A 95% CI for true average serum-creatinine level was calculated as  (3.81, 3.95), based on a sample size of 20 peoples (after they received a newly proposed antibiotic) and the assumption that serum -creatinine level is normally distributed.Suppose you want to test H0: μ = 4 versus Ha: μ 4 using 5% level of significance. Without testing the hypothesis, can you write down the statistical conclusion you would make about the hypothesis. If not, then give reasons.

Q: Suppose you could take all possible samples of size n = 25 from a Normal population with mean μ = 50…

A: Given that the sample size is n=25. That is less than 30. The mean and the standard deviation of the…

Q: A well-known psychologist has established what she calls her Generalized Anxiety (GA) scale. The GA…

A: Number of adults =11Regression equation is

Q: he DASS-21 questionnaire is a validated measure of depression, anxiety, and stress. For the general…

A: Given that the mean for the anxiety for the population is 4.2 As it scales from the questions 0 to…

Q: A published report of a repeated-measures research study includes the following description of the…

A: Given information: The result show significant difference among the treatment condition. F(2,…

Q: Suppose you could take all possible samples of size n = 25 from a Normal population with mean μ = 50…

A: Given that a sample of size n = 25 is drawn from a normal population with mean μ = 50 and σ = 5.

Q: The claim is that for a smartphone carriers data speeds at airports, the mean is u= 12.00 Mbps. The…

A: Mean = 12  N= 11  df = N-1 = 10  t = 1.415

Q: You set out to conduct a hypothesis test at the 95% level. Mean yields are distributed Normally. You…

A:

Q: A doctor wants to estimate the mean HDL cholesterol of all 20-29 year old females. How many subjects…

A: formula for the sample size needed to estimate a population mean is

Q: Interpret the following statement regarding the statistical findings of a research study.  “61% (n =…

A: Introduction: The outcome of a study involving low-carbohydrate and low-fat diets is given.

Q: A manufacturer claims that 10% of women using the "pill" suffer from side effects. The Federal Drug…

A: It was found that 103 out of 900 women had side effects. Let p-cap be the sample proportion.

Q: A sample of 124 kissing couples were observed, with 44 of them leaning their heads to the left. Use…

A: The test statistic for One sample proportion test is as follows…

Q: In developing a generic drug, it is necessary for a manufacturer of biopharmaceutical products to…

A: We have given that  Sample size n =20 Sample mean =18.22 Standard deviation =0.92

Q: a test of the effectiveness of garlic for lowering​ cholesterol, 41 senior citizens were treated…

A: Concept: Parameter is the variable of population Statistic is the variable of sample

Q: A survey is conducted to determine if there is a difference in the proportion of students, parents,…

A: Given info: The chi-square test statistic is 0.19, df=2, and the P-value is greater than any…

Q: A clinical trial is planned to compare an experimental medication designed to lower blood pressure…

A: The test hypotheses are given below: From the given information, the claim of the problem is testing…

Q: Did the authors note any differences in gender with regard to fish consumption and inflammatory…

A: HI, as per our policy, we'll answer the first three subparts for you.  Given:

Q: 54% of students entering four-year colleges receive a degree within six years. Is this percent…

A: n=299x=138Population proportion(P)=0.54and

Q: To help assess the health risks of second-hand smoke, the levels of cotinine (a metabolite of…

A: The data is paired and not normally distributed, so the test used will be Wilcoxon signed rank test…

Q: A repeated-measures study comparing two treatments with a sample of n = 4 participants produces MD =…

A:

Q: A researcher would like to examine how the chemical tryptophan, contained in foods such as turkey,…

A: Given - sample size, n = 9, mean difference in score, M = 14, sum of squares of difference scores,…

Q: Suppose the average blood sugar level in 35- to 44-year-olds is 4.86 (mmol/L). Do sedentary people…

A: The hypothesized mean is 4.86.

Q: A group of health conscious researchers were interested in ways to lower blood pressure.  The study…

A: It is given that there are three intervention types on post-treatment blood pressure with each of 30…

Q: A published report of a repeated-measures research study includes the following description of the…

A: The provided information is:

Q: If your critical value is ±1.96 and your z-value is -2.44, do you reject that the sample mean…

A: From the given information,   Critical Value: ±1.96 z-value: -2.44

Q: g that = 41.0 (in milligrams per 100 millileters-mg/100 ml). If the researcher wants to be 96%…

A: The population standard deviation  (σ)  = 41.0confidence level = 96%The margin of error (E) =4To…

Q: The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day.…

A:

Q: Samuel Morse determined that the percentage of a's in the English language in the 1800s was 8%. A…

A: Denote p as the true proportion of a’s in modern newspaper. It is reported that proportion of a’s in…

Q: doctor wants to estimate the mean HDL cholesterol of all 20 to 29 year old females. How many…

A: Given s=11.2 E=2

Q: The DASS-21 questionnaire is a validated measure of depression, anxiety, and stress. For the general…

A: Hypothesis Ho: μ=4.2 vs H1: μ>4.2 test statistic=t=(x¯-μ)/s/n and df=n-1 When population…

Q: of 8,700 lbs of sugar per acre. Thus, the null and alternative hypotheses are       Ho: mu = 8,700…

A: As the population standard deviation is not known, we will use t test. The null and alternative…

Q: The EPA recommends avoiding consumption of fish species if the mercury concentration is higher than…

A: Obtain the confidence interval for the mercury concentration: The concentration in a large random…

Q: A nutrition store in the mall is selling "Memory Booster," which is a concoction of herbs and…

A: Solution: Given information: n= 16 Sample size M= 24  Sample mean μ= 20  Population meanSS= 960 sum…

Q: A normal population has a mean of μ = 25 on a communication effectiveness scale. After receiving a…

A: From the provided information, Sample size (n) = 4 Level of significance (α) = 0.05

Q: After a sample of n=25 high school students took a special training course, their SAT scores…

A: Given Data: n=25 MD=18SS=9600 Standard Deviaton=SSn-1=960024=400=20

Q: f all participants in a repeated measures research study show roughly the same difference between…

A: Hypothesis test is conducted to check the difference. To check mean differences we use either Z or T…

Q: . Do the sample data support the conclusion that the Memory Booster has a significant "booster"…

A: Answer:-  Our hypothesis is, H0 : u=20   vs   H1 : u>20 Given that, n=16 xis 26 Variance=64…

Q: You are comparing the variability of two groups of data to see if they come from the same…

A: Solution: From the given information, level of significance is 0.05, the two sample sizes are 11 and…

Q: The athletic director at a large university compared the proportions of freshmen (1st year students)…

A: The hypothesis is, Null hypothesis: H0: There is no difference between proportions of freshmen and…

Q: A survey is conducted to determine if there is a difference in the proportion of students, parents,…

A:

Q: If random samples, each with n = 16 scores, are selected from a normal population with µ = 100 and σ…

A: Here, the known values are n = 16 scores, µ = 100 and σ = 20.

Q: The average age of licensed drivers in a county is µ = 42.6, s= 10, and the distribution is…

A: The null and alternative hypotheses are, The test is two tailed test The level of significance is,…

Q: LSU's Ag. Center wants to determine whether the mean yield for sugarcane is different this year…

A: Given  x¯ = 8853σ = 1150n = 100α = 95% The null and alternate hypothesis is given as follows: H0:μ =…

Q: patients revealed that 45 patients were misdiagnosed with indigestion instead of a heart attack.…

A: Solution: Given information: p=7%= 7100=0.07q=1-p= 0.93x= 45n= 950p^= xn=45950=0.0474α=0.05

Q: Although the samples are actually related, an investigator ignores this fact in the statistical…

A: Introduction: It is required to identify how the probability of a Type II error is affected in the…

Q: b) Now suppose that the same sample proportions came from a sample of 30 times as large. That is,…

A:

Q: The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day.…

A: Test statistic: Given information: n=117x¯=12.2s=6.60μ=15 Therefore,   z=x¯-μsn  =12.2-156.60117…

Q: A research study has two samples, each with n = 6, and the two experimental treatments used in each…

A: Given that a research study has two samples, each with n = 6, and the two experimental treatments…

Q: The population of healthy female adults, the mean red blood cell count (RBC) is 4.8 (millions of…

A: It is needed to find whether the given scenario is an example of Type 1 Error, Type 2 Error, No…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.