Suppose the formation of nitryl fluoride proceeds by the following mechanism: step elementary reaction rate constant 1 NO2(9) + F2(9) NO,F(9) + F(g) → 2 F(g) + NO,(9) → NO,F(g) k2 Suppose also k,»k,. That is, the first step is much faster than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k U Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k.1 and k.2 for the reverse of the two k = elementary reactions in the mechanism.

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Suppose the formation of nitryl fluoride proceeds by the following mechanism:
step
elementary reaction
rate constant
1
NO2(g) + F,(9) → NO,F(g) + F(g)
k1
2
F(g) + NO2(9)
→ NO,F(g)
Suppose also k,»k,. That is, the first step is much faster than the second.
Write the balanced
chemical equation for the
overall chemical reaction:
Write the experimentally-
observable rate law for the
overall chemical reaction.
rate = k U
%3D
Note: your answer should
not contain the
concentrations of any
intermediates.
Express the rate constant
k for the overall chemical
reaction in terms of k1, k2,
and (if necessary) the rate
constants k1 and k-2 for
k =
the reverse of the two
elementary reactions in
the mechanism.
Transcribed Image Text:Suppose the formation of nitryl fluoride proceeds by the following mechanism: step elementary reaction rate constant 1 NO2(g) + F,(9) → NO,F(g) + F(g) k1 2 F(g) + NO2(9) → NO,F(g) Suppose also k,»k,. That is, the first step is much faster than the second. Write the balanced chemical equation for the overall chemical reaction: Write the experimentally- observable rate law for the overall chemical reaction. rate = k U %3D Note: your answer should not contain the concentrations of any intermediates. Express the rate constant k for the overall chemical reaction in terms of k1, k2, and (if necessary) the rate constants k1 and k-2 for k = the reverse of the two elementary reactions in the mechanism.
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