We’re trying to show that the true average calcium level in humans is greater than 2.4. What are the correct hypotheses?
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Q: Test the claim that the proportion of people who own cats is larger than 10% at the 0.01…
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- Help with 2On a test for the amount of cell phone usage, the alternative hypothesis was mean usage was greater than 100 minutes per week and the null hypothesis was average use was 100 minutes per week. Suppose the p-value for the test was 0.21. What would be your conclusion? a. Average use was greater than 100 minutes b. Average use was less than 100 minutes c. Average use was 100 minutes d. Average use was not 100 minutes e. None of the aboveTest the claim that the proportion of people who own cats is smaller than 90% at the 0.025 significance level.The null and alternative hypothesis would be: H0:μ≥0.9H0:μ≥0.9 H1:μ<0.9H1:μ<0.9 H0:p≥0.9H0:p≥0.9H1:p<0.9H1:p<0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:p≤0.9H0:p≤0.9H1:p>0.9H1:p>0.9 H0:μ≤0.9H0:μ≤0.9H1:μ>0.9H1:μ>0.9 The test is: two-tailed right-tailed left-tailed Based on a sample of 200 people, 85% owned catsThe p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
- Listed below are the lead concentrations in muμg/g measured in different traditional medicines. Use a 0.010.01 significance level to test the claim that the mean lead concentration for all such medicines is less than 1515 muμg/g. Assume that the lead concentrations in traditional medicines are normally distributed. 12 22.5 8 3 9.5 22.5 12.5 13.5 10.5 10.5 What are the null and alternative hypotheses? A. Upper H 0H0: muμequals=1515 muμg/g Upper H 1H1: muμless than<1515 muμg/g Your answer is correct. B. Upper H 0H0: muμequals=1515 muμg/g Upper H 1H1: muμgreater than>1515 muμg/g C. Upper H 0H0: muμgreater than>1515 muμg/g Upper H 1H1: muμless than<1515 muμg/g D. Upper H 0H0: muμequals=1515 muμg/g Upper H 1H1: muμnot equals≠1515 muμg/g Determine the test statistic: ?? (Round to two decimal places as needed.)Use the pulse rates in beats per minute (bpm) of a random sample of adult females listed in the data set available below to test the claim that the mean is less than 74 bpm. Use a 0.01 significance level. E Click the icon to view the pulse rate data. Pulse Rate Data Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? Pulse Rate (bpm) O A. Ho: H= 74 bpm H1: H 74 bpm 57 35 104 86 ОС. Но: и» 74 bpm H1: µ<74 bpm O D. Ho: H=74 bpm H1: µ+74 bpm 97 101 62 49 59 73 Determine the test statistic. 69 45 104 42 |(Round to two decimal places as needed.) 52 105 99 36 Determine the P-value. 74 54 (Round to three decimal places as needed.) 105 60 56 82 State the final conclusion that addresses the original claim. 88 75 52 59 V Ho. There is evidence to conclude that the mean of the population of pulse rates for adult females is V 74 bpm. 82 104 97 76 76 47 97 74 63 52 93 98 104 53 35 35 100 39 Click to select your answer(s). 58 41Test the claim that the mean GPA of night students is smaller than 2.4 at the 0.01 significance level.The null and alternative hypothesis would be: H0:μ=2.4H0:μ=2.4H1:μ≠2.4H1:μ≠2.4 H0:μ≤2.4H0:μ≤2.4H1:μ>2.4H1:μ>2.4 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:μ≥2.4H0:μ≥2.4H1:μ<2.4H1:μ<2.4 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 Correct The test is: right-tailed left-tailed two-tailed Correct Based on a sample of 80 people, the sample mean GPA was 2.37 with a standard deviation of 0.07The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
- Test the claim that the proportion of people who own cats is larger than 70% at the 0.025 significance level.The null and alternative hypothesis would be: H0:μ≥0.7H0:μ≥0.7H1:μ<0.7H1:μ<0.7 H0:p≥0.7H0:p≥0.7H1:p<0.7H1:p<0.7 H0:p≤0.7H0:p≤0.7H1:p>0.7H1:p>0.7 H0:μ≤0.7H0:μ≤0.7H1:μ>0.7H1:μ>0.7 H0:μ=0.7H0:μ=0.7H1:μ≠0.7H1:μ≠0.7 H0:p=0.7H0:p=0.7H1:p≠0.7H1:p≠0.7 The test is: right-tailed left-tailed two-tailed Based on a sample of 600 people, 75% owned catsThe p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis(c) Write a conclusion for this hypothesis test assuming an a= 0.05 level of significance. OA. Reject the null hypothesis. There is not sufficient evidence to conclude that the mean height of women 20 years of age or older is greater today. OB. Reject the null hypothesis. There is sufficient evidence to conclude that the mean height of women 20 years of age or older is greater today. C. Do not reject the null hypothesis. There is not sufficient evidence to conclude that the mean height of women 20 years of age or older is greater today. OD. Do not reject the null hypothesis. There is sufficient evidence to conclude that the mean height of women 20 years of age or older is greater today.Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .05 significance level.The null and alternative hypothesis would be: H0:μM=μFH1:μM<μF H0:pM=pFH1:pM<pF H0:pM=pFH1:pM>pF H0:pM=pFH1:pM≠pF H0:μM=μFH1:μM≠μF H0:μM=μFH1:μM>μF The test is: right-tailed left-tailed two-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 60 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
- Test the claim that the proportion of people who own cats is significantly different than 40% at the 0.05 significance level.The null and alternative hypothesis would be: H0:p≥0.4H0:p≥0.4H1:p<0.4H1:p<0.4 H0:μ≤0.4H0:μ≤0.4H1:μ>0.4H1:μ>0.4 H0:μ≥0.4H0:μ≥0.4H1:μ<0.4H1:μ<0.4 H0:p≤0.4H0:p≤0.4H1:p>0.4H1:p>0.4 H0:p=0.4H0:p=0.4H1:p≠0.4H1:p≠0.4 H0:μ=0.4H0:μ=0.4H1:μ≠0.4H1:μ≠0.4 The test is: two-tailed left-tailed right-tailed Based on a sample of 700 people, 44% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.1 significance level.The null and alternative hypothesis would be: A.) H0:μM=μF H1:μM≠μF B.)H0:μM=μF H1:μM<μF C.)H0:pM=pF H1:pM<pF D.)H0:pM=pF H1:pM≠pF E.)H0:μM=μF H1:μM>μF F.)H0:pM=pF H1:pM>pF The test is: A.) right-tailed B.) left-tailed C.) two-tailed Based on a sample of 40 men, 40% owned catsBased on a sample of 20 women, 55% owned cats The test statistic is:___________ (to 2 decimals)The p-value is: _____________ (to 2 decimals)Based on this we: A.) Reject the null hypothesis B.) Fail to reject the null hypothesishelp!
