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Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00 Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00

Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00 Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00

Principles of Modern Chemistry
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 94AP
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Absorbance values: 0, 0.078, 0.235, 0.660, 0.823, and 1.005.
y = mx +b which is "y= 5489.3x- 0.0821"
• Y = absorbance, m = slope, x = concentration, b = y-intercept
1. Determine the unknown concentration of your mixtures from your measured absorbances
• Solve the best fit line equation for x for each equilibrium mixture (E1-E6)
3. Set up ICE tables for each E mixture to find [Fe3+] and [SCN-] at
equilibrium for each
• Use the given amounts and concentrations from Table 2 for your initial [Fe3+] and [SCN-]
• Use your equilibrium concentrations from the previous step for your [FeSCN2+]eq
4. Calculate Kf
• Use your calculations of [Fe3+], [SCN-] and [FeSCN2+] to find Kf:
• kf = [FeSCN2+][Fe3+][SCN−]
Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00
Transcribed Image Text:Initial Change Equilibrium Solution Concentration Absorbance Fe3+ SCN- FeSCN²+ 0.00
Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00
Transcribed Image Text:Table 1: Standard Solutions for FeSCN2+ Beer's Law Plot Solution [Fe3+] [SCN] S1 (blank) 4.0 x 10-2 M 0.0 M S2 4.0 x 10-2 M 4.0 x 10-5 M S3 4.0 x 10-2 M 8.0 x 10-5 M S4 4.0 x 10-2 M 12.0 x 10-5 M S5 4.0 x 10-2 M 16.0 x 10-5 M S6 4.0 x 10-2 M 20.0 x 10-5 M Solution Volume in mL of 0.00200 M Fe(NO3)3 Table 2: Volumes for Unknown Equilibrium Solutions Volume in mL of 0.10 M HNO3 Volume in mL of 0.00200 M NaSCN E1 (blank) 5.00 0.00 5.00 E2 5.00 1.00 4.00 E3 5.00 2.00 3.00 E4 5.00 3.00 2.00 E5 5.00 4.00 1.00 E6 5.00 5.00 0.00
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