.     For the code below, draw a picture of the program stack when the function partition() is called the first time. You only have to draw the part of the stack for quicksort() and partition().   # extracted from suquant's reply at # https://stackoverflow.com/questions/18262306/quicksort-with-python def partition(array, begin, end):     pivot = begin     for i in range(begin+1, end+1):         if array[i] <= array[begin]:             pivot += 1             array[i], array[pivot] = array[pivot], array[i]     array[pivot], array[begin] = array[begin], array[pivot]     return pivot   def quicksort(array, begin, end):     if begin >= end:         return     pivot = partition(array, begin, end)     quicksort(array, begin, pivot-1)     quicksort(array, pivot+1, end)   # added calling code if __name__ == "__main__":     mylist = [8, 2, 17, 4, 12]     quicksort(mylist, 0, 4)

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1.     For the code below, draw a picture of the program stack when the function partition() is called the first time. You only have to draw the part of the stack for quicksort() and partition().

 

# extracted from suquant's reply at

# https://stackoverflow.com/questions/18262306/quicksort-with-python

def partition(array, begin, end):

    pivot = begin

    for i in range(begin+1, end+1):

        if array[i] <= array[begin]:

            pivot += 1

            array[i], array[pivot] = array[pivot], array[i]

    array[pivot], array[begin] = array[begin], array[pivot]

    return pivot

 

def quicksort(array, begin, end):

    if begin >= end:

        return

    pivot = partition(array, begin, end)

    quicksort(array, begin, pivot-1)

    quicksort(array, pivot+1, end)

 

# added calling code

if __name__ == "__main__":

    mylist = [8, 2, 17, 4, 12]

    quicksort(mylist, 0, 4)

Expert Solution
Step 1

The first function named as partition will find the pivot element

This is the main line in this function

if array[i]<=array[i+1]

pivot+= 1

array[i],array[pivot] = array[pivot],arry[i]

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