=L/2 = 0.5 m - 9 x=L = 1 m
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