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- For a study of two independent samples: Sample 1: mean = 18.1, standard deviation = 2.5, sample size = 30; Sample 2: mean = 19, standard deviation = 2.0; sample size : 54. = a. Calculate t-obtained ONLY (do not interpret). a. How many degrees of freedom are there?Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 18 mu g/g. Assume that the sample is a simple random sample. a. Determine the test statistic. (Round to two decimal places as needed.) b. Determine the P-value. (Round to three decimal places as needed.)3. Suppose that the inside diameter of bulb lamp manufactured by a company are normally distributed with a sample of 200 bulb lamps, µ = 0.502 inches, and o = 0.005 inches. A bulb lamp will be considered defective if its diameter is less than 0.496 inches or greater than 0.508 inches. What is the percentage of defective bulb lamp produced by the company? What did the answer indicate?
- Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the 5-number summary. 1.49 0.79 0.72 1.25 0.85 0.84 1.13 0.68 1.43 0.51 1.18 Question content area bottom Part 1 The 5-number summary is enter your response here, enter your response here, enter your response here, enter your response here, and enter your response here, all in W/kg. (Use ascending order. Type integers or decimals. Do not round.)200 people were randomly sampled and asked what they regularly eat for breakfast or lunch. Each person was identified as either a consumer or a non consumer of high-fiber cereals, and the number of calories consumed at lunch was measured and recorded. These data are summarized below; Consumer of high fiber cereals Non consumer of high fiber cereals η1 =41 η2 = 159 Mean 1 =603 Mean 2 =639 Stanadard deviation 1 = 110 Standard deviation 2 = 141 If the scientist claims that people who eat high fiber cereals for breakfast do consume on average fewer calories for lunch than people who don’t eat high fiber cereals for breakfast, and if it is true, high fiber cereal manufacturer will be able to claim another advantage of eating their products-potential weight reduction for dieter. REQUIRED Are there sufficient evidence at 5% significance level to support the above claim?Six samples of each of four types of cereal grain grown in a certain region were analyzed to determine thiamin content, resulting in the following data (µg/g). Wheat 5.2 4.4 6.1 6.2 6.6 5.8 Barley 6.5 7.9 6.0 7.6 6.0 5.7 Maize 5.8 4.6 6.4 4.9 6.0 5.2 Oats 8.4 6.2 7.8 7.1 5.4 7.2 USE SALT Does this data suggest that at least two of the grains differ with respect to true average thiamin content? Use a level α = 0.05 test. State the appropriate hypotheses. | H₂: M₁ = H₂ = H3 = H4 H₂: all four μ's are unequal • Ho: M₁ = H₂ = H3 = H4 H₂: at least two μ's are unequal ⒸH₂² H₁ H₂ H3 H4 # H: all four μ's are equal O Ho: M₁ #M₂ #H3 H4 H₂: at least two μ's are equal Compute the test statistic value. (Round your answer to two decimal places.) f = What can be said about the P-value for the test? O P-value > 0.100 O 0.050 < P-value < 0.100 O 0.010 < P-value < 0.050 O 0.001 < P-value < 0.010 O P-value < 0.001 State the conclusion in the problem context. O Reject Ho. There is not significant evidence…
- Samples were collected from two ponds in the Bahamas to compare salinity values (in parts per thousand). Several samples were drawn at each site. Pond 1: 37.03, 37.45, 36.75, 37.54, 37.71, 37.02, 37.32 Pond 2: 38.89, 39.05, 38.51, 38.53, 38.71 Use a 2% significance level to test the claim that the two ponds have the same mean salinity value. Assume that nothing is known about the population distribution of salinities. (a) Enter the rank values in the same order as in the original sample. The rank values for Pond 1 are: The rank values for Pond 2 are: (b) The test statistic is: . (c) The test critical value is: . (d) The conclusion isA. There is not sufficient evidence to indicate that the two ponds have different distributions of salinity values.B. There is sufficient evidence to indicate that the two ponds have different distributions of salinity values.The following information is available for two samples selected from independent normally distributed populations. Complete parts (a) and (b). s? = 57.3 s2 = 20.6 Population A: n= 13 Population B: n= 21 a. At the 0.05 level of significance, is there evidence of a difference between of and o3? Determine the hypotheses. Choose the correct answer below. O A. Ho of = 03 O B. Ho, o7 so? O D. Ho; o7 +o3 OC. Họ; o7 203 H,: of o?? What is your statistical decision? The upper-tail critical value of F is (Round to two decimal places as needed.) What is your statistical decision? V Ho. There is V evidence that o? >o3.Answer the following: 1. Test Stat 2. Critical Region: Select one: a. T1.761 c. T>2.14 d. T>abs(2.145) 3. Conclusion: At 5% level of significance… Select one: a. the new type of fabric does not exceed the WRA of the top current brand b. the new type of fabric exceeds the WRA of the top current brand
- a study of store checkout scanners, 1234 items were checked and 23 checked items were overcharges. Use a 0.05 significance level to test the claim that with scanners, 1% of sales are overchanrges. (Before scanners were used, the overcharge rate was estimated to be about 1%). a. Define the parameter A. mu = The proportion of all sales that are undercharges B. p = The proportion of all sales that are incorrect C. p = The proportion of all sales that are overcharges D. mu = The mean number of sales that are overcharges b. State the null and alternative hypotheses A. Upper H 0 : mu not equals 0.01 Upper H 1 : mu equals 0.01 B. Upper H 0 : p greater than 0.01 Upper H 1 : p equals 0.01 C. Upper H 0 : p equals 0.01 Upper H 1 : p not equals 0.01 D. Upper H 0 : p equals 23 Upper H 1 : p less than 23 c. Calculate the sample proportion ModifyingAbove p…Determine the point of estimate of the population mean and margin of error from the given information: Lower Bound: 5 Upper Bound: 23 Question 4 options: x¯= 15 E = 10 x¯= 12 E = 9 x¯= 13.5 E = 9 x¯= 14 E = 9A manufacturing company glues one part to another part during the assembly of its final product. Either too much or too little glue presents a problem. It is important for the pressure of the glue nozzle (pounds per square inch) to be set correctly because it affects the amount of glue (ounces) that is applied. Ten applications are sampled and the following information collected: SSXX = 129.6 SSYY = 2.345 SSXY = 16.6 X bar = 25.2 Y bar = 2.05 What is the estimated y intercept?
