We plan to test the claim that the mean GPA of night students is more than 2.6 at the a = 0.07 significance level. In this case, the null and alternative hypothesis would be: Ho: µ > 2.6 Ha:µ + 2.6 Но: 2.6 Ha:u + 2.6 Но: д > 2.6 На: и < 2.6 Ho: 4 2.6 Ha:u > 2.6 Ho: µ < 2.6 Ha:µ > 2.6 This test will be | Select an answer A sample of 35 night students had a mean GPA of 2.73 with a standard deviation of 0.35. Based on this data, when we do our hypothesis test the P- value is (round to 4 decimal places). Therefore, we should | Select an answer What is our conclusion regarding the original question?

We plan to test the claim that the mean GPA of night students is more than 2.6 at the a = 0.07 significance level. In this case, the null and alternative hypothesis would be: Ho: µ > 2.6 Ha:µ + 2.6 Но: 2.6 Ha:u + 2.6 Но: д > 2.6 На: и < 2.6 Ho: 4 2.6 Ha:u > 2.6 Ho: µ < 2.6 Ha:µ > 2.6 This test will be | Select an answer A sample of 35 night students had a mean GPA of 2.73 with a standard deviation of 0.35. Based on this data, when we do our hypothesis test the P- value is (round to 4 decimal places). Therefore, we should | Select an answer What is our conclusion regarding the original question?

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Test the claim that the mean GPA of night students is larger than 2 at the .025 significance level.The null and alternative hypothesis would be: H0:p=0.5H1:p<0.5 H0:μ=2H1:μ≠2 H0:p=0.5H1:p≠0.5 H0:μ=2H1:μ>2 H0:μ=2H1:μ<2 H0:p=0.5H1:p>0.5 Based on a sample of 60 people, the sample mean GPA was 2.03 with a standard deviation of 0.06The test statistic is (to 3 decimals)The critical value is (to 3 decimals)Based on this we reject the null hypothesis fail to reject the null hypothesis
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.10 significance level.The null and alternative hypothesis would be: H0:μN=μDH0:μN=μDH1:μN≠μDH1:μN≠μD H0:μN≥μDH0:μN≥μDH1:μN<μDH1:μN<μD H0:pN≥pDH0:pN≥pDH1:pN<pDH1:pN<pD H0:pN=pDH0:pN=pDH1:pN≠pDH1:pN≠pD H0:μN≤μDH0:μN≤μDH1:μN>μDH1:μN>μD H0:pN≤pDH0:pN≤pDH1:pN>pDH1:pN>pD The test is: right-tailed left-tailed two-tailed The sample consisted of 55 night students, with a sample mean GPA of 2.32 and a standard deviation of 0.05, and 55 day students, with a sample mean GPA of 2.37 and a standard deviation of 0.02.The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
also option We should not reject the null hypothesis because t0>tα. So, at the 10% significance level, the data do not provide sufficient evidence to conclude that the average length of time between dentist visits is less than 193days.
Can I use CRONBACH’S ALPHA in testing the reliability of the device? How?
Test the claim that the proportion of people who own cats is smaller than 60% at the 0.005 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 The test is: two-tailed right-tailed left-tailed Based on a sample of 200 people, 51% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
A study is being conducted to compare vitamin C and zinc to determine which is better at fighting colds. Customers believe vitamin C is better at fighting colds. What are the appropriate hypotheses for this testing scenario? Let μc equal the mean of the effectiveness of vitamin C and μz equal the mean of the effectiveness of zinc. O Ho: Hc - Hz= 0 Ha Hc - Hz > 0 O Ho: Hc - Hz= 0 Ha Mc-Hz 0 o Ho: Xe – xz = 0 Hai Xi — Xz #0
My answer is as follows: T critical = 2.70 T value= 7.775 P< a (0.01) Therefore we reject the null. Is this correct?
A test of Ho: H=0 versus H₁: >0 is performed using a significance level of a=0.05. The P-value is 0.07. Part: 0/3 Part 1 of 3 (a) Is Ho rejected? Since P Part: 1/3 Part 2 of 3 Part: 2/3 ▾a, we do not reject Ho at the a= 0.05 level. (b) If the true value of μ is 0, is the result a Type I error, a Type II error, or a correct decision? The result is a correct decision Part 3 of 3 X X S (c) If the true value of His 4, is the result a Type I error, a Type II error, or a correct decision? S Español
To evaluate the effect of a treatment, a sample is obtained from a population with a mean of =40, and the treatment is administered to the individuals in the sample. After treatment, the sample mean is found to be M = 44.5 with a variance of s² = 36. If the sample consists of n = 16 individuals, are the data sufficient to conclude that the treatment has a significant effect using a two-tailed test with a = .05? O For these data, t= 1.50. This value is less than the critical value of 2.131, so we reject the null hypothesis and conclude that there is a significant treatment effect. O For these data, t = 3.00. This value is greater than the critical value of 2.131, so we reject the null hypothesis and conclude that there is a significant treatment effect. O For these data, t = 4.50. This value is greater than the critical value of 2.131, so we reject the null hypothesis and conclude that there is a significant treatment effect. O For these data, t = 1.50. This value is less than the…
For a one-tailed hypothesis test, the critical z value of the test statistic is -2.33. Which of the following is true about the significance level and the rejection region for the hypothesis test? a. α = 0.05 for a left-tailed test b. α = 0.05 for an right-tailed test c. α = 0.01 for a left-tailed test d. α = 0.01 for an right-tailed test
A test of the null hypothesis Ho: p = .25 gives a test statistic z = 1.6. What is the p-value if the alternative is Ha: p > .25? What is the p-value if the alternative is Ha: p < .25? What is the p-value if the alternative is Ha: p .25?
Test the claim that the mean GPA of night students is smaller than 2.7 at the 0.10 significance level.The null and alternative hypothesis would be: H0:μ=2.7H0:μ=2.7H1:μ≠2.7H1:μ≠2.7 H0:p=0.675H0:p=0.675H1:p≠0.675H1:p≠0.675 H0:p≤0.675H0:p≤0.675H1:p>0.675H1:p>0.675 H0:μ≤2.7H0:μ≤2.7H1:μ>2.7H1:μ>2.7 H0:p≥0.675H0:p≥0.675H1:p<0.675H1:p<0.675 H0:μ≥2.7H0:μ≥2.7H1:μ<2.7H1:μ<2.7 The test is: right-tailed two-tailed left-tailed Based on a sample of 40 people, the sample mean GPA was 2.65 with a standard deviation of 0.07The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis