Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00 Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00
Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00 Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter11: Properties Of Solutions
Section: Chapter Questions
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Question
Absorbance values: 0, 0.078, 0.235, 0.660, 0.823, and 1.005.
y = mx +b which is "y= 5489.3x- 0.0821"
• Y = absorbance, m = slope, x = concentration, b = y-intercept
1. Determine the unknown concentration of your mixtures from your measured absorbances
• Solve the best fit line equation for x for each equilibrium mixture (E1-E6)
3. Set up ICE tables for each E mixture to find [Fe3+] and [SCN-] at
equilibrium for each
• Use the given amounts and concentrations from Table 2 for your initial [Fe3+] and [SCN-]
• Use your equilibrium concentrations from the previous step for your [FeSCN2+]eq
4. Calculate Kf
• Use your calculations of [Fe3+], [SCN-] and [FeSCN2+] to find Kf:
• kf = [FeSCN2+][Fe3+][SCN−]
• Y = absorbance, m = slope, x = concentration, b = y-intercept
1. Determine the unknown concentration of your mixtures from your measured absorbances
• Solve the best fit line equation for x for each equilibrium mixture (E1-E6)
3. Set up ICE tables for each E mixture to find [Fe3+] and [SCN-] at
equilibrium for each
• Use the given amounts and concentrations from Table 2 for your initial [Fe3+] and [SCN-]
• Use your equilibrium concentrations from the previous step for your [FeSCN2+]eq
4. Calculate Kf
• Use your calculations of [Fe3+], [SCN-] and [FeSCN2+] to find Kf:
• kf = [FeSCN2+][Fe3+][SCN−]
Transcribed Image Text:Initial
Change
Equilibrium
Solution
Concentration
Absorbance
Fe3+
SCN-
FeSCN²+
0.00
![Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot
Solution
[Fe3+]
[SCN]
S1 (blank)
4.0 x 10-2 M
0.0 M
S2
4.0 x 10-2 M
4.0 x 10-5 M
S3
4.0 x 10-2 M
8.0 x 10-5 M
S4
4.0 x 10-2 M
12.0 x 10-5 M
S5
4.0 x 10-2 M
16.0 x 10-5 M
S6
4.0 x 10-2 M
20.0 x 10-5 M
Solution
Volume in mL of
0.00200 M Fe(NO3)3
Table 2: Volumes for Unknown Equilibrium Solutions
Volume in mL of
0.10 M HNO3
Volume in mL of
0.00200 M NaSCN
E1 (blank)
5.00
0.00
5.00
E2
5.00
1.00
4.00
E3
5.00
2.00
3.00
E4
5.00
3.00
2.00
E5
5.00
4.00
1.00
E6
5.00
5.00
0.00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3cff6d5e-6d7b-4ef6-9838-a544f8e2903b%2F65665074-c117-425a-93c3-ec81470b90e3%2Fdynniq9_processed.png&w=3840&q=75)
Transcribed Image Text:Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot
Solution
[Fe3+]
[SCN]
S1 (blank)
4.0 x 10-2 M
0.0 M
S2
4.0 x 10-2 M
4.0 x 10-5 M
S3
4.0 x 10-2 M
8.0 x 10-5 M
S4
4.0 x 10-2 M
12.0 x 10-5 M
S5
4.0 x 10-2 M
16.0 x 10-5 M
S6
4.0 x 10-2 M
20.0 x 10-5 M
Solution
Volume in mL of
0.00200 M Fe(NO3)3
Table 2: Volumes for Unknown Equilibrium Solutions
Volume in mL of
0.10 M HNO3
Volume in mL of
0.00200 M NaSCN
E1 (blank)
5.00
0.00
5.00
E2
5.00
1.00
4.00
E3
5.00
2.00
3.00
E4
5.00
3.00
2.00
E5
5.00
4.00
1.00
E6
5.00
5.00
0.00
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