The standard treatment for a disease works in 0.65 of all patients.A new treatment ispatients (of similar general health) isproposed. Is it better? An initial clinical trial of n = 100conducted: 73 people are cured. Assume the selection of patients is random(a) Perform a significance test to test whether the treatment is better at a 10% significance level.lp Z-=l.v5.= 73 = .731 oowe are go corfident that the populaticr.9rofortienlbe be(b) Find the power of the test under the alternative ofHa 0.810 ,812-neu PP.(I-PtoYl

Answered: The standard treatment for a disease…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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10% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 369 people from the inner city surveyed, 22 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: Ho: ? μ p Select an answer = < ≠ > (please enter a decimal) H1: ? μ p Select an answer > ≠ < = (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly smaller than 10% at αα = 0.01, so…
Researchers wanted to know if therapy could help smokers quit smoking. Of the 71 smokers they tested, 39 were smoking one year after treatment. Use a 0.05 significance level to test the claim that the majority are smoking one year after treatment. What is/are the critical value(s)? ттT Arial 3 (12pt) v TE -E · -
An ANOVA is used to evaluate the mean difference among three treatment conditions with a sample of n= 12 particpantsin each treatment. For study, what is df total?
14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…
Suppose you want to test the claim that u, > H,. Two samples are randomly selected from normal populations. The sample statistics are given below. Assume that o #o5. At a level of significance of a = 0.01, when should you reject Ho? n, = 18, n2 =13, x, = 470, x2 = 455, s, = 40, s2 = 25 %3D O A. Reject H, if the standardized test statistic is greater than 2.681. B. Reject Ho if the standardized test statistic is greater than 1.699. O C. Reject H, if the standardized test statistic is greater than 3.055. D. Reject H, if the standardized test statistic is greater than 2.179.
Can you write it in text please so I can copy and paste it!! Thank you
A repeated-measures ANOVA was calculated with df = 1, 14. If the same data were analyzed with a repeated-measures t test, how many degrees of freedom would be used with the t statistic?
Is the proportion of wildfires caused by humans in the south lower than the proportion of wildfires caused by humans in the west? 360 of the 501 randomly selected wildfires looked at in the south were caused by humans while 435 of the 588 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the = 0.10 level of significance? For this study, we should use Select an answer t-test for the difference between two dependent population means z-test for the difference between two population proportions t-test for a population mean t-test for the difference between two independent population means z-test for a population proportion The null and alternative hypotheses would be: Select an answer μ1 p1 Select an answer < ≠ > = Select an answer μ2 p2 (please enter a decimal) Select an answer μ1 p1 Select an answer > ≠ < = Select an answer p2 μ2 (Please enter a decimal) The test statistic ? z t = (please show your…
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Suppose IQ scores were obtained for 20 randomly selected sets of couples. The 20 pairs of measurements yield x = 101.02, y = 100.75, r = 0.852, P-value = 0.000, and y = 5.93 + 0.94x, where x represents the IQ score of the husband. Find the best predicted value of y given that the husband has an lQ of 100? Use a significance level of 0.05. %3D Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted value of y is Critical values of the pearson correlation coefficient r (Round to two decimal places as needed.) Critical Values of the Pearson Correlation Coefficient r X = 0.05 a = 0.01 INOTE: To test Ho: p=0 n Jagainst H,: p+0, reject Ho if the absolute value of r is greater than the critical value in the table. 4 0.950 0.990 0.878 0.959 0.811 0.917 7 0.754 0.875 0.707 0.834 0.666 0.798 10 0.632 0.765 11 0.602 0.735 12 0.576 0.708 13 0.553 0.684 14 0.532 0.661 15 0.514 0.641 16 0.497 0.623 17 0.482 0.606 18 0.468 0.590 19 0.456 0.575 20 0.444…

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