Jennifer, a college student, would like to make the claim that the average amount that students spend on textbooks each semester is more than $225. Jennifer samples 16 of her classmates and obtains a sample mean of $244. At the 2.5% significance level, should Jennifer reject or fail to reject the null hypothesis given the sample data below? • Ho : µ= $225; H : µ > $225 0.025 (significance level) • test statistic = 2.51 a = Use the graph below to select the type of test (left-, right, or two-tailed). Then set the a and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hypothesis. Move the blue dot to choose the appropriate test Significance level = 0.025 a=0.01 a=0.025 a=0.05 a=0.1 p-value = 0.834 test statistic = 0.97 196 to

Jennifer, a college student, would like to make the claim that the average amount that students spend on textbooks each semester is more than $225. Jennifer samples 16 of her classmates and obtains a sample mean of $244. At the 2.5% significance level, should Jennifer reject or fail to reject the null hypothesis given the sample data below? • Ho : µ= $225; H : µ > $225 0.025 (significance level) • test statistic = 2.51 a = Use the graph below to select the type of test (left-, right, or two-tailed). Then set the a and the test statistic to determine the p-value. Use the results to determine whether to reject or fail to reject the null hypothesis. Move the blue dot to choose the appropriate test Significance level = 0.025 a=0.01 a=0.025 a=0.05 a=0.1 p-value = 0.834 test statistic = 0.97 196 to

Name: ### Hypothesis Testing Visualization#### Description:This image featu
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Description: ### Hypothesis Testing Visualization#### Description:This image features a standard normal distribution curve used for hypothesis testing. The x-axis represents the z-scores ranging from -4 to 4. - **Shaded Region:** Represents the p-value of 0.834,

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1
During the 1990s, the fatality rate for lung cancer was 80 per 100,000 people. After the turn of the century and the establishment of newer treatments and adjustment in public health advertising, a random sample of 10,000 people exhibits only six deaths due to lung cancer. Test at the 0.05 significance level whether that data are proof of a reduced fatality rate for lung cancer. b. Make the decision rule. (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.) c. Evaluate the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.)
Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.
Low-fat or low-carb? Are low-fat diets or low-carb diets more effective for weight loss? A sample of 77 subjects went on a low-carbohydrate diet for six months. At the end of that time, the sample mean weight loss was 4.7 kilograms with a sample standard deviation of 7.16 kilograms. A second sample of 79 subjects went on a low-fat diet. Their sample mean weight loss was 2.6 kilograms with a standard deviation of 5.90 kilograms. Can you conclude that the mean weight loss differs between the two diets? Let 4, denote the mean weight lost on the low-carb diet and u, denote the mean weight lost on the low-fat diet. Use the a = 0.01 level and the TI-84 Plus calculator. Compute the -value. Round the answer to four decimal places. Determine whether to reject H0 State a conclusion
Use the information below, gathered from 1000 students from a small college who disclosed their age as well as their preference for type of instruction, to determine whether or not there is an association between age and preferred type of instruction. Write your hypotheses, perform the test, find the test statistic, the p-value, and state your conclusion. Assume a significance level of � = 0.01. AGE 18 & under 19-25 26-35 36-45 65 or Older online 43 56 26 20 20 Scheduled Zoom 48 75 34 26 20 Hybrid Zoom 82 19 88 83 59 Face to Face 27 50 52 71 101 a) Write your hypotheses.b) Use your calculator to determine the test statistic and p-value.c) Using the significance level provided, write an appropriate conclusion
You suspect that your east-facing portion of your Macintosh apple orchard is producing less apples than your west facing portion. You decide to conduct a study of your apple trees to determine the average production of apples per tree as measured in bushels for both sections. Conduct a hypothesis test at 5% level of significance to determine if the East facing section is producing significantly less apples per tree compared to the West facing section. Use the table below. Sample size Average amount of Standard of trees deviation Bushels West 55 28 East 50 22 12 What is the p-value? p=0.0021 0.025
A program administrator at a high school wanted to see if there was a significant association between experiencing verbal abuse and anxiety in teenage women. She wasn't sure what to expect. Perform the correct statistical procedure to assess the degree of association between these variables and interpret your findings. Set alpha = .05 for your statistical test. YOU CAN EITHER TYPE YOUR WORK OUT HERE OR TAKE A PICTURE OF HANDWRITTEN WORK AND EMAIL IT TO ME. %3D Anxiety Verbal Abuse 5. 4. 4.
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Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
The summary statistics are n=85, x=3.93, s=0.63. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 4.00. identify null/ alt hypothesis, test statistic, P- value, and state final conclusion that addresses the original claim
A publisher reports that 69 % of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually under the reported percentage. A random sample of 200 found that 60% of the readers owned a particular make of car. Is there sufficient evidence at the 0.10 level to support the executive's claim? Step 5 of 7: Identify the value of the level of significance.
A statistician changes her level of significance from .001 to .05. What impact will this change have on her risk of making a Type I and Type II error? Is the change in the level of significance a good decision? Why or why not?