Suppose our cache memory has parameters b = 4, l = 8, a = 1 ns, and μ = 16 ns. Assume that when necessary we replace the block in cache that was least-recently used, and that we set naccess=256 in the program fragment above. Consider the following table of estimated times per access in nanoseconds and show how each entry is derived. m = 16 m = 32 m = 64 m=128 S 1 2 4 8 16 1.125 1.125 1.125 1.125 1.063 1.250 1.250 3.000 5.000 1.250 9.000 1.250 17.000 1.125 1.250 3.000 5.000 9.000 17.000 17.000
Suppose our cache memory has parameters b = 4, l = 8, a = 1 ns, and μ = 16 ns. Assume that when necessary we replace the block in cache that was least-recently used, and that we set naccess=256 in the program fragment above. Consider the following table of estimated times per access in nanoseconds and show how each entry is derived. m = 16 m = 32 m = 64 m=128 S 1 2 4 8 16 1.125 1.125 1.125 1.125 1.063 1.250 1.250 3.000 5.000 1.250 9.000 1.250 17.000 1.125 1.250 3.000 5.000 9.000 17.000 17.000
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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![Suppose our cache memory has parameters b = 4, l = 8, a = 1 ns, and µ = 16 ns.
Assume that when necessary we replace the block in cache that was least-recently used,
and that we set naccess=256 in the program fragment above. Consider the following
table of estimated times per access in nanoseconds and show how each entry is derived.
S m = 16
m = 32 m = 64 m = 128
4
8
16
1.125
1.125
1.125
1.125
1.063
1.250
3.000
1.250
5.000
1.250
9.000
1.250 17.000
1.125
1.250
3.000
5.000
9.000
17.000
17.000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5dd9b50e-72ba-4ce3-b7d9-b8309d635da7%2Fb6d68dba-05e0-413c-92fb-d9953521be16%2Fcsu40b8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Suppose our cache memory has parameters b = 4, l = 8, a = 1 ns, and µ = 16 ns.
Assume that when necessary we replace the block in cache that was least-recently used,
and that we set naccess=256 in the program fragment above. Consider the following
table of estimated times per access in nanoseconds and show how each entry is derived.
S m = 16
m = 32 m = 64 m = 128
4
8
16
1.125
1.125
1.125
1.125
1.063
1.250
3.000
1.250
5.000
1.250
9.000
1.250 17.000
1.125
1.250
3.000
5.000
9.000
17.000
17.000
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