Regulations from the Environmental Protection Agency say that soil used in play areas should not have lead levels that exceed a 400 parts per million (ppm). Before beginning construction at a new site, an agent will take a sample of soil and run a significance test on the mean lead level in the soil. If the mean lead level in the sample is significantly higher than 400 ppm, then the soil is deemed unsafe and construction cannot continue. Here are the hypotheses for this test: Ho : H < 400 ppm (soil is safe)

Regulations from the Environmental Protection Agency say that soil used in play areas should not have lead levels that exceed a 400 parts per million (ppm). Before beginning construction at a new site, an agent will take a sample of soil and run a significance test on the mean lead level in the soil. If the mean lead level in the sample is significantly higher than 400 ppm, then the soil is deemed unsafe and construction cannot continue. Here are the hypotheses for this test: Ho : H < 400 ppm (soil is safe)

Name: AThe soil is actually safe, and the sample result is below 400 ppm, s
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Description: AThe soil is actually safe, and the sample result is below 400 ppm, so construction continues.The soil is actually safe, and the sample result is significantly higher than 400 ppm, so constructionBstops.The soil is actually unsafe, and the sample re

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Because of high production-changeover time and costs, a director of manufacturing must convince management that a proposed manufacturing method reduces costs before the new method can be implemented. The current production method operates with a mean cost of $260 per hour. A research study will measure the cost of the new method over a sample production period. (a) Develop the null and alternative hypotheses most appropriate for this study. H0: ? < 260 Ha: ? ≥ 260 H0: ? > 260 Ha: ? ≤ 260 H0: ? ≤ 260 Ha: ? > 260 H0: ? = 260 Ha: ? ≠ 260 H0: ? ≥ 260 Ha: ? < 260 (b) Comment on the conclusion when H0 cannot be rejected. There is not enough evidence to conclude that the new method reduces costs. Management should consider implementing the new method.There is enough evidence to conclude that the new method reduces costs. Management should not consider implementing the new method. There is enough evidence to conclude that the new method reduces costs. Management…
To determine whether a new sleeping pill has an affect that varies with dosage, a researcher randomly assigns adult insomniacs, in equal numbers, to receive either 4 or 8 grams of the sleeping pill. The amount of sleeping time is measured for each subject during an 8-hour period after the administration of the dosage. What type of design is this, and what type of statistic is needed to analyze the data (consider ABAB studies)?
You may need to use the appropriate appendix table or technology to answer this question. An agency reports that historically 11.3% of workers in a particular country belong to unions. Suppose a sample of 300 workers is collected to determine whether union efforts to organize have increased union membership. (a) Formulate the hypotheses that can be used to determine whether union membership has increased. H0: p ≥ 0.113 Ha: p < 0.113 H0: p = 0.113 Ha: p ≠ 0.113 H0: p ≤ 0.113 Ha: p > 0.113 H0: p < 0.113 Ha: p ≥ 0.113 H0: p > 0.113 Ha: p ≤ 0.113 (b) If the sample results show that 36 of the workers belonged to unions, what is the p-value for your hypothesis test? Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = (c) At α = 0.05, what is your conclusion? Reject H0. There is insufficient evidence to conclude that there has been an increase in union…
1. For this study, we should use a. t-test for a population mean b. z-test for a population proportion 2. The null and alternative hypotheses would be: H0: p or μ a. < b. > c. = d. ≠ H1: p or μ a. < b. > c. = d. ≠ 3. z or t
You may need to use the appropriate appendix table or technology to answer this question. Suppose that the proportion of citizens in a local community who use bus transportation was reported to be 10.2%. Assume that this report was based on a random sample of four hundred citizens. (a) The local mayor wants to know if the sample results can be used to conclude that the proportion of bus riders in the local community is significantly higher than the national average of 7.9%. Develop a hypothesis test that can be used to see if the conclusion that the proportion of bus riders in the local community is higher than the national average can be supported. Ho: p2 0.079 H:p 0.079 Ho:p > 0.079 H:ps 0.079 O Ho: P = 0.079 H:p+ 0.079 (b) Use the sample data collected for the local community to compute the p-value for the hypothesis test in part (a). Using a = 0.05, what is your conclusion? Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round…
2. (Table: TV and Aggressiveness) In a fictional study, a pretest-posttest design was used to examine the influence of a television program on children's aggressiveness. The number of aggressive responses was measured during an observation period both before and after the television program. Calculate the appropriate test statistic to hypothesis test whether or not there is a difference in the number of aggressive behaviors in children after having viewed the television program. Use a = .05 and calculate the test statistic as a two tailed test. Table: TV and Aggressiveness Participant 1 2 3 4 5 6 7 Before 6 4 12 9 10 2 14 After 9 3 11 12 14 6 12
Jennifer, a golfer, has a sample driving distance mean of 244.0 yards from 16 drives. Jennifer still claims that her average driving distance is 225 yards, and the high average can be attributed to chance. At the 2% significance level, does the data provide sufficient evidence to conclude that Jennifer's mean driving distance is greater than 225 yards? Given the sample data below, accept or reject the hypothesis. H0:μ=225 yards; Ha:μ>225 yards α=0.02 (significance level) z0=2.51 p=0.006 Select the correct answer below: Do not reject the null hypothesis because the p-value 0.006 is less than the significance level α=0.02. Reject the null hypothesis because the p-value 0.006 is less than the significance level α=0.02. Reject the null hypothesis because 2.51>0.02. Do not reject the null hypothesis because 2.51>0.02. Reject the null hypothesis because the value of z is positive.
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We’re trying to show that the true average calcium level in humans is greater than 2.4. What are the correct hypotheses? Ho: P≤ 2.4; Ha: P>2.4 Ho: μ≤ 2.4; Ha: μ>2.4 Ho: μ > 2.4; Ha: μ≤2.4 Ho: x≤ 2.4; Ha: x > 2.4
10. A small pilot study is conducted to investigate the effect of a nutritional supplement on total body weight. Six participants agree to take the nutritional supplement. To assess its effect on body weight, weights are measured before starting the supplementation and then after 6 weeks. The data are shown below. Is there a significant increase in body weight following supplementation? Run the test at a 5% level of significance. Demonstrate the five steps for hypothesis testing and explain your results. Subject Initial Weight Weight after 6 Weeks di ff di ff ? 1 155 157 -2 n=6 142 145 - 3 3 176 180 16 4 180 175 25 210 209 1. 6. 125 126 Total 56 2.
Select the correct answer below: Reject H0. At the 1% significance level, the test results are not statistically significant and at best, provide weak evidence against the null hypothesis. Reject H0. At the 1% significance level, the data provide sufficient evidence to conclude that the mean yearly new customers is more than 163 people. Do not reject H0. At the 1% significance level, the test results are not statistically significant and at best, provide weak evidence against the null hypothesis. Do not reject H0. At the 1% significance level, the data provide sufficient evidence to conclude that the mean yearly new customers is more than 163 people.