Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.10 significance level. The null and alternative hypothesis would be: Ho: Ho = c Ho: Ho 2 Hc Ho:Po = po Ho: Po S Pc Ho:po 2 Pc Ho: Ho < HC H: 4o + Pc H1:Ho < Hc H1:Po + Pc H1:Po > Pc H1:Po < Pc H1 Ho > Hc The test is: two-tailed right-tailed left-tailed The sample consisted of 45 Orange Coast students, with a sample mean GPA of 2.24 and a standard deviation of 0.02, and 45 Coastline students, with a sample mean GPA of 2.25 and a standard deviation of 0.05. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.10 significance level. The null and alternative hypothesis would be: Ho: Ho = c Ho: Ho 2 Hc Ho:Po = po Ho: Po S Pc Ho:po 2 Pc Ho: Ho < HC H: 4o + Pc H1:Ho < Hc H1:Po + Pc H1:Po > Pc H1:Po < Pc H1 Ho > Hc The test is: two-tailed right-tailed left-tailed The sample consisted of 45 Orange Coast students, with a sample mean GPA of 2.24 and a standard deviation of 0.02, and 45 Coastline students, with a sample mean GPA of 2.25 and a standard deviation of 0.05. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis

Name: Test the claim that the mean GPA of Orange Coast students is smaller
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastlinestudents at the 0.10 significance level.The null and alternative hypothesis would be:= Pc Ho: Ho µc Ho:po = po Ho: po pc Ho: po < HoH1: 4o + Pc

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015

1st Edition

ISBN:9781680331141

Author:HOUGHTON MIFFLIN HARCOURT

Publisher:HOUGHTON MIFFLIN HARCOURT

Chapter4: Writing Linear Equations

Section: Chapter Questions

Problem 14CR

See similar textbooks

Similar questions

I need help figuring this question out.
Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.1 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN=μDH0:μN=μDH1:μN>μDH1:μN>μD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:pN=pDH0:pN=pDH1:pN>pDH1:pN>pD H0:pN=pDH0:pN=pDH1:pN<pDH1:pN<pD H0:μN=μDH0:μN=μDH1:μN<μDH1:μN<μD The test is: two-tailed left-tailed right-tailed The sample consisted of 45 night students, with a sample mean GPA of 2.15 and a standard deviation of 0.06, and 35 day students, with a sample mean GPA of 2.16 and a standard deviation of 0.03.The test statistic is: ________(to 2 decimals)The positive critical value is: ________(to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the .01 significance level. The null and alternative hypothesis would be: Ho: LN = HD Ho: pN = PD Ho:PN = PD Ho: UN = 4D Họ:pN = PD Họ: HN = HD Hị: HN > uD H1: PN # PD H1: PN > PD H1: LN + 4D Hị : pN < PD H1: N < HD The test is: right-tailed left-tailed two-tailed The sample consisted of 25 night students, with a sample mean GPA of 2.87 and a standard deviation of 0.03, and 50 day students, with a sample mean GPA of 2.89 and a standard deviation of 0.04. The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.05 significance level.The null and alternative hypothesis would be: H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:pN=pDH0:pN=pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN>pDH1:pN>pD H0:μN=μDH0:μN=μDH1:μN>μDH1:μN>μD H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN=μDH0:μN=μDH1:μN<μDH1:μN<μD The test is: two-tailed right-tailed left-tailed The sample consisted of 70 night students, with a sample mean GPA of 3.4 and a standard deviation of 0.03, and 55 day students, with a sample mean GPA of 3.43 and a standard deviation of 0.07.The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is larger than the mean GPA of day students at the 0.025 significance level. The null and alternative hypothesis would be: Họ : UN = UD Họ: PN = PD Họ : PN = PD Ho : UN = HD Ho: PN = PD Ho: uN = HD H1 : UN > HD Hị : PN PD H1 : UN + HD H1:PN + PD H1: µN < HD The test is: two-tailed right-tailed left-tailed The sample consisted of 80 night students, with a sample mean GPA of 2.26 and a standard deviation of 0.03, and 80 day students, with a sample mean GPA of 2.23 and a standard deviation of 0.06. The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: Reject the null hypothesis O Fail to reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significance level. The null and alternative hypothesis would be: Ho: µM = HF Ho:pM = PF Ho:µM = µF Ho:PM = PF Ho: µM = µF Ho:PM = PF H: HM PF H1:PM # HF H1:PM µF H1:PM PF The test is: right-tailed two-tailed left-tailed Based on a sample of 20 men, 25% owned cats Based on a sample of 40 women, 45% owned cats The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis > Next Question Ce %23 & 3. 7 16
Which choice would be correct? Extraneous variables that are not directly studied but may influence the DV can be statistically controlled by: a. ANOVA b. ANCOVA c. Friedman's two-way ANOVA d. MANOVA
Test the claim that the proportion of people who own cats is significantly different than 90% at the 0.02 significance level. The null and alternative hypothesis would be: Ho : µ = 0.9 Ho: µ = 0.9 Họ:p= 0.9 Họ:p= 0.9 Họ:p= 0.9 Ho: µ = 0.9 H1: µ > 0.9 H1:u + 0.9 H1:p# 0.9 H1:p 0.9 H1: µ Next Question MacBook Pro @ # % & 2 4 6. 7 8. W R T Y S D G J 但 * 00
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF Incorrect The test is: left-tailed two-tailed right-tailed Incorrect Based on a sample of 20 men, 35% owned catsBased on a sample of 80 women, 40% owned catsThe test statistic is: Incorrect (to 2 decimals)The critical value is: Incorrect (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Incorrect Submit QuestionQuestion 6
A poll was conducted to investigate opinions about global warming. The respondents who answered yes when asked if there is solid evidence that the earth is getting warmer were then asked to select a cause of global warming. The results are given in the accompanying data table. Use a 0.01significance level to test the claim that the sex of the respondent is independent of the choice for the cause of global warming. Do men and women appear to agree, or is there a substantial difference? Human activity Natural patterns Don't know Male 305 151 41 Female 310 170 43 A. Identify the null and alternative hypotheses. H0:(The sex of the respondent/Respondents who answered yes/The choice for human activity) and (the respondents who answered no/the choice for the cause of global warming/the choice for natural patterns) are (dependent/independent) H1:(The sex of the respondent/Respondents who answered yes/The…
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: left-tailed two-tailed right-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 40 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.05 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned catsBased on a sample of 40 women, 60% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis