For a bolted assembly with four bolts, the stiffness of each bolt iskb = 3.0 MN/mm and the stiffness at the members is km = 4.2MN/mm per bolt. The bolts are pre-loaded to 75% of the proofstrength.Assume the external load is equally distributed to all the bolts.The bolts are M16x1.5 class 8.8 with rolled threads. A fluctuatingexternal load is applied to the entire joint with Pmax = 160 kN andPmin = 80 kN.Determine the factor of safety against fatigue failure using theGoodman criterion.

Answered: Image /qna-images/answer/6baba49f-c6c9-486e-8e33-d1ed1ae4e6e4.jpg

Answered: For a bolted assembly with four bolts,…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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can you please help me please with this question.
A link in a mechanism is to be subjected to a tensile force that varies from 3500 to 500 N in a cyclical fashion as the mechanism runs. It has been decided to use AISI 1040 cold-drawn steel. Complete the design of the link, specifying a suitable cross-sectional shape and dimensions.
A cantilever is to be attached to the flat side of a 6-in wide channel used as a column. The cantilever is to carry a load as shown in the figure. If two fasteners are used, should the array be arranged vertically, horizontally, or diagonally? How would you decide? Specify an optimal bolt pattern and size the bolts. 6 in- 6 in 6 in -in steel plate + 2000 lbf
Q1 A single-square thread power screw is to raise a load of 100KN. The screw has a major diameter of 42 mm and a pitch of 6 mm. The nut for the screw transfers the load as shown in the F/2 F/2 figure right. The power screw is made of carbon steel having Sy=350MPA and Sut= 500MPa. The nut is to be made of ASTM 25 gray cast iron having S,=220MPA and Suc=670MPA. The friction on the screw threads is 0.15 and the friction on the nut is ignored. Calculate; i) ii) iii) iv) Raising and lowering torques Efficiency for raising the load Check for the self-locking condition Nut height (h) when considering the failures due to direct shear at the root of the thread and bearing stress failure on nut. Take the factor of safety as 3. Critical load when the power screw is at maximum height of 850mm. v)
Need only a handwritten solution only (not a typed one).
Qestion-1: A 9/16 in UNF bolt is subjected to a load P = 60 kip in a tension joint as shown in Figure. The bolt is SAE grade 5 and lubricated. The initial bolt tension (F) = 35 kip. The bolt and joint stiffnesses are k, = 6.5 and km 10.8 Mlbf/in Note: Use the related tables, formulas and concepts to answer following question (a) Formulate to determine the preload and service load stresses in the bolt. (b) Solve to find the torque necessary to develop the preload. (c) Identify if the bolt will fail or no under preload and service load stresses (Calculated in part a) by comparing with the SAE minimum proof strength of the bolt. (d) Can you identify; with given input data, tables and formulas that bolt is self-locking? Table 8-9 SAE Specifications for Steel Bolts Size SAE Range Grade Inclusive, No. in +14 1 2 4 5 5.2 7 8 TI I LI I I I +-14 8.2 -1 Minimum Proof Strength," kpsi 33 55 33 65 85 74 85 105 120 120 Table 8-2 Diameters and Area of Unified Screw Threads Size Designation 0 1 2 3 4…
Required information A solid square rod is cantilevered at one end. The rod is 0.6 m long and supports a completely reversing transverse load at the other end of ±1.7 kN. The material is AISI 1080 hot-rolled steel. If the rod must support this load for 5 x 104 cycles with a design factor of 1.5, what dimension should the square cross section have? Neglect any stress concentrations at the support end. Determine the endurance limit for this application. Assume that the size modification factor kis 0.85 until a size for the section is known. The endurance limit is 278.4 MPa.
A rectangular bar is cut from an AISI 1020 cold-drawn steel flat. The bar is 2.500 in wide by 4/8 in thick and has a 0.500-in-dia. hole drilled through the center as depicted in Table A-15-1. The bar is concentrically loaded in push-pull fatigue by axial forces Fa, uniformly distributed across the width. Using a design factor of na = 2, estimate the largest force Fa that can be applied ignoring column action. What is the largest force that can be applied to the part? (Round the final answer to three decimal places.) The largest force that can be applied is kips.
! Required information A rectangular bar is cut from an AISI 1020 cold-drawn steel flat. The bar is 2.500 in wide by 4/8 in thick and has a 0.500-in-dia. hole drilled through the center as depicted in Table A-15-1. The bar is concentrically loaded in push-pull fatigue by axial forces Fa, uniformly distributed across the width. Using a design factor of na = 2, estimate the largest force Fã that can be applied ignoring column action. Determine the endurance limit for this material as well as the value after correction for surface finish, sizing, and loading. The endurance limit for the material is kpsi. The endurance limit after correction is kpsi.
A rectangular bar is cut from an AISI 1020 cold-drawn steel flat. The bar is 2.500 in wide by 4/8 in thick and has a 0.500-in-dia. hole drilled through the center as depicted in Table A-15–1. The bar is concentrically loaded in push-pull fatigue by axial forces Fa, uniformly distributed across the width. Using a design factor of na = 2, estimate the largest force Fa that can be applied ignoring column action. What are the values of the theoretical stress-concentration factor, the notch sensitivity, and the fatigue stress-concentration factor? The value of the theoretical stress-concentration factor is The value of the notch sensitivity is (Round the final answer to three decimal places.) The value of the fatigue stress-concentration factor is (Round the final answer to three decimal places.)
I keep getting this one wrong. For T1, I did 370/cos(30) = 427.24 lb tension , and -427.24 x cos(30)= -370. I also tried T1=820, and T2=-710.14, which was not correct as well. Thank you for your help on these two parts
Pravinbhai

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