3. A stack can be implemented with an array $ A[0..N-1] $ and a variable $ \text{pos} $. The push and pop operations are defined by the following code.```push(x) A[pos] ← x pos ← pos - 1end pushpop() pos ← pos + 1 return A[pos]end pop```Which of the following will initialize an empty stack with capacity $ N $ for this implementation?

Array An array is a group of homogeneous elements stored in contiguous memory locations. The…

Answered: A stack can be implemented with an…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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You are going to be asked to make a singly-linked list of singly-linked lists. How are you designing your data structure to best facilitate this design? Be sure to explain how the data is internally stored within your linked list of linked lists. (PI 1.1/ABET[1], PI 6.1/ABET[6]) #Python
You are allowed to operate on a stack WORK and a temporary stack TEMP (ifneeded) supporting their ADT operations of PUSH (S,X), POP (S, X) andEMPTYSTACK (S) only, where X represents an element/variable to be pushed in orpopped out of the stack and S represents a stack. You are also permitted to use onevariable if needed to carry out the operations.i) Given n distinct random numbers that are to be pushed into WORK, how canyou find the minimum element that was pushed into it? You are permitted to use alone variable.ii) Given n distinct random numbers that are to be pushed into WORK, how canyou find the maximum element that was pushed into it, all the while ensuring thatthe elements stored in WORK are in their descending order with the maximumelement beginning at the bottom of stack? You are permitted to use a lone variableand a temporary stack TEMP.iii) Given an array A[1: n] of distinct random numbers how can you obtain thesorted list in the array, making use of stacks alone?
Design a function bool validateStackSequences(const std::vector<int>& v) that takes an int vector with distinct values, and returns if values in v could be a valid sequence of stack operations You may assume the input values are always{1, 2, 3, 4, 5}. #include <vector> #include <stack> #include <iostream> // TODO: implement this function bool validateStackSequences(const std::vector<int>& v) { if (v.size() % 2 != 0) return false; std::stack<int> s; int i = 0; int j = v.size() - 1; while (i <= j) { if (v[i] == v[j]) { i++; j--; } else if (!s.empty() && s.top() == v[j]) { s.pop(); j--; } else { s.push(v[i]); i++; } } return s.empty(); } int main(){ // use following code snippet for testing // expected output: // true // false // true // false // true std::cout << std::boolalpha << validateStackSequences({5, 4, 3, 2, 1}) << std::endl; std::cout <<…
C4
You are allowed to operate on a stack WORK and a temporary stack TEMP (ifneeded) supporting their ADT operations of PUSH (S,X), POP (S, X) andEMPTYSTACK (S) only, where X represents an element/variable to be pushed in orpopped out of the stack and S represents a stack. You are also permitted to use onevariable if needed to carry out the operations.i) Given n distinct random numbers that are to be pushed into WORK, how canyou find the minimum element that was pushed into it? You are permitted to use alone variable.ii) Given n distinct random numbers that are to be pushed into WORK, how canyou find the maximum element that was pushed into it, all the while ensuring thatthe elements stored in WORK are in their descending order with the maximumelement beginning at the bottom of stack? You are permitted to use a lone variableand a temporary stack TEMP.iii) Given an array A[1: n] of distinct random numbers how can you obtain thesorted list in the array, making use of stacks alone?
Algorithm
Java code needed
:Symbols of stack are {a,b,c,d} {a,b,c,d,$} Uɛ {a,b] {a,b,$}Uɛ Answer about these questions: b, e>b c, bE d, aE a, e→a c, bE 93 d, aE 94 E, $→E 96 E, ES b, e > b
Asapp
2. For the code below, draw a picture of the program stack when the function partition() is called the 2nd time. # extracted from suquant's reply at # https://stackoverflow.com/questions/18262306/quicksort-with-python def partition(array, begin, end): pivot = begin for i in range(begin+1, end+1): if array[i] <= array[begin]: pivot += 1 array[i], array[pivot] = array[pivot], array[i] array[pivot], array[begin] = array[begin], array[pivot] return pivot def quicksort(array, begin, end): if begin >= end: return pivot = partition(array, begin, end) quicksort(array, begin, pivot-1) quicksort(array, pivot+1, end) # added calling code if __name__ == "__main__": mylist = [8, 2, 17, 4, 12] quicksort(mylist, 0, 4)
Quickly
PLease help fix my Python code, tell me also what's wrong ... def hasDuplicateParanthesis(expression): If not expression or len(expression) <= 3 : return False #empty stack of characters needed first Stack = deque () #traversing through the input expression for c in Expression : #if character is not a closing paranthesis If C != ‘)’: Stack.append(c) # if character having closed paranthesis else If stack[-1] == ‘(‘ : Return True #pop till ‘(‘ is found While stack[-1] != ‘(‘: stack.pop() Stack.pop() Return False if —name— == ‘__main__’: expression = ‘((X+Y))’ # let consider this a valid expression if HasDuplicateParanthesis(expression) Print (‘the given expression has duplicate paranthesis’) else: print (‘The expression does…

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