Suppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 . Using the above data and calculating a 95% CI for the difference between the actual average stopping distance of cars equipped with brake system 1 and cars with brake system 2. The calculated range suggests that accurate information about the value of this difference is available? From this information, it is possible to mark the alternative as correct: a) The calculated range is (-13.50, -11.80). With this range, even with values so close, it is not possible to say that precise information is available. b) The calculated range is (-20.40, -6.80). With this interval, even being so wide, it is possible to affirm that accurate information is available. c) The calculated range is (-20.40, -6.80). With such a wide range, it is not possible to say that accurate information is available. d) The calculated range is (-13.50, -11.80). With this range where the values are close, it is possible to assert that accurate information is available. e) The calculated range is (-15.86, -11.34). With such a close range of values, it is not possible to say that accurate information is available.
Suppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 .
Using the above data and calculating a 95% CI for the difference between the actual average stopping distance of cars equipped with brake system 1 and cars with brake system 2. The calculated
a) The calculated range is (-13.50, -11.80). With this range, even with values so close, it is not possible to say that precise information is available.
b) The calculated range is (-20.40, -6.80). With this interval, even being so wide, it is possible to affirm that accurate information is available.
c) The calculated range is (-20.40, -6.80). With such a wide range, it is not possible to say that accurate information is available.
d) The calculated range is (-13.50, -11.80). With this range where the values are close, it is possible to assert that accurate information is available.
e) The calculated range is (-15.86, -11.34). With such a close range of values, it is not possible to say that accurate information is available.
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