**Memory Allocation Exercise****Problem Statement:**If P3 is allocated, what is the Base Address (BA)?---**Solution:**Fill in the updated free list as follows:1. **BA:** [blank] ; **Sz:** [blank] → **BA:** [blank] ; **Sz:** [blank]2. [blank] → **BA:** [blank] ; **Sz:** [blank] → **BA:** [blank]---**Explanation:**In this exercise, you need to fill in the Base Address (BA) and Size (Sz) for each memory block in the updated free list after the allocation of P3. The arrows indicate the linkage or sequence of free memory blocks.Consider how memory is allocated and updated, and provide the corresponding BA and Sz values based on the allocation scenario provided. # Memory Management with Dynamic, Variable-Sized PartitioningConsider a memory of size 8KB (8192 bytes) that allows **dynamic, variable-sized** partitioning among processes and uses a linked list to keep track of free spaces (hereafter referred to as the *free list*) in the memory at any given time. Assume that there are 6 processes and each has specific memory size requirements (in bytes) as shown below:- **P1:** 500- **P2:** 600- **P3:** 1300- **P4:** 2000- **P5:** 100- **P6:** 200## Initial State of the Free ListAssume that the initial state of the free list is as follows. Here, *BA* is the base address and *Sz* is the size of each free space:- **BA: 0; Sz: 1100**- **BA: 1200; Sz: 600**- **BA: 2000; Sz: 1800**- **BA: 6000; Sz: 400**This setup allows efficient allocation and deallocation of memory for processes with varying demands, optimizing the use of available resources.

We will use fcfs technique to solve the above problem Given: p1 = 500 p2 = 600 p3 = 1300 p4 = 2000…

Answered: If P3 is allocated, what is the BA? The…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

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If P3 is allocated, what is the BA? The updated free list is: BA: ; Sz: → BA: ; Sz: → BA: ; Sz: → BA: ; Sz