reviously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 150 pregnant mothers and finds that 2 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the α=0.05 level of significance. What are the null and alternative hypotheses? H0: ▼ pp sigmaσ muμ ▼ less than< equals= not equals≠ greater than> nothing versus H1: ▼ pp sigmaσ muμ ▼ less than< not equals≠ greater than> equals= nothing (Type integers or decimals. Do not round.) Because np01−p0=nothing ▼ greater than> not equals≠ equals= less than< 10, the normal model ▼ may may not be used to approximate the P-value. (Round to one decimal place as needed.) Find the P-value. P-value=nothing (Round to three decimal places as needed.) Is there sufficient evidence to support the obstetrician's statement? A. Yes, reject the null hypothesis because the P-value is less than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%. B. Yes, do not reject the null hypothesis because the P-value is greater than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%. C. No, do not reject the null hypothesis because the P-value is greater than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%. D. No, reject the null hypothesis because the P-value is less than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%.
reviously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 150 pregnant mothers and finds that 2 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the α=0.05 level of significance. What are the null and alternative hypotheses? H0: ▼ pp sigmaσ muμ ▼ less than< equals= not equals≠ greater than> nothing versus H1: ▼ pp sigmaσ muμ ▼ less than< not equals≠ greater than> equals= nothing (Type integers or decimals. Do not round.) Because np01−p0=nothing ▼ greater than> not equals≠ equals= less than< 10, the normal model ▼ may may not be used to approximate the P-value. (Round to one decimal place as needed.) Find the P-value. P-value=nothing (Round to three decimal places as needed.) Is there sufficient evidence to support the obstetrician's statement? A. Yes, reject the null hypothesis because the P-value is less than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%. B. Yes, do not reject the null hypothesis because the P-value is greater than α. There is sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%. C. No, do not reject the null hypothesis because the P-value is greater than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%. D. No, reject the null hypothesis because the P-value is less than α. There is not sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than 3%.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
reviously,
3%
of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than
3%
today. She randomly selects
150
pregnant mothers and finds that
2
of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the
α=0.05
level of significance.What are the null and alternative hypotheses?
H0:
▼
pp
sigmaσ
muμ
▼
less than<
equals=
not equals≠
greater than>
H1:
▼
pp
sigmaσ
muμ
▼
less than<
not equals≠
greater than>
equals=
(Type integers or decimals. Do not round.)
Because
be used to approximate the P-value.
np01−p0=nothing
10,
the normal model
▼
greater than>
not equals≠
equals=
less than<
▼
may
may not
(Round to one decimal place as needed.)
Find the P-value.
P-value=nothing
(Round to three decimal places as needed.)Is there sufficient evidence to support the obstetrician's statement?
Yes,
reject
the null hypothesis because the P-value is
less
than
α.
There
is
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3%.
Yes,
do not reject
the null hypothesis because the P-value is
greater
than
α.
There
is
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3%.
No,
do not reject
the null hypothesis because the P-value is
greater
than
α.
There
is not
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3%.
No,
reject
the null hypothesis because the P-value is
less
than
α.
There
is not
sufficient evidence to conclude that the percentage of mothers who smoke 21 or more cigarettes during pregnancy is less than
3%.
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