The following details are available with regard to a test of hypothesis for the population mean: H0:μ = 60, σ = 60 x̅ = 72, test statistic = 1.20 what is the sample size?
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The following details are available with regard to a test of hypothesis for the population mean:
H0:μ = 60, σ = 60
x̅ = 72, test statistic = 1.20
what is the
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- Use the following ANOVA table to answer the question. Source Regression Error Total DF MS SS 355.22 177.61 10.91 2 76.38 431.60 7 How many observations were in the data set used to create this model? (i.e. what is n?) 18 15 10 9.Given a 95% C.I. = (34.14 mm, 36.02 mm) for a sample of Wooly Bear caterpillar lengths (preceding problem), address the following. Based upon the above information, I am _____ % confident that the 95% C.I. contains the sample mean.Samples of body temperatures were taken from both men and women. The information from the samples is summarized below. Use a 0.05 significance level to to test the claim that men and women have different mean body temperatures. Men: n₁ = 15; 1 = 98.38° F; s₁ = 0.45°F Women: n2=91; 2 = 98.17°F; $2 = 0.65° F a. On your Work Upload or Calculations page, write down your hypotheses. Label which hypothesis is the claim. b. The test statistic is c. The critical value is . (Round to 3 decimal places.) (Round to 3 decimal places.) d. The p-value is (Round to 3 decimal places.) e. On your Work Upload or Calculations page, show how you made your decision using either the traditional or p-value method. The correct decision is to 1: Reject the null hypothesis, or 2: Fail to reject the null hypothesis. box.) (Type 1 or 2 in the f. On your Work Upload or Calculations page, write your conclusion/results summary. (Use the standard language about evidence and support of claims.)
- The following data was collected during the Framingham Heart Study. Is there a statistically significant difference in mean SBP between men and women using a 5% level of significance? Sample size Mean Standard Deviation Men 1623 128.2 17.5 Women 1911 126.5 20.1This is part A: population mean= 30.23 population standard deviation 13.84 sample size= 25 sample mean 33.17 How likely were we to draw a sample from part A, given the true average weight gain in the population was in fact 30.23?For a study of two independent samples: Sample 1: mean = 18.1, standard deviation = 2.5, sample size = 30; Sample 2: mean = 19, standard deviation = 2.0; sample size : 54. = a. Calculate t-obtained ONLY (do not interpret). a. How many degrees of freedom are there?
- Listed below are the lead concentrations in mu g/g measured in different traditional medicines. Use a 0.05 significance level to test the claim that the mean lead concentration for all such medicines is less than 18 mu g/g. Assume that the sample is a simple random sample. a. Determine the test statistic. (Round to two decimal places as needed.) b. Determine the P-value. (Round to three decimal places as needed.)Below are the SPSS results of a related (dependent) samples t-test. Use the SPSS results to answer Questions 5, 6, and 7. Paired Samples Statistics Mean N Std. Deviation Std. Error Mean Pair 1 Statistics Posttest 57.1250 40 16.73962 2.64677 Statistics Pretest 49.9250 40 15.09014 2.38596 Paired Samples Test Paired Differences t df Sig. (2-tailed) Mean Std. Deviation Std. Error Mean Pair 1 Statistics Posttest - Statistics Pretest 7.200 12.313 ( a ) ( b ) ( c ) .001 Find the mean of the differences ( and standard deviation of the differences (Sd). Replace “a,” “b,” and “c” in the table above with the correct values. Round to the third decimal place. Do you think there is a statistically significant difference between the pretest and posttest at the .05 level of significance?The next five questions refer to the following scenario: • sample mean T = 10 • sample size n = 100 • population standard deviation O = 4
- Kenneth, a competitor in cup stacking, claims that his average stacking time is 8.2 seconds. During a practice session, Kenneth has a sample stacking time mean of 7.8 seconds based on 11 trials. At the 4% significance level, does the data provide sufficient evidence to conclude that Kenneth's mean stacking time is less than 8.2 seconds? Accept or reject the hypothesis given the sample data below. H0:μ=8.2 seconds; Ha:μ<8.2 seconds α=0.04 (significance level) z0=−1.75 p=0.0401 Select the correct answer below: a. Do not reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. b. Reject the null hypothesis because the p-value 0.0401 is greater than the significance level α=0.04. c. Reject the null hypothesis because the value of z is negative. d. Reject the null hypothesis because |−1.75|>0.04. e. Do not reject the null hypothesis because |−1.75|>0.04.Answer the last questionDetermine the point of estimate of the population mean and margin of error from the given information: Lower Bound: 5 Upper Bound: 23 Question 4 options: x¯= 15 E = 10 x¯= 12 E = 9 x¯= 13.5 E = 9 x¯= 14 E = 9
