Test the claim that the mean GPA of night students is larger than 2.4 at the 0.10 significance level.The null and alternative hypotheses would be:Ho:µ = 2.4 Ho :p = 0.6 Ho:p = 0.6 Ho:µ = 2.4 Ho:p= 0.6 Ho:µ= 2.4H1:µ # 2.4 H1:p < 0.6 H:p# 0.6 H1:H < 2.4 H1:p > 0.6 H1:µ > 2.4%3D%3DThe test is:right-tailed two-tailed left-tailedBased on a sample of 32 people, the sample mean GPA was 2.42 with a standard deviation of 0.08The p-value is:(to 3 decimals)The significance level is:(to 2 decimals)Based on this we:O Fail to reject the null hypothesisO Reject the null hypothesisQuestion Help: Message instructorSubmit Question

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Answered: Test the claim that the mean GPA of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the mean GPA of night students is significantly different than the mean GPA of day students at the 0.02 significance level. (a) The null and alternative hypothesis would be: H0:πN=πD H1:πN<πD H0:μN=μD H1:μN<μD H0:μN=μD H1:μN>μD H0:πN=πD H1:πN>πD H0:πN=πD H1:πN≠πD H0:μN=μD H1:μN≠μD (b) The test is: right-tailed left-tailed two-tailed The sample consisted of 45 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 45 day students, with a sample mean GPA of 3.01 and a standard deviation of 0.03. (c) The t-score is: (Round to 2 decimal places.) (d) The p-value is: (Round to 4 decimal places.) (e) Based on this we conclude: null is plausible strong support for the alternative
Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .005 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF The test is: right-tailed left-tailed two-tailed Based on a sample of 80 men, 25% owned catsBased on a sample of 60 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is smaller than 90% at the .05 significance level.The null and alternative hypothesis would be: H0:μ=0.9H0:μ=0.9H1:μ>0.9H1:μ>0.9 H0:p=0.9H0:p=0.9H1:p>0.9H1:p>0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:μ=0.9H0:μ=0.9H1:μ<0.9H1:μ<0.9 H0:p=0.9H0:p=0.9H1:p<0.9H1:p<0.9 The test is: right-tailed two-tailed left-tailed Based on a sample of 65 people, 87% owned catsThe test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis I dont understand this.
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.05 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: right-tailed two-tailed left-tailed Based on a sample of 40 men, 40% owned catsBased on a sample of 40 women, 60% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF The test is: left-tailed two-tailed right-tailed Based on a sample of 20 men, 40% owned catsBased on a sample of 40 women, 55% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 2.1 at the 0.01 significance level. The null and alternative hypotheses would be: 0.525 Ho: u = 2.1 Ho: µ = 2.1 Ho:µ = 2.1 Ho:p 0.525 Ho:p 0.525 H:p> 0.525 H1:p+ 2.1 H:µ > 2.1 H:µ < 2.1 H1:p< 0.525 H :p + 0.525 The test is: left-tailed two-tailed right-tailed Based on a sample of 38 people, the sample mean GPA was 2.11 with a standard deviation of 0.2 The p-value is: (to 3 decimals) The significance level is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: Message instructor Submit Question N D arch
Test the claim that the proportion of people who own cats is smaller than 60% at the 0.005 significance level.The null and alternative hypothesis would be: H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 The test is: two-tailed right-tailed left-tailed Based on a sample of 200 people, 51% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 3.3 at the .10 significance level.The null and alternative hypothesis would be: H0:μ=3.3H0:μ=3.3H1:μ>3.3H1:μ>3.3 H0:p=0.825H0:p=0.825H1:p<0.825H1:p<0.825 H0:p=0.825H0:p=0.825H1:p≠0.825H1:p≠0.825 H0:μ=3.3H0:μ=3.3H1:μ<3.3H1:μ<3.3 H0:μ=3.3H0:μ=3.3H1:μ≠3.3H1:μ≠3.3 H0:p=0.825H0:p=0.825H1:p>0.825H1:p>0.825 The test is: right-tailed two-tailed left-tailed Based on a sample of 80 people, the sample mean GPA was 3.35 with a standard deviation of 0.06The test statistic is:  (to 2 decimals)The critical value is:  (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis Im not understanding this material.
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level.The null and alternative hypothesis would be: H0:μ=0.8H0:μ=0.8H1:μ≠0.8H1:μ≠0.8 H0:p≥0.8H0:p≥0.8H1:p<0.8H1:p<0.8 H0:p≤0.8H0:p≤0.8H1:p>0.8H1:p>0.8 H0:μ≥0.8H0:μ≥0.8H1:μ<0.8H1:μ<0.8 H0:μ≤0.8H0:μ≤0.8H1:μ>0.8H1:μ>0.8 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: two-tailed right-tailed left-tailed Based on a sample of 300 people, 74% owned catsThe test statistic is:  (to 2 decimals)The p-value is:  (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Test the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats at the 0.2 significance level.The null and alternative hypothesis would be: H0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μF H0:pM=pFH0:pM=pFH1:pM<pFH1:pM<pF H0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pF H0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pF H0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μF H0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μF The test is: right-tailed left-tailed two-tailed Based on a sample of 40 men, 25% owned catsBased on a sample of 20 women, 30% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we: Reject the null hypothesis Fail to reject the null hypothesis
You wish to test the following claim (HaHa) at a significance level of α=0.002α=0.002. For the context of this problem, μd=μ2−μ1μd=μ2-μ1 where the first data set represents a pre-test and the second data set represents a post-test. Ho:μd=0Ho:μd=0 Ha:μd≠0Ha:μd≠0You believe the population of difference scores is normally distributed, but you do not know the standard deviation. You obtain pre-test and post-test samples for n=125n=125 subjects. The average difference (post - pre) is ¯d=2.5d¯=2.5 with a standard deviation of the differences of sd=21.3sd=21.3.What is the critical value for this test? (Report answer accurate to three decimal places.)critical value = ±±What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = The test statistic is... in the critical region not in the critical region This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final…
Use a significance level of a=0.05 to test the claim that μ=19. The sample data consists of 15 scores for which x=20.4 and s=4.8. State the null and alternative hypotheses, compute the value of the test statistic, and find the P-value for the sample. State your conclusions about the claim.

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