A random sample of size 12 from a normal population has a mean of x-bar = 52.8 and s = 2.53. If%3Dyou were to test the following hypothesis at the .05 level of significance the critical region forrejecting the null hypothesis would be defined as:Ho: H= 50%3DHo: H> 50Ot> 2.179Ot> 1.782Ot> 1.796Ot> 2.201

Answered: Image /qna-images/answer/17d39220-6820-46e0-ac0b-8eb1c0d246e2.jpg

Answered: A random sample of size 12 from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Suppose μ1 and M₂ are true mean stopping distances at 50 mph for cars of a certain type equipped with two different types of braking systems. Use the two-sample t test at significance level 0.01 to test Ho: μ₁ −μ₂ = -10 versus H₂: M₁ M₂ < -10 for the following data: m = 8, x = 114.6, s₁ = 5.05, n = 8, y = 129.5, and s₂ = 5.33. USE SALT Calculate the test statistic and determine the P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = State the conclusion in the problem context. Reject Ho. The data suggests that the difference between mean stopping distances is less than -10. Reject Ho. The data does not suggest that the difference between mean stopping distances is less than -10. Fail to reject Ho. The data suggests that the difference between mean stopping distances is less than -10. Fail to reject Ho. The data does not suggest that the difference between mean stopping distances is less than -10. You may need to use the…
Below is the complete question Fail to reject / reject H0. There is not / is enough evidence at the 1% level of significance to support / reject the claim.
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In a test of hypothesis, the null hypothesis is that o = o and the alternative hypothesis is 2. Samples of sizes n₁ = 18 and n₂ = 17 selected from two normal populations produced variances of s² = 9.94 and s2 = 21.61, respectively. What is the approximate p- value for this test? O c. 0.1223 a. 0.0612 O e. 0.9388 O d. 0.4694 O b. 0.0408
The police chief selects a sample of 50 local police officers from a population of officers with a mean physical fitness rating of 75 ± 8.0 (m ± s) on a 100-point physical endurance rating scale. He measures a sample mean physical fitness rating on this scale equal to 79. He conducts a one–independent sample z test to determine whether physical endurance increased at a .05 level of significance. Compute effect size using Cohen’s d.
A random sample of size 24 and mean 2.547 was selected from normal distribution if we want to test that the population mean is less than 5.547, knowing that the sample variance 25, the critical value for alpha =0.01 is? a. 2.807 b. 2.500 c. 2.547 d. 2.33
Which of the following is a Null hypothesis for a paired-samples t-test? μd = 0 μd = X μ1 ≠ μ2 μ1 = μ2
You wish to test the claim that the average IQ score is less than 100 at the .10 significance level. You determine the hypotheses are: Ho: μ=100Ho: μ=100 H1:μ<100H1:μ<100 You take a simple random sample of 73 individuals and find the mean IQ score is 95.2, with a standard deviation of 15.1. Let's consider testing this hypothesis two ways: once with assuming the population standard deviation is not known and once with assuming that it is known. Round to three decimal places where appropriate. Assume Population Standard Deviation is NOT known Assume Population Standard Deviation is 15 Test Statistic: t = Test Statistic: z = Critical Value: t = Critical Value: z = p-value: p-value: Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Null: Reject the null hypothesis Fail to reject the null hypothesis Conclusion About the Claim: There is sufficient evidence to support the claim that the average IQ…
A random sample of size 25 from a normal population has a mean of x-bar = 62.8 and s = 3.55. If you were to test the following hypothesis at the .05 level of significance. The value of the test statistic is Họ: H = 60 %3D Họ: H+60 O-3.94 O 0.79 -0.79 O 3.94 O 2.8
For a fixed alpha level of significance used for a hypothesis test, the critical value for a chi-square statistic decreases as the size of the sample decreases. a. True b. False
Suppose the national average dollar amount for an automobile insurance claim is $777.86. You work for an agency in Michigan and you are interested in whether or not the state average is less than the national average. The hypotheses for this scenario are as follows: Null Hypothesis: μ ≥ 777.86, Alternative Hypothesis: μ < 777.86. You take a random sample of claims and calculate a p-value of 0.0232 based on the data, what is the appropriate conclusion? Conclude at the 5% level of significance. Question 9 options: 1) The true average claim amount is significantly different from $777.86. 2) The true average claim amount is significantly less than $777.86. 3) The true average claim amount is significantly higher than $777.86. 4) We did not find enough evidence to say the true average claim amount is less than $777.86. 5) The true average claim…
A researcher wishes to see if there is a difference between the mean number of hours per week that a family with no children participates in recreational activities and a family with children participates in recreational activities. She selects two random samples and the data are shown. Use μ1 for the mean number of families with no children. At α=0.10, is there a difference between the means? Use the P-value method and tables. (a) State the hypothesis and identify the claim with the correct hypothesis. H0: ▼(Choose one) H1: ▼(Choose one) This hypothesis test is a ▼(Choose one) test. (b)Find the critical value(s). Round the answer to 3decimal places, if necessary. If there ismore than one critical value, Critical values: (c)Compute the test value. Round the answer to at least 3 decimal places, if necessary. z= Compute the P -value. Round the answer to four decimal places. P-value= (d)Make the decision. What's the null hypothesis? (e)Summarize the…

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