Suppose two threads with a shared variable "lockywocky" execute the following instructions: shared int lockywocky; Thread 1: lockywocky = 0 lockywocky lockywocky + 1 lockywocky lockywocky - 1 cout << lockywocky + 1 << endl; = Thread 2: lockywocky = 0 lockywocky lockywocky - 1 lockywocky lockywocky + 1 cout << lockywocky + 1 << endl; = = It may seem like this code can only bring the number "1". Demonstrate that a race condition can cause it to instead print "2" by number each instruction to form a sequence that triggers the bug. You do not need to continue numbering instructions once your code has reached the cout that prints '2'.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Suppose two threads with a shared variable "lockywocky" execute the following
instructions:
shared int lockywocky;
Thread 1:
lockywocky = 0
lockywocky = lockywocky + 1
lockywocky = lockywocky - 1
cout << lockywocky + 1 << endl;
Thread 2:
lockywocky = 0
lockywocky = lockywocky - 1
lockywocky = lockywocky + 1
cout << lockywocky + 1 << endl;
It may seem like this code can only bring the number "1". Demonstrate that a race condition can cause
it to instead print "2" by number each instruction to form a sequence that triggers the bug. You do not
need to continue numbering instructions once your code has reached the cout that prints '2'.
Transcribed Image Text:Suppose two threads with a shared variable "lockywocky" execute the following instructions: shared int lockywocky; Thread 1: lockywocky = 0 lockywocky = lockywocky + 1 lockywocky = lockywocky - 1 cout << lockywocky + 1 << endl; Thread 2: lockywocky = 0 lockywocky = lockywocky - 1 lockywocky = lockywocky + 1 cout << lockywocky + 1 << endl; It may seem like this code can only bring the number "1". Demonstrate that a race condition can cause it to instead print "2" by number each instruction to form a sequence that triggers the bug. You do not need to continue numbering instructions once your code has reached the cout that prints '2'.
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