Synthesis of lodosalicylamide - An Electrophilic Aromatic Substitution Introduction Benzene can undergo certain types of reactions known as electrophilic aromatic substitutions (EAS). As the name implies, some atom or small molecule substitutes onto the benzene ring in place of a hydrogen atom. In today's experiment, we will be using a derivative of benzene, salicylamide, and substituting an iodine atom onto the ring. In all EAS reactions, the ring is the nucleophile while the atom/molecule that is being substituted onto the ring must have electrophilic character. Groups already present on the ring can either activate or deactivate the ring. Another way to think about this is that activating groups can speed up the rate of reaction while deactivating groups slow down the reaction. Activating groups will donate electron density into the ring an will specifically activate it's ortho and para positions. This is why we classify them as ortho, par directors. Deactivating groups will withdraw electron density from the ring. This electron withdrawing effect deactivates the ortho para positions towards nucleophilic attack, which in turn directs the substitution to its meta position. This is why deactivating groups are meta directors. The only exception to this statement is the halogens. The halogens do deactivate th ring, but they also can donate an electron pair into the ring via resonance. Therefore, halogem will be ortho para directing but deactivate the ring. Your organic lecture textbook and your instructor will have discussed this in further detail in lecture. More resources regarding these types of reactions can be found under this week's resources on Brightspace. The overall reaction is shown below. The line going through the benzene ring connected to iodine is a type of shorthand that can be used when you're unsure of the exact location of th substituent on the ring. As far as the exact location of the substitution, you'll need to predict based on your knowledge of the types of activating/deactivating groups already substituted salicylamide. NH₂ S OH 1.) Nal, NaOCI, CH₂CH₂OH 2.) Na2S₂O3, HCI NH₂ OH As a quick reference, the mechanism for the electrophilic aromatic substitution is shown bell The electrophile, It, is generated from 12. The nucleophile, the pi electrons of the ring, attack and loses aromaticity, forming a sigma complex. This sigma complex is a resonance stabilize carbocation intermediate. The ring will then regain aromaticity once it is deprotonated by a base.
Carbohydrates
Carbohydrates are the organic compounds that are obtained in foods and living matters in the shape of sugars, cellulose, and starch. The general formula of carbohydrates is Cn(H2O)2. The ratio of H and O present in carbohydrates is identical to water.
Starch
Starch is a polysaccharide carbohydrate that belongs to the category of polysaccharide carbohydrates.
Mutarotation
The rotation of a particular structure of the chiral compound because of the epimerization is called mutarotation. It is the repercussion of the ring chain tautomerism. In terms of glucose, this can be defined as the modification in the equilibrium of the α- and β- glucose anomers upon its dissolution in the solvent water. This process is usually seen in the chemistry of carbohydrates.
L Sugar
A chemical compound that is represented with a molecular formula C6H12O6 is called L-(-) sugar. At the carbon’s 5th position, the hydroxyl group is placed to the compound’s left and therefore the sugar is represented as L(-)-sugar. It is capable of rotating the polarized light’s plane in the direction anticlockwise. L isomers are one of the 2 isomers formed by the configurational stereochemistry of the carbohydrates.
please answer this question, i think my calculations are coming out wrong-
Calculate the theoretical yield and percent yield using the RESULT/DATA below:
Mass of salicylamide: 0.503g
Mass of sodium iodide: 0. 606 g
Mass of Recrystallized dry Product: 0.170g
![pola na bimsi
0²68-$-51-0
sigma complex
During this reaction, a series of three redox reactions will take place. Color changes of the
reaction mixture will be observed as the different redox reactions take place. In the first redox
reaction, the iodide ion (from Nal) reacts with hypochlorite in the presence of three protons to
form iodine (12). 12 is the source of It, the electrophile in the EAS reaction. Some of the iodide ion
is left behind and will combine with 12 which forms 13¹. The thiosulfate ion is then added to
reduce 13¹ to water soluble 1¹ which stops the reaction.
(1) CIO3¹+ 41¹
(2)
(3)
715-770 (strong)
Redox Reactions:
+ 3 H
13¹ + 2S₂O32- → 31¹-
HCI + H₂O + 2 12₂ (red)
12 + 1²¹13¹ (yellow/green)
+ O3S-S-S-SO3
Our reactant and product this week can be analyzed by investigating the fingerprint region of
the IR. Substitution pattern on aromatic rings can be found in the region between 700 and 900
cm¹ depending on how the groups are arranged. You should be able to determine the
substitution pattern of your product easily by examining this region. The vibration arises from
the C-H bend from the aromatic ring called the "C-H oop." The different substitution patterns
and their corresponding expected peaks are listed below.
750-790 (strong)
Base
730-770 (strong)
760-820 (strong)
400
800-850 (strong)
830-910 (strong)
800-870 (strong)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa19fa31b-c6a1-4dda-95dc-44f8d9193b80%2Fa3f6e16b-1ca6-4eb0-b73b-c02622f39d6f%2Fkwxm1w_processed.jpeg&w=3840&q=75)
![Synthesis of lodosalicylamide - An Electrophilic Aromatic
Substitution
Introduction
Benzene can undergo certain types of reactions known as electrophilic aromatic substitutions
(EAS). As the name implies, some atom or small molecule substitutes onto the benzene ring in
place of a hydrogen atom. In today's experiment, we will be using a derivative of benzene,
salicylamide, and substituting an iodine atom onto the ring. In all EAS reactions, the ring is the
nucleophile while the atom/molecule that is being substituted onto the ring must have
electrophilic character.
Groups already present on the ring can either activate or deactivate the ring. Another way to
think about this is that activating groups can speed up the rate of reaction while deactivating
groups slow down the reaction. Activating groups will donate electron density into the ring and
will specifically activate it's ortho and para positions. This is why we classify them as ortho, para
directors. Deactivating groups will withdraw electron density from the ring. This electron
withdrawing effect deactivates the ortho para positions towards nucleophilic attack, which in
turn directs the substitution to its meta position. This is why deactivating groups are meta
directors. The only exception to this statement is the halogens. The halogens do deactivate the
ring, but they also can donate an electron pair into the ring via resonance. Therefore, halogens
will be ortho para directing but deactivate the ring. Your organic lecture textbook and your
instructor will have discussed this in further detail in lecture. More resources regarding these
types of reactions can be found under this week's resources on Brightspace.
The overall reaction is shown below. The line going through the benzene ring connected to
iodine is a type of shorthand that can be used when you're unsure of the exact location of the
substituent on the ring. As far as the exact location of the substitution, you'll need to predict
based on your knowledge of the types of activating/deactivating groups already substituted on
salicylamide.
NH₂
OH
1.) Nal, NaOCI, CH₂CH₂OH
2.) Na₂S₂O3, HCI
NH₂
OH
As a quick reference, the mechanism for the electrophilic aromatic substitution is shown below.
The electrophile, It, is generated from 12. The nucleophile, the pi electrons of the ring, attacks I*
and loses aromaticity, forming a sigma complex. This sigma complex is a resonance stabilized
carbocation intermediate. The ring will then regain aromaticity once it is deprotonated by a
base.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa19fa31b-c6a1-4dda-95dc-44f8d9193b80%2Fa3f6e16b-1ca6-4eb0-b73b-c02622f39d6f%2Fvouespi_processed.jpeg&w=3840&q=75)
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