Test the claim that the proportion of men who own cats is larger than 50% at the .005 significance level. The null and alternative hypothesis would be: О Но:р 3D 0.5 Ha:p+ 0.5 Но: д — 0.5 Ha: µ + 0.5 Ο 10: μ = 0.5 Ha:µ > 0.5 Ho: µ = 0.5 Ha:µ < 0.5 Но: р 3 0.5 Ha:p < 0.5 O Ho:p = 0.5 Ha:p > 0.5 The test is: right-tailed left-tailed two-tailed
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From the provided information,
The claim is that the proportion of men who own cats is larger than 50%.
Level of significance (α) = 0.005
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- A random sample of n = 25 individuals is selected from a population with a mean of = 20, and a treatment is administered to each individual in the sample. After treatment, the sample mean is found to be M = 22.2 with SS=384. a) How much difference is there between the mean for the treated sample and the mean for the original population? (Note: In a hypothesis test, this value forms the numerator of the t statistic.) b.) If there is no treatment effect, how much difference is expected between the sample mean and its population mean? That is, find the standard error for M. ? (Note: In a hypothesis test, this value is the denominator of the tstatistic.) c) Based on the sample data, does the treatment have a significant effect? Use a two-tailed test with a = 0.05 .A consumer group plans a comparative study of the mean life of four different brands of batteries. Ten batteries of each brand will be randomly selected and the time until the energy level falls below a pre-specified level is measured. a) Which of the following is the appropriate alternative hypothesis for the null hypothesis: H0: μa = μb = μc = μd? (In this problem, μa = mean time of Brand A, μb = mean time of Brand B, etc.) Ha: none of the means are equal Ha: μa ≠ μb ≠ μc ≠ μd Ha: μa ≠ μb, μa ≠ μc, μa ≠ μd, μb ≠ μc, μb ≠ μd, μc ≠ μd Ha: at least one of the means is different b)In order to analyze the data with ANOVA, we need to satisfy the condition of randomization. How do we know that this condition has been met? -One SRS of batteries is selected from a collection of batteries of all brands. -The batteries are randomly allocated to the four brands. -Separate random samples of batteries are selected from each brand.Suppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 . Using the above data and calculating a 95% CI for the difference between the actual average stopping distance of cars equipped with brake system 1 and cars with brake system 2. The calculated range suggests that accurate information about the value of this difference is available? From this information, it is possible to mark the alternative as correct: a) The calculated range is (-13.50, -11.80). With this range, even with values so close, it is not possible to say that precise information is available. b) The calculated range is (-20.40, -6.80). With this interval, even being so wide, it is possible to affirm that accurate information is…
- Listed below are the lead concentrations in ug/g measured in different traditional medicines. Use a 0.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 16 ug/g. 6 22.5 14 9 4 18 9.5 17.5 9 9.5 D What are the null and alternative hypotheses? Ο Β. Ho μ= 16 μgg Ο Α. Ho μ= 16 μgg H:µ 16 µg/g O D. Ho: H> 16 µg/g Η: μ< 16 μgg Determine the test statistic. (Round to two decimal places as needed.) State the final conclusion that addresses the original claim. V Ho. There is V evidence to conclude that the mean lead concentration for all such medicines is V 16 µg/g.Select the most appropriate response.It is claimed that the mean age of bus drivers in Chicago is 50.2 years. If a hypothesis test is performed, how should you interpret a decision that rejects the null hypothesis? Question 1 options: There is not sufficient evidence to support the claim μ = 50.2. There is not sufficient evidence to reject the claim μ = 50.2. There is sufficient evidence to support the claim μ = 50.2. There is sufficient evidence to reject the claim μ = 50.2.For a chi-square goodness-of-fit test for the one-way table, which of the following is a valid null hypothesis? #3 C E There is no relationship between blood type and hair color in the population. Oл₁-0.25, л₂ = 0.5, л3 = 0.5 Oл₁= 0.3, л₂ = 0.4, л3 = 0.3 D $ 4 R tv F Q Search or enter address % e 5 T G 6 MacBook Pro Y & 7 A H + U * 00 8 J 1 ( 9
- A researcher wonders if a “majority” of all residents of a particular city were in favor of a newly proposed city ordinance. Her hypotheses are H0: p = 0.5 versus Ha: p > 0.5. She collected data from a large enough random sample of residents (in order to use the normal approximation), and the resulting sample proportion was 0.41. The researcher has a few interns working on this project and has asked them to conduct the appropriate test and report an approximate p-value. Unfortunately, she received three different p-values from her interns: Chris reported a p-value of 0.08 Jamie reported a p-value of 0.41 Taylor reported a p-value of 0.62 A. Which of her interns reported a reasonable p-value? Explain. Hint: The precise p-value cannot be computed here, but you can eliminate interns' guesses. B. Use the p-value from part (a) to determine if a majority of all residents of the city were in favor of a newly proposed city ordinance.The null and alternate hypotheses are:H0 : μ1 = μ2H1 : μ1 ≠ μ2A random sample of 10 observations from one population revealed a sample mean of 23 and a sample standard deviation of 4. A random sample of 8 observations from another population revealed a sample mean of 26 and a sample standard deviation of 5.The population standard deviations are unknown but assumed to be equal. At the 0.05 significance level, is there a difference between the population means? a. State the decision rule. b. Compute the pooled estimate of the population variance c. Compute the test statistic. d. State your decision about the null hypothesis. e. The p-value isSuppose μ1 and M₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. Use the two-sample t test at significance level 0.01 to test Ho: μ₁ −μ₂ = -10 versus H₂: M₁ M₂ < -10 for the following data: m = 8, x = 114.6, s₁ = 5.05, n = 8, y = 129.5, and s₂ = 5.33. USE SALT Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. Reject Ho. The data suggests that the difference between mean stopping distances is less than -10. Reject Ho. The data does not suggest that the difference between mean stopping distances is less than -10. Fail to reject Ho. The data suggests that the difference between mean stopping distances is less than -10. Fail to reject Ho. The data does not suggest that the difference between mean stopping distances is less than -10. You may need to use the…
- 9.12 Independent random samples selected from two normal populations produced the following sample means and standard deviations: Sample 1 Sample 2 n1 = 17 n2 = 12 x₁ = 5.4 x2 = 7.9 $1 = 3.4 $2 4.8 = variances, conduct the test a. Assuming equal Ho: (μ₁ −μ₂) = 0 against Ha: (μ₁ −μ₂) ‡ 0 using - α - .05. b. Find and interpret the 95% confidence interval for (μ₁ - M₂).5.A researcher is interested in the effectiveness of a new program at reducing the average systolicblood pressure in a population with a new anti-hypertensive medication. The researcher wants totest the hypothesis that the mean difference in systolic blood pressure is greater than 40 mmHG.Which of the following represents the correct null and alternative hypotheses for the study?A) Ho: µ1 - µ2 = 0, Ha: µ1 - µ2 = 40B) Ho: µ1 - µ2 = 40 Ha: µ1 - µ2 ≠ 40C) Ho: µD = 40 Ha: µD >40D) Ho: µD = 40 Ha: µD ≠408.26 In a test of Ho: u = 100 against Hạ: µ > 100, the sample data yielded the test statistic z = 2.17. Find and interpret the p-value for the test. , orm %3D