Suppose that we have the following stack, where the red line is the indicator for sp. The stack growsdownwards in main memory, just as it does in a regular RISC-V main memory. Both Wordo andWord1 occupy 1 word each:Word (Word1If we want to store the following contents of the stack: (i) a byte from to, (ii) a half word from t1, (iii)a word from t2, such that the stack becomes the following shown below:WordtoIt1t2So essentially, we are popping Word1 from stack and then pushing t0, t1 and t2 in order.Given the following RISC-V code:1 addi sp, sp,2 sb to,3 sh tl,4 SW t2,O -7,0, 1, 5Please select the proper number sequence to fill in the blanks in lines of code maintaining the correctorder. All the numbers in the options below are in decimalO-3, 0, 1, 5▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬(sp)(sp)(sp)O-3, 6, 4, 0O None of the options

Suppose that we have the following stack, where the red line is the indicator for sp. The stack grows downwards in main memory, just as it does in a regular RISC-V main memory. Both Word0 and Word1 occupy 1 word each: Word0 Word1 If we want to store the following contents of the stack: (i) a byte from to, (ii) a half word from t1, (iii) a word from t2, such that the stack becomes the following shown below: Word to t1 t2 So essentially, we are popping Word1 from stack and then pushing t0, t1 and t2 in order. Given the following RISC-V code: 1 addi sp, sp, 2 sb to, 3 sh tl, 4 sw t2, Please select the proper number sequence to fill in the blanks in lines of code maintaining the correct order. All the numbers in the options below are in decimal O -7,0, 1, 5 O-3, 0, 1, 5 (sp) (sp) (sp) O None of the options O-3, 6, 4, 0

Suppose that we have the following stack, where the red line is the indicator for sp. The stack grows downwards in main memory, just as it does in a regular RISC-V main memory. Both Word0 and Word1 occupy 1 word each: Word0 Word1 If we want to store the following contents of the stack: (i) a byte from to, (ii) a half word from t1, (iii) a word from t2, such that the stack becomes the following shown below: Word to t1 t2 So essentially, we are popping Word1 from stack and then pushing t0, t1 and t2 in order. Given the following RISC-V code: 1 addi sp, sp, 2 sb to, 3 sh tl, 4 sw t2, Please select the proper number sequence to fill in the blanks in lines of code maintaining the correct order. All the numbers in the options below are in decimal O -7,0, 1, 5 O-3, 0, 1, 5 (sp) (sp) (sp) O None of the options O-3, 6, 4, 0

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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2. Suppose the numbers 0, 1, 2, ., 9 were pushed onto a stack in that order, but that pops occurred at random points between the various pushes. The following is a valid sequence in which the values in the stack could have been popped: 3, 2, 6, 5, 7, 4, 1, 0, 9, 8 Explain why it is not possible that 3, 2, 6, 4, 7, 5, 1, 0, 9, 8 is a valid sequence in which the values could have been popped off the stack.
Use the C++ Standard Template Library's stack class to write a program for processing a file of postfix expressions. Recall that in a postfix expression, a binary operator comes after its two operands. Thus the infix expression (w + x) * (y – z) becomes w x + y z * in postfix. A postfix expression can be efficiently evaluated using a stack as follows. 1. Read the expression from the left to the right. 2. When an operand is encountered, push it on the stack. 3. When an operator is encountered, pop the top two elements from the stack, perform the operation, and then push the result. 4. There should be exactly one element on the stack at the end and this element is the value of the expression. For example, if the expression 20 5 – 3 * is entered, the evaluation should proceed as follows. Symbol read 20 Actions taken Push 20 5 Push 5 Pop 5, Pop 20, Push 20 – 5 Push 3 Pop 3, Pop 15, Push 15 * 3 The result of 45 should then be output. Your program should ask the user for the name of an input…
The solution is provided. Could you explain this question step by step.
Some applications require two types of accesses to the critical section-read access and write access. For these applications, it is reasonable for multiple read accesses to happen concurrently. However, a write access cannot happen concurrently with either a read access or a write access. Example: For a sequence [R1, R2, W1, R3] of requests, R1 and R2 should be able to access the critical section concurrently while W1 and R3 wait in the queue. Once R1 and R2 leave the critical section, W1 can enter the critical section while R3 waits in the queue. (a) Modify Lamport's algorithm for such applications. (b) Modify Ricart and Agrawala's algorithm for such applications.
Suppose your stack was allocated to be between addresses 0x20002000 and 0x200022FF. Imagine the stack pointer was currently pointing at 0x20002138. How many more words can you push to the stack and not have a problem for the following 4 stack policies: a)Empty ascending b)Empty descending c)Full ascending d)Full descending
Suppose that we are asked to run the program and when our program reaches to line 23, we are also asked to take a snapshot of our program's run-time stack. So, please draw full ARIS of the all subprograms which are placed in the stack at line 23. def sub1(): def sub2(isEverythingOk): def sub3(): print("in sub3") 1st = [1, 2, 3, 4, 5, 6, 7] for x, res in enumerate(lst): print (x,":",res) %3D sub2(false) print("end of sub3") 10 11 12- 13 14 - print("in sub2") if (isEverythingOk): sub3() else: 15 sub4() 16 print("end of sub2") 17 18 - def sub4(): | 19 - 20 21 22 23 24 25 26 27 28 29 def sub5(): print("in sub5") secondLst = [10, 50, 12, 45, 66, 73, 29] res = list(map(lambda x:x, secondLst)) print(res) # POSITION print("end of sub5") print("in sub4") sub5() print("end of sub4") print("in sub1") sub2(true) 30 31 32 print("end of sub1") N m 4 n6 7 00
4. Suppose we want to create a stack of names that vary in length. Why is it advantageous to store the names in separate areas of memory and then build the stack out of pointers to these names rather than allowing the stack to contain the names themselves?
How do I code the following stack in C program?
Solve the problem in the image
Write a program that converts an infix expression into an equivalent postfix expression. The rules to convert an infix expression into an equivalent postfix expression are as follows: Suppose infx represents the infix expression and pfx represents the postfix expression. The rules to convert infx into pfx are as follows: a. Initialize pfx to an empty expression and initialize the stack. b. Get the next symbol, sym, from infx. b.1. If sym is an operand, append sym to pfx. b.2. If symis (, push sym into the stack. b.3. If sym is ), pop and append all the symbols from the stack until the most recent left parenthesis. Pop and discard the left parenthesis. b.4. If sym is an operator: b.4.1. Pop and append all the operators from the stack to pfx that are above the most recent left ( and have precedence greater than or equal to sym. b.4.2. Push sym onto the stack. c. After processing infx, some operators might be left in the stack. Pop and append to pfx everything from the stack. In this…
Write an Arm Assembly Program that does the following:•Stores on the stack a list of words of memory where the first element of the list is how manyremaining elements are in the list, and the rest of the elements in the list are initialized tosome random values.– Example:list: 6, -3, 4, 5, 9, 22, 99//stores a list of the 6 elements -3, 4, 5, 9, 22, 99•At the end of the program, register r0 should hold the sum of only the negative values in thearray (nonnegative elements are ignored).•Note that your program must work correctly even if the values stored in the list are changed.
2. For the code below, draw a picture of the program stack when the function partition() is called the 2nd time. # extracted from suquant's reply at # https://stackoverflow.com/questions/18262306/quicksort-with-python def partition(array, begin, end): pivot = begin for i in range(begin+1, end+1): if array[i] <= array[begin]: pivot += 1 array[i], array[pivot] = array[pivot], array[i] array[pivot], array[begin] = array[begin], array[pivot] return pivot def quicksort(array, begin, end): if begin >= end: return pivot = partition(array, begin, end) quicksort(array, begin, pivot-1) quicksort(array, pivot+1, end) # added calling code if __name__ == "__main__": mylist = [8, 2, 17, 4, 12] quicksort(mylist, 0, 4)