Sucrose (C12H₂O11), which is commonly known as table sugar, reacts in dilute acid solutions to form two simpler sugars, glucose and fructose, both of which have the formula C₂H2Os At 23 °C and in 0.5 M HCL the following data were obtained for the disappearance of sucrose Time (min) CH₂O₁ (M) 10 39 80 140 210 0.316 0.274 0.238 0.100 0.148 ▾ Part B What is the rate constant? Express your answers using three significant figures. 3.67×10 min-1 Previous Answere ✔Correct The first-order rate constant (k) is equal to the negative of the slope produced by plotting the natural log of the concentration over time. In order to find the slope of the plot, the natural log of each concentration must first be calculated. Part C (sucroses = These natural log values can then be used to plot a trend line, which will have a slope of -3.67 x 10³ Since it is the negative of the slope, the value of & will be 3.67 x 10³ min¹ AZO Part D Using the rate constant found in Part B, calculate the concentration of sucrose at 30 min if the initial sucrose concentration were 0.318 M and the reaction were zero order in sucrose Express your answers using two significant figures. VA → C13 ? Submit Previous Answers Request Answer X Incorrect: Try Again; 5 attempts remaining CH₂On In CnH₂O -1.15 -1.30 -1.44 0.316 0.274 0.238 0.190 0.148 M Review Constants Periodic Table -1.60 -1.92
Catalysis and Enzymatic Reactions
Catalysis is the kind of chemical reaction in which the rate (speed) of a reaction is enhanced by the catalyst which is not consumed during the process of reaction and afterward it is removed when the catalyst is not used to make up the impurity in the product. The enzymatic reaction is the reaction that is catalyzed via enzymes.
Lock And Key Model
The lock-and-key model is used to describe the catalytic enzyme activity, based on the interaction between enzyme and substrate. This model considers the lock as an enzyme and the key as a substrate to explain this model. The concept of how a unique distinct key only can have the access to open a particular lock resembles how the specific substrate can only fit into the particular active site of the enzyme. This is significant in understanding the intermolecular interaction between proteins and plays a vital role in drug interaction.
can you help me understand how to find the constant rate to parts c - f
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