Treatment of Data   Mole amount of Na2Cl3 - Moles Na2CO3 =  Mole amount of CaCl2- Moles of CaCl2 =  limiting reagent-  mole amount CaCO3-  theoretical yield CaCO3 =   Experimental yield =  20. Percentage yield =

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Treatment of Data

 

  1. Mole amount of Na2Cl3 - Moles Na2CO3 = 
  2. Mole amount of CaCl2- Moles of CaCl2 = 
  3. limiting reagent- 
  4. mole amount CaCO3- 
  5. theoretical yield CaCO3 =  
  6. Experimental yield = 
  7. 20. Percentage yield = 

 

Calculations (Show work here)

  1. Number of moles of Na2CO3 used

 

  1. The number of moles of CaCl2 used

 

  1. Identify the limiting reagent in this experiment based on calculation in questions 15 and 16

No. Of moles of CaCl2 is less, it is our limiting regent

17) Calculate the theoretical yield of CaCO3 in moles

 

20) Calculate the percent yield.

 

 

Clipboard
Font
Alignment
Number
G20
fr
A
C
D
E
F
H
K
1 1
Volume of Na2CO3, mL
15.78
2 2 Molarity of Na2CO3, mol/L
1.13
3
4 4
Volume of CaCl2, mL
10.90
5 5 Molarity of CaCl2, mol/L
1.27
6.
7
8 8
Mass of the filter paper, g
1.00
9 9
Mass of the watch glass, g
2.17
10 10 Mass of the filter paper + watch glass + wet product, g
11.38
11 11 Mass of the filter paper + watch glass + dry product, g
8.88
12
12
Transcribed Image Text:Clipboard Font Alignment Number G20 fr A C D E F H K 1 1 Volume of Na2CO3, mL 15.78 2 2 Molarity of Na2CO3, mol/L 1.13 3 4 4 Volume of CaCl2, mL 10.90 5 5 Molarity of CaCl2, mol/L 1.27 6. 7 8 8 Mass of the filter paper, g 1.00 9 9 Mass of the watch glass, g 2.17 10 10 Mass of the filter paper + watch glass + wet product, g 11.38 11 11 Mass of the filter paper + watch glass + dry product, g 8.88 12 12
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