Suppose that whether it rains in a certain city tomorrow depends on the weather conditions for today and yesterday. Climate data showsthe following:If it rained yesterday and today, then it will rain tomorrow with probability 0.52.If it rained yesterday but not today, then it will rain tomorrow with probability 0.24.If it rained today but not yesterday, then it will rain tomorrow with probability 0.43.If it did not rain yesterday and today, then it will rain tomorrow with probability 0.34.Over the course of a year, about how many days in the city are rainy according to the model?The transition matrix for this Markov chain is given below.P=0.52 0 0.43 00.480 0.57 00 0.24 0 0.340 0.760 0.66OOver the course of a year, there are about rainy days.(Round to the nearest day as needed.)

Answered: Image /qna-images/answer/c740e476-1c7a-4e4d-abc2-2e375b08c606.jpg

Answered: Suppose that whether it rains in a…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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A company is introducing a new product into the market. If the sales are high, there is a 0.6 probability that they will remain so next month. If they are not, the probability that will become high next month is only 0.1. The company has the option of launching an advertisement campaign. If it does and the sales are high, the probability that they will remain high next month will increase to 0.7. On the other hand, an advertising campaign while the sales are low will raise the probability to only 0.3. If no advertisement is used and the sales are high, the returns (in thousands of dollars) are expected to be 9 if the sales remain high next month and 3 if they do not. The corresponding returns if the product starts with low sales are 6 and -3. Using advertisement will result in returns of 8 if the product starts with high sales and continues to be so and 5 if it does not. If the sales start low, the returns are 4 and -6, depending on whether or not they remain high. Compute the…
A company is introducing a new product into the market. If the sales are high, there is a 0.6 probability that they will remain so next month. If they are not, the probability that will become high next month is only 0.1. The company has the option of launching an advertisement campaign. If it does and the sales are high, the probability that they will remain high next month will increase to 0.7. On the other hand, an advertising campaign while the sales are low will raise the probability to only 0.3. If no advertisement is used and the sales are high, the returns (in thousands of dollars) are expected to be 9 if the sales remain high next month and 3 if they do not. The corresponding returns if the product starts with low sales are 6 and -3. Using advertisement will result in returns of 8 if the product starts with high sales and continues to be so and 5 if it does not. If the sales start low, the returns are 4 and -6, depending on whether or not they remain high. Obtain the…
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suppose that an airline has two flights each day from Toronto to Winnipeg; one scheduled at 9am and the other at 3pm. On any given day, the probability that the 9am flight departs on time is .81the probability that the 3pm flight departs on time is .68. The probability that neither depart on time is .21. Find the probability that the 3p flight does not depart on time. Find the probability that both flights depart on time. Find the probability that exactly one of the two flights depart on time. Full explanation (not too complicated) would be awesome
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