9.12 Independent random samples selected from two normalpopulations produced the following sample means andstandard deviations:Sample 1Sample 2n1= 17n2=12x₁ = 5.4x2 = 7.9$1= 3.4$2 4.8=variances, conduct the testa. Assuming equalHo: (μ₁ −μ₂)=0 against Ha: (μ₁ −μ₂) ‡ 0 using-α - .05.b. Find and interpret the 95% confidence interval for(μ₁ - M₂).

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Answered: standard deviations: Sample 1 Sample 2…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A company is doing a hypothesis test on the variation of quality from two suppliers. Both distributions are normal, and the populations are independent. use x = 0.01 ܐ ܕ g = ܐ ܗ : H H₂:0₁ ²0₂ The standard deviation of the first sample is 2.8914 9.2416 is the standard deviation of the second sample. The test statistic is =
WebAssign -→ xC OD Let x represent the number of mountain dimbers killed each year. The long term variance of x is approximately o= 136.2. Suppose that for the past 7 years, the vanance has been sE 110.6. Use a 1% level of significance to test the daim that the recent variance for number of mountain cimber deaths is less than 136.2., Find a 90% confidence interval for the population variance (a) What is the level of significance? State the null and alternate hypotheses. O Ho: a- 136.2; Hi o > 136.2 O Ho: - 136.2; Hạ o < 136.2 OHại o- 136.2; H o 136.2 O Hại a < 136.2; H o 136.2 (b) Find the value of the dhl-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? What assumptions are you making about the original distribution We assume a normal population distribution. We assume a binomial population distribution We assume a esponential population distribution We assume a uniform population distribution () Find or estimate the PyValue…
Perform the analysis of variance (ANOVA) at the a = 0.05 to identify is there any significant differece in the mean between the populations. It is known that there are three populations with five samples in each popula- tion in this analysis. (c) Source of variation Sum of squares 944.9333 Between Within 2224.8000 Table 4.1: Sum of squares
Answer (1.32, 10.68), (1, 11)
8
In the year 2033, Sarai Patterson is a leading traveling nurse. Sarai is interested in reducing the mean recovery time for patients after experiencing a serious injury (assume recovery times are normally distributed). Suppose the mean recovery time is presently 8.6 months. Sarai takes a random sample of 46 patients that have experienced serious injury to participate in a new treatment program and finds the sample mean is 8.1 months and a sample standard deviation of 1.2 months. Using α = 0.05, answer the following questions. a) What is the setup for your null and alternative hypothesis? b) What is the value of the test statistic? c) What is/are the critical value(s)?
Part Variability is critical in the manufacturing of the ball bearings. Large variances in the size of the ball bearings cause bearing failure and rapid wear out. Production standards call for a maximum variance of .0001 when the bearing sizes are measured in inches. A sample of 15 bearings shows a sample standard deviation of .014. a. Compute the 90% confidence interval estimate of the variance of the ball bearings in the population. b. Use a= 0.10 to determine whether the sample indicates that the maximum acceptable variance is being exceeded. Use critical value approach. ( Note: You must state null and alternative hypotheses, compute the test statistic, Report the critical Value, and draw a conclusion.
pounds, with a standard deviation of 15.81 pounds. At the 0.05 level of significance, test the claim that the weights of football players have a greater variance than the weights of baseball deviation of 40.09 pounds. A random sample of 25 baseball players had a mean weight of 202.9 6. A random sample of 48 football players had a mean weight of 246.6 pounds, with a standard ith a players. ie th sufficient evidence to conclude that Step 5: There
2. A pet association claims that the mean annual costs of food for dogs and cats are the same. The results for samples of the two types of pets are shown in the following table. On wished to test the claim. Assume both populations follow normal distributions Dogs Cats 21 - 16 T1= 239 n2 = 18 Iz= 203 S1 = 32 82 =28 with equal variances. Which of the following formula should be used to calculate the standardized test statistic? (a) Z = (21-32)- Do lu A n2 = (E1-2)-Do (b) Z V n1+2 (c) T (1-2)-Do (21-1)a7+(n2-1)s I1 11+11タ-3 V 1'n2 (d) T = d- Do sp/Vn (e) Z
How do you find (b.)?
IQ scores among the general population have a mean of 100 and a standard deviation of 14. A researcher claims that the standard deviation, o, of IQ scores for females is not equal to 14. A random sample of 24 IQ scores females had a mean of 98 and a standard deviation of 11. Assuming that IQ scores for females are approximately normally distributed, is there significant evidence (at the 0.05 level of significance) to conclude that the researcher's claim is correct? Perform a two-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places and round your answers as specified below. (If necessary, consult a list of formulas.) (a) State the null hypothesis H, and the alternative hypothesis H,. H, :0 H, :0 (b) Determine the type of test statistic to use. (Choose one) ▼ O=0 OSO (c) Find the value of the test statistic. (Round to three or more decimal places.) O

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standard deviations: Sample 1 Sample 2 17 12 n2 X2 X1 5.4 7.9 || S1 = 3.4 S2 4.8 variances, the a. Assuming equal Ho: (µ1 – µz) = 0 against Ha: (1 – Mz) # 0 using conduct test a = .05. b. Find and interpret the 95% confidence interval for (m - uz).