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- At 500 K in the presence of a copper surface, ethanol decom- poses according to the equation C,H,OH(g) –→ CH,CHO(g) + H,(g) The pressure of C2H5OH was measured as a function of time and the following data were obtained: Time (s) PCH,OH (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the con- centration of gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the above data, deduce the rate law, the integrated rate law, and the value of the rate constant, all in terms of pressure units in atm and time in seconds. Predict the pressure of C,H;OH after 900. s from the start of the reaction. (Hint: To determine the order of the reaction with respect to C2H5OH, compare how the pressure of C2H5OH decreases with each time listing.)

- At 500 K in the presence of a copper surface, ethanol decom- poses according to the equation C,H,OH(g) –→ CH,CHO(g) + H,(g) The pressure of C2H5OH was measured as a function of time and the following data were obtained: Time (s) PCH,OH (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the con- centration of gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the above data, deduce the rate law, the integrated rate law, and the value of the rate constant, all in terms of pressure units in atm and time in seconds. Predict the pressure of C,H;OH after 900. s from the start of the reaction. (Hint: To determine the order of the reaction with respect to C2H5OH, compare how the pressure of C2H5OH decreases with each time listing.)

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter12: Kinetics
Section: Chapter Questions
Problem 50E: For the past 10 years, the unsaturated hydrocarbon 1, 3-butadiene (CH2 = CH - CH = CH2) has ranked...
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596 Chapter 12 Chemical Kinetics 42. At 500 K in the presence of a copper surface, ethanol decom- poses according to the equation C,H¿OH(g) → CH;CHO(g) + H2(g) The pressure of C2H5OH was measured as a function of time and the following data were obtained: Time (s) Рснон (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the con- centration of gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the above data, deduce the rate law, the integrated rate law, and the value of the rate constant, all in terms of pressure units in atm and time in seconds. Predict the pressure of C2H5OH after 900. s from the start of the reaction. (Hint: To determine the order of the reaction with respect to C2H5OH, compare how the pressure of C,H5OH decreases with each time listing.)
Transcribed Image Text:596 Chapter 12 Chemical Kinetics 42. At 500 K in the presence of a copper surface, ethanol decom- poses according to the equation C,H¿OH(g) → CH;CHO(g) + H2(g) The pressure of C2H5OH was measured as a function of time and the following data were obtained: Time (s) Рснон (torr) 250. 100. 237 200. 224 300. 211 400. 198 500. 185 Since the pressure of a gas is directly proportional to the con- centration of gas, we can express the rate law for a gaseous reaction in terms of partial pressures. Using the above data, deduce the rate law, the integrated rate law, and the value of the rate constant, all in terms of pressure units in atm and time in seconds. Predict the pressure of C2H5OH after 900. s from the start of the reaction. (Hint: To determine the order of the reaction with respect to C2H5OH, compare how the pressure of C,H5OH decreases with each time listing.)
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