In the following program, the main thread creates four peer threads and passes a pointer to the loop variable to each one. Each peer thread prints a message containing the loop variable. 1 #include 2 #include 3 4 void *foo (void *arg) { 5 int *myid = (int *) arg; 6 printf ("Hello from thread %d\n", *myid); 7 return NULL; 8} 9 10 int main() { 11 12 13 14 15 16 17 18 19 20 21 } pthread_t tid [4]; int i; for(i=0; i<4; i++) pthread_create(&tid[i], NULL, foo, &i); for(i=0; i<4; i++) pthread_join(tid[i], NULL); return 0; We might expect that the program will print all the four values of i, but when the program is executed, we see the following incorrect result containing repetitions: Hello from thread 1 Hello from thread 3 Hello from thread 3 Hello from thread 3 What causes this behavior? Explain your answer. ) [Continuation of Question 2b above] Rectify only the main() function such that the concurrent peer threads print unique values, i.e., the first thread prints 0, the second thread prints 1, the third thread prints 2 and the final thread prints 3. We don't expect the threads will print "in order" (we expect that they just print the correct value per thread). Explain your answer.

In the following program, the main thread creates four peer threads and passes a pointer to the loop variable to each one. Each peer thread prints a message containing the loop variable. 1 #include 2 #include 3 4 void foo (void arg) { 5 int myid = (int ) arg; 6 printf ("Hello from thread %d\n", *myid); 7 return NULL; 8} 9 10 int main() { 11 12 13 14 15 16 17 18 19 20 21 } pthread_t tid [4]; int i; for(i=0; i<4; i++) pthread_create(&tid[i], NULL, foo, &i); for(i=0; i<4; i++) pthread_join(tid[i], NULL); return 0; We might expect that the program will print all the four values of i, but when the program is executed, we see the following incorrect result containing repetitions: Hello from thread 1 Hello from thread 3 Hello from thread 3 Hello from thread 3 What causes this behavior? Explain your answer. ) [Continuation of Question 2b above] Rectify only the main() function such that the concurrent peer threads print unique values, i.e., the first thread prints 0, the second thread prints 1, the third thread prints 2 and the final thread prints 3. We don't expect the threads will print "in order" (we expect that they just print the correct value per thread). Explain your answer.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

) In the following program, the main thread creates four peer threads and passes
a pointer to the loop variable to each one. Each peer thread prints a message
containing the loop variable.
1 #include<stdio.h>
2 #include<pthread.h>
3
4 void *foo (void *arg) {
5 int *myid = (int *) arg;
6
printf ("Hello from thread %d\n", *myid);
7
return NULL;
8}
9
10 int main() {
11
12
13
14
15
16
17
18
19
20 return 0;
21 }
pthread_t tid [4];
int i;
for(i=0; i<4; i++)
pthread_create(&tid[i], NULL, foo, &i);
for(i=0; i<4; i++)
pthread_join(tid[i], NULL);
We might expect that the program will print all the four values of i, but when the
program is executed, we see the following incorrect result containing repetitions:
Hello from thread 1
Hello from thread 3
Hello from thread 3
Hello from thread 3
What causes this behavior? Explain your answer.
) [Continuation of Question 2b above] Rectify only the main() function such
that the concurrent peer threads print unique values, i.e., the first thread prints 0,
the second thread prints 1, the third thread prints 2 and the final thread prints 3.
We don't expect the threads will print "in order" (we expect that they just print the
correct value per thread). Explain your answer.

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