Suppose that the neighboring cities of Tweed and Ledee are long-term rivals. Neal, who was born and raised in Tweed, is confident that Tweed residents are more concerned about the environment than the residents of Ledee. He knows that the average electricity consumption of Tweed households last February was 654.32 kWh and decides to test if Ledee residents used more electricity that month, on average. He collects data from 45 Ledee households and calculates the average electricity consumption to be 687.81 kWh with a standard deviation of 117.17 kWh. There are no outliers in his sample data. Neal does not know the population standard deviation nor the population distribution. He uses a one-sample t-test with a significance level of a = 0.05 to test the null hypothesis, Ho: µ = 654.32, against the alternative hypothesis, H1:µ > 654.32, where µ is the average electricity consumption of Ledee households last February. Neal calculates a t-statistic of 1.917 and a P-value of 0.031. Based on these results, complete the following sentences to state the decision and conclusion of the test. Neal's decision is to the (P=0.031). There is evidence to the hypothesis that the average electricity consumption of iS *....... 1.......

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Based on these results, complete the following sentences to state the decision and conclusion of the test.
Neal's decision is to
the
(P = 0.031). There is
evidence to
the hypothesis that the average
electricity consumption of
is
Answer Bank
equal to
0.05
fail to accept
reject
all Ledee households
0.031
greater than
fail to reject
sample proportion
less than
687.81 kWh
45
null hypothesis
not equal to
insufficient
5%
no
the Ledee household sample
prove
1.917
alternative hypothesis
support
disprove
654.32 kWh
some
one-sample t-test
sufficient
ассеpt
117.17 kWh
!......
Transcribed Image Text:Based on these results, complete the following sentences to state the decision and conclusion of the test. Neal's decision is to the (P = 0.031). There is evidence to the hypothesis that the average electricity consumption of is Answer Bank equal to 0.05 fail to accept reject all Ledee households 0.031 greater than fail to reject sample proportion less than 687.81 kWh 45 null hypothesis not equal to insufficient 5% no the Ledee household sample prove 1.917 alternative hypothesis support disprove 654.32 kWh some one-sample t-test sufficient ассеpt 117.17 kWh !......
Suppose that the neighboring cities of Tweed and Ledee are long-term rivals. Neal, who was born and raised in Tweed, is
confident that Tweed residents are more concerned about the environment than the residents of Ledee. He knows that the
average electricity consumption of Tweed households last February was 654.32 kWh and decides to test if Ledee residents
used more electricity that month, on average. He collects data from 45 Ledee households and calculates the average
electricity consumption to be 687.81 kWh with a standard deviation of 117.17 kWh. There are no outliers in his
sample data.
Neal does not know the population standard deviation nor the population distribution. He uses a one-sample t-test with a
significance level of a = 0.05 to test the null hypothesis, Họ: µ = 654.32, against the alternative hypothesis,
H1:µ > 654.32, where u is the average electricity consumption of Ledee households last February. Neal calculates a
t-statistic of 1.917 and a P-value of 0.031.
Based on these results, complete the following sentences to state the decision and conclusion of the test.
Neal's decision is to
the
(P = 0.031). There is
evidence to
the hypothesis that the average
electricity consumption of
is
Transcribed Image Text:Suppose that the neighboring cities of Tweed and Ledee are long-term rivals. Neal, who was born and raised in Tweed, is confident that Tweed residents are more concerned about the environment than the residents of Ledee. He knows that the average electricity consumption of Tweed households last February was 654.32 kWh and decides to test if Ledee residents used more electricity that month, on average. He collects data from 45 Ledee households and calculates the average electricity consumption to be 687.81 kWh with a standard deviation of 117.17 kWh. There are no outliers in his sample data. Neal does not know the population standard deviation nor the population distribution. He uses a one-sample t-test with a significance level of a = 0.05 to test the null hypothesis, Họ: µ = 654.32, against the alternative hypothesis, H1:µ > 654.32, where u is the average electricity consumption of Ledee households last February. Neal calculates a t-statistic of 1.917 and a P-value of 0.031. Based on these results, complete the following sentences to state the decision and conclusion of the test. Neal's decision is to the (P = 0.031). There is evidence to the hypothesis that the average electricity consumption of is
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