9% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 306 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.10? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer > = < ≠ (please enter a decimal) H1: ? p μ Select an answer > ≠ = < (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 9%. The data suggest the populaton proportion is significantly larger than 9% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 9% The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 9%. Interpret the p-value in the context of the study. If the population proportion of inner city residents who have sleep apnea is 9% and if another 306 inner city residents are surveyed then there would be a 0.1% chance that more than 14% of the 306 inner city residents surveyed have sleep apnea. If the sample proportion of inner city residents who have sleep apnea is 14% and if another 306 inner city residents are surveyed then there would be a 0.1% chance of concluding that more than 9% of all inner city residents have sleep apnea. There is a 0.1% chance of a Type I error. There is a 0.1% chance that more than 9% of all inner city residents have sleep apnea. Interpret the level of significance in the context of the study. If the population proportion of inner city residents who have sleep apnea is larger than 9% and if another 306 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 9%. If the population proportion of inner city residents who have sleep apnea is 9% and if another 306 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is larger than 9%. There is a 10% chance that the proportion of all inner city residents who have sleep apnea is larger than 9%. There is a 10% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth.

9% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 306 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.10? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer > = < ≠ (please enter a decimal) H1: ? p μ Select an answer > ≠ = < (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 9%. The data suggest the populaton proportion is significantly larger than 9% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 9% The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 9%. Interpret the p-value in the context of the study. If the population proportion of inner city residents who have sleep apnea is 9% and if another 306 inner city residents are surveyed then there would be a 0.1% chance that more than 14% of the 306 inner city residents surveyed have sleep apnea. If the sample proportion of inner city residents who have sleep apnea is 14% and if another 306 inner city residents are surveyed then there would be a 0.1% chance of concluding that more than 9% of all inner city residents have sleep apnea. There is a 0.1% chance of a Type I error. There is a 0.1% chance that more than 9% of all inner city residents have sleep apnea. Interpret the level of significance in the context of the study. If the population proportion of inner city residents who have sleep apnea is larger than 9% and if another 306 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 9%. If the population proportion of inner city residents who have sleep apnea is 9% and if another 306 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is larger than 9%. There is a 10% chance that the proportion of all inner city residents who have sleep apnea is larger than 9%. There is a 10% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth.

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Description: 9% of all Americans suffer from sleep apnea. A researcher suspects that a higher percentage of those who live in the inner city have sleep apnea. Of the 306 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be conclu

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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For this study, we should use Select an answer z-test for a population proportion t-test for a population mean
The null and alternative hypotheses would be:
Ho: ? μ p Select an answer > = < ≠ (please enter a decimal)
H₁: ? p μ Select an answer > ≠ = < (Please enter a decimal)

The test statistic ? t z = (please show your answer to 3 decimal places.)
The p-value = (Please show your answer to 4 decimal places.)
The p-value is ? ≤ > αα
Based on this, we should Select an answer fail to reject reject accept the null hypothesis.
Thus, the final conclusion is that ...
- The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 9%.
- The data suggest the populaton proportion is significantly larger than 9% at αα = 0.10, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 9%
- The data suggest the population proportion is not significantly larger than 9% at αα = 0.10, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is larger than 9%.
Interpret the p-value in the context of the study.
- If the population proportion of inner city residents who have sleep apnea is 9% and if another 306 inner city residents are surveyed then there would be a 0.1% chance that more than 14% of the 306 inner city residents surveyed have sleep apnea.
- If the sample proportion of inner city residents who have sleep apnea is 14% and if another 306 inner city residents are surveyed then there would be a 0.1% chance of concluding that more than 9% of all inner city residents have sleep apnea.
- There is a 0.1% chance of a Type I error.
- There is a 0.1% chance that more than 9% of all inner city residents have sleep apnea.
Interpret the level of significance in the context of the study.
- If the population proportion of inner city residents who have sleep apnea is larger than 9% and if another 306 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 9%.
- If the population proportion of inner city residents who have sleep apnea is 9% and if another 306 inner city residents are surveyed then there would be a 10% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is larger than 9%.
- There is a 10% chance that the proportion of all inner city residents who have sleep apnea is larger than 9%.
- There is a 10% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth.

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