Table 7-111) Determine the available tension capacity (LRFD) of theconnection with A36 steel plates. Fy 36 ksi, F. = 58 ksi,U=1. Assume the bearing capacity is adequate.Available ShearStrength of Bolts, kipsNominal Bolt Diameter, d, in.Nominal Bolt Area, in.21.2314 in x 1 in. R中Desig-Thread(ksi) | (ksi) Load- TaingASD LRFDnationCond.ASDLRFD(11)S33.266.449.827.040.5GroupD.99.641.862.734.051.0D.83.6 12541.862.734.051.0Group83.6 1259.5 in x 4 in. PS51.777.515542.063.04-1 in. A325 N bolts(Group A) (138 in. hole size)103

according to AISC Steel Manual 13th Ed AISC Steel Manual Table no 1-7 (P 1-42) given, Angle…

Table 7-1 11) Determine the available tension capacity (LRFD) of the connection with A36 steel plates. Fy 36 ksi, F.= 58 ksi, U=1. Assume the bearing capacity is adequate. Available Shear Strength of Bolts, kips Nominal Bolt Diameter, d, in. Nominal Bolt Area, in.2 1.23 14 in x 1 in. R Desig- Thread Cond. (ksi) (ksi) Load- ing ASD LRFO nation ASD LRFD (11) 49.8 33.2 86.4 27.0 40.5 Group 99.6 41.8 62.7 34.0 51.0 83.6 125 41.8 62.7 Group N 34.0 51.0 D. 83.6 125 9.5 in x % in. P 77.5 155 51.7 42.0 63.0 4-1 in. A325 N bolts (Group A) (18 in hole size) 103

Table 7-1 11) Determine the available tension capacity (LRFD) of the connection with A36 steel plates. Fy 36 ksi, F.= 58 ksi, U=1. Assume the bearing capacity is adequate. Available Shear Strength of Bolts, kips Nominal Bolt Diameter, d, in. Nominal Bolt Area, in.2 1.23 14 in x 1 in. R Desig- Thread Cond. (ksi) (ksi) Load- ing ASD LRFO nation ASD LRFD (11) 49.8 33.2 86.4 27.0 40.5 Group 99.6 41.8 62.7 34.0 51.0 83.6 125 41.8 62.7 Group N 34.0 51.0 D. 83.6 125 9.5 in x % in. P 77.5 155 51.7 42.0 63.0 4-1 in. A325 N bolts (Group A) (18 in hole size) 103

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: 0 W12X31 6-120 1.10m 4.20m 3.2n

Q: I need answers to parts 10, 11, and 12, pertaining to the print provided.

A: Hii,thanks for the question but there is only 10th question so we are answeering only 10th…

Q: Two 1/4 in × 8 in A36 steel plates are joined with a lap joint using 3/4 in A325-N bolts. If a…

A: Steel plates of size 14 in × 8 in of A 36 steel Ultimate tensile strength of A 36 steel is…

Q: For a bolted assembly with 8 bolts, the stiffness of each bolt is k_b = 1.1 N/mm and the stiffness…

A: Question is solved below Explanation:To find the maximum safe working load for the bolted assembly,…

Q: Problem 3: A Hexagonal bolt connects two members. The joint has a gap 1 = 2 in and the applied load…

A: Given data: The gap (or) length of the bolt, l = 2 in Applied load, P = 2000 lb 5/16 in 18 UNC-2A…

Q: In using the formula for measuring an American Standard Unified Screw Thread by the three-wire…

A: Here is the solution of your question:-Explanation:In the formula you provided for measuring an…

Q: The bolts used to mount an engine on an industrial machine must each carry a static tensile load of…

A: For the bolt material, SAE grade 5 UNC, the yield strength is generally,

Q: Required information For a bolted assembly with eight bolts, the stiffness of each bolt is kb = 0.8…

A: Kb = 0.8 MN/mm Km = 2.6 MN/mm no.of bolts N = 8 M6 x 1 class 5.8 bolt From the standard bolt data…

Q: For a bolted assembly with eight bolts, the stiffness of each bolt is K,=1.0 MN/mm and the stiffness…

Q: A screw jack having a 2 in double-thread Acme screw is used to raise a load of 6200 lb. A plain…

Q: 1/2-inch thick steel bar is welded to the vertical support A) Calculate the allowable load if the…

A: Given data as per the question h = 3/16 = 4.7625 mm d =4'' = 101.6 mm L =12''=304.8 mm

Q: For a bolted assembly with four bolts, the stiffness of each bolt is kb = 3.0 MN/mm and the…

Q: Q1: Power square thread lift 10 tons, dm= 40 mm, do= 46 mm & u=0.15 . choose the thread angle (2)…

Q: = 3) A double screw (Acme thread angle o 14.5) mechanism is designed to lift a load of 18,000 lb in…

A: Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: Q1:Prepare a full-section assembly drawing of the four fastener assemblies shown in the Figure.…

A: To find:The clearance and the threaded holes.Consider the top view:

Q: For a bolted assembly with six bolts, the stiffness of each bolt is kb = 1.8 Mlbf/in and the…

A: If you have any doubts,do write in comments.

Q: Use LRFD and design a 13-foot-long tension member and its connection for a service dead load of 8…

A: Equilibrium is a state of a body at which there is no disturbance in a system neither inside nor…

Q: ZL.m An M8x1 bolt joins to members of 40 mm total thickness. The bolt and members are made of the…

Q: Part A Determine the smallest diameter of the rod that will support the load ofP = 3.4 kip without…

Concept explainers

Fasteners and Design of Non Permanent Joints

Fasteners are described as mechanical components used to join or assemble two or more pieces of materials. The fasteners are used in various machines or structures based on their suitability to produce non-permanent, semi-permanent, and permanent joints.

Question

Table 7-1
11) Determine the available tension capacity (LRFD) of the
connection with A36 steel plates. Fy 36 ksi, F. = 58 ksi,
U=1. Assume the bearing capacity is adequate.
Available Shear
Strength of Bolts, kips
Nominal Bolt Diameter, d, in.
Nominal Bolt Area, in.2
1.23
14 in x 1 in. R
中
Desig-
Thread
(ksi) | (ksi) Load- Ta
ing
ASD LRFD
nation
Cond.
ASD
LRFD
(11)
S
33.2
66.4
49.8
27.0
40.5
Group
D.
99.6
41.8
62.7
34.0
51.0
D.
83.6 125
41.8
62.7
34.0
51.0
Group
83.6 125
9.5 in x 4 in. P
S
51.7
77.5
155
42.0
63.0
4-1 in. A325 N bolts
(Group A) (138 in. hole size)
103

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Fasteners and Design of Non Permanent Joints

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

A cantilever is to be attached to the flat side of a 6-in wide channel used as a column. The cantilever is to carry a load as shown in the figure. If two fasteners are used, should the array be arranged vertically, horizontally, or diagonally? How would you decide? Specify an optimal bolt pattern and size the bolts. 6 in- 6 in 6 in -in steel plate + 2000 lbf
Caloulate the maimum tensile stress in the bracket shupnt befow. 20mm thiat 400m m ->
- once answered correctly will UPVOTE!!
Need only a handwritten solution only (not a typed one).
Q4/A/Determine the Maximum axial stress for a 36-ft.joint of 7.625-in.OD.6.625in.ID.39 Ib/ft. N-80 casing with API long, round thread couplings if the casing subjected to a 400 00 0 lbf axial tension in a portion of directional wellbore having a doglog severity of 4/100ft.Compute the maximum axiat stress assuming: 1-Uniform contact between the casing and the borehole wall. 2- Contact between the casing and the borehole wall only at the couplings. 3-The joint strength of the API round thread-couplings. Take ult for N-80-100 000 lbf). utmat
Qestion-1: A 9/16 in UNF bolt is subjected to a load P = 60 kip in a tension joint as shown in Figure. The bolt is SAE grade 5 and lubricated. The initial bolt tension (F) = 35 kip. The bolt and joint stiffnesses are k, = 6.5 and km 10.8 Mlbf/in Note: Use the related tables, formulas and concepts to answer following question (a) Formulate to determine the preload and service load stresses in the bolt. (b) Solve to find the torque necessary to develop the preload. (c) Identify if the bolt will fail or no under preload and service load stresses (Calculated in part a) by comparing with the SAE minimum proof strength of the bolt. (d) Can you identify; with given input data, tables and formulas that bolt is self-locking? Table 8-9 SAE Specifications for Steel Bolts Size SAE Range Grade Inclusive, No. in +14 1 2 4 5 5.2 7 8 TI I LI I I I +-14 8.2 -1 Minimum Proof Strength," kpsi 33 55 33 65 85 74 85 105 120 120 Table 8-2 Diameters and Area of Unified Screw Threads Size Designation 0 1 2 3 4…
Pc=nxdxtxo =2x25x20x150 150000 N The strength of the riveted joint= Least of P, Ps , Pc =150 000 N %3D The lap join the edges of There are th %3D 000 050= 02I X 0Z X 001 ='91d=d 0000$ =D0.625 or 62.5 % %3D 0000 a-single tr Homework: 1-A single riveted lap joint is made in 1.5 cm thick plates with 2 cm diameter rivets Determine the strength of the joint, if the pitch of rivets is 6 cm? Take 6,=1200 kg/cm ; o,= 900 kg/cm² ; 6=1600 kg/cm 2-Two plates 16-mm thick are joined by á double riveted lap joint. The pitch of each row of rivets is 9 cm. The rivets are 2.5 cm in diameter. The permissible stresses are as aqnop -4 c-paraller [ans:2827kg] 2. G,=1400 kg/cm ; 6,=1100 kg/cm² ; 6.= 2400 kg/cm 2. Find the efficiency of the joint . 3-A double riveted double cover butt joint is made in 1.2 cm thich plates with 18 mm diameter rivets.find the efficiency of the joint for a pitch of 8 cm. 2. 2. ст Take :6,=1150 kg/cm ; 6, = 800 kg/cm² ; oc=1600 kg/cm 10 mm thick, the allowable stresses are : 6, =…
Please help. Written on paper not typed on computer or keyboard please. Need help on all questions. Please include all units, steps to the problem and information such as its direction or if it is in compression or tension. Thx.
19. The Knuckle Joint is made from SAE 1020 Steel having an allowable tensile strength of 15,000 psi and an allowable shear strength of 7500 psi. The axial load is 1 ton (recall, 1 ton = 2205 lb). Yoke Pin Rod -A The dimensions are as follows: D-0.652 in d-0.652 in c = 0.66 in b = 0.33 in m = 1.306 in e = 0.505 in Determine: a) Tensile stress (psi) at section A-A b) Factor of safety for a) c) Shearing stress (psi) in the pin d) Factor of safety for b) e) Bearing stress (psi) between the pin and the rod f) Factor of safety for e) g) Bearing stress (psi) between the pin and the yoke h) Factor of safety for g) i) Tensile stress (psi) across the hole in the rod j) Factor of safety for i) k) Tensile stress (psi) across the hole in the yoke 1) Factor of safety for k)
Long, square rod in a long cylinder. Also, what is F22? F12 = F21 = || F22 = i w=D/5 A₁ -A₂ t
O b. 2:1 Oc. 1:2 O d. T: 1 QUESTION 10 What is the maximum tensile load P that can be applied to the bolted joint if the bolt diameter is 20 mm and the shear strength of the bolt material is 120 MNm 2 ? Apply a 'safety factor' of 1.2 in your calculations. Note: Please read about 'safety factors' and how they are applied in calculations. O a. 26.4 Nm2 O b. 26.4 kN O c. 62.5 kN O d. 62.5 MNm2 QUESTION 11