Complete the function odd_even that classifies an number as either 'odd' or 'even' and the function classify tha takes in a list and applies odd_even to all elements in the list. def odd_even(x): """Classify a number as odd or even. >>> odd_even (4) 'even' >>> odd_even (3) 'odd' |||||| "*** YOUR CODE HERE ***" def classify(s): BEACH Classify all the elements of a sequence as odd or even assify ( [0, 1, 2, 4]) ['even', 'odd', 'even', 'even'] >>> "*** YOUR CODE HERE ***"

Complete the function odd_even that classifies an number as either 'odd' or 'even' and the function classify tha takes in a list and applies odd_even to all elements in the list. def odd_even(x): """Classify a number as odd or even. >>> odd_even (4) 'even' >>> odd_even (3) 'odd' |||||| "* YOUR CODE HERE " def classify(s): BEACH Classify all the elements of a sequence as odd or even assify ( [0, 1, 2, 4]) ['even', 'odd', 'even', 'even'] >>> " YOUR CODE HERE *"

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include <iostream>using namespace std;double median(int *, int);int get_mode(int *, int);int *create_array(int);void getinfo(int *, int);void sort(int [], int);double average(int *, int);int getrange(int *,int);int main(){ int *dyn_array; int students; int mode,i,range;float avrg;do{cout << "How many students will you enter? ";cin >> students;}while ( students <= 0 );dyn_array = create_array( students );getinfo(dyn_array, students);cout<<"\nThe array is:\n";for(i=0;i<students;i++)cout<<"student "<<i+1<<" saw "<<*(dyn_array+i)<<" movies.\n";sort(dyn_array, students);cout << "\nthe median is "<<median(dyn_array, students) << endl;cout << "the average is "<<average(dyn_array, students) << endl;mode = get_mode(dyn_array, students);if (mode == -1)cout << "no mode.\n";elsecout << "The mode is " << mode << endl;cout<<"The range of movies seen is…
'Split List' in Scheme:
Concatenate Map This function will be given a single parameter known as the Map List. The Map List is a list of maps. Your job is to combine all the maps found in the map list into a single map and return it. There are two rules for addingvalues to the map. You must add key-value pairs to the map in the same order they are found in the Map List. If the key already exists, it cannot be overwritten. In other words, if two or more maps have the same key, the key to be added cannot be overwritten by the subsequent maps. Signature: public static HashMap<String, Integer> concatenateMap(ArrayList<HashMap<String, Integer>> mapList) Example: INPUT: [{b=55, t=20, f=26, n=87, o=93}, {s=95, f=9, n=11, o=71}, {f=89, n=82, o=29}]OUTPUT: {b=55, s=95, t=20, f=26, n=87, o=93} INPUT: [{v=2, f=80, z=43, k=90, n=43}, {d=41, f=98, y=39, n=83}, {d=12, v=61, y=44, n=30}]OUTPUT: {d=41, v=2, f=80, y=39, z=43, k=90, n=43} INPUT: [{p=79, b=10, g=28, h=21, z=62}, {p=5, g=87, h=38}, {p=29,…
#include <iostream>#include <vector>using namespace std; void PrintVectors(vector<int> numsList) { unsigned int i; for (i = 0; i < numsList.size(); ++i) { cout << numsList.at(i) << " "; } cout << endl;} int main() { vector<int> numsList; int userInput; int i; for (i = 0; i < 3; ++i) { cin >> userInput; numsList.push_back(userInput); } numsList.erase(numsList.begin()+1); numsList.insert(numsList.begin()+1, 102); numsList.insert(numsList.begin()+1, 100); PrintVectors(numsList); return 0;} Not all tests passed clearTesting with inputs: 33 200 10 Output differs. See highlights below. Special character legend Your output 33 100 102 10 Expected output 100 33 102 10 clearTesting with inputs: 6 7 8 Output differs. See highlights below. Special character legend Your output 6 100 102 8 Expected output 100 6 102 8 Not sure what I did wrong but the the 33…
Question 15 kk .Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line
Q1: Assignment Difficulty Dan has a list of problems suitable for Assignment 4. The difficulties of these problems are stored in a list of integers a. The i-th problem’s difficulty is represented by a[i] (the higher the integer, the more difficult the problem). Dan is too busy eating saltines to worry about Assignment 4 decisions, so he asks Michael the TA to select at least two problems from the list for the assignment. Since there are many possible subsets of the problems to consider and Michael has a life, he decides to consider only sublists (definition follows) of the list of problems. To make grading the assignment easier, Michael wants to pick problems that don’t vary too much in difficulty. What is the smallest difference between the difficulties of the most difficult selected problem and the least difficult selected problem he can achieve by selecting a sublist of length at least 2 of the original list of problems? Definition: A sublist of a list a is any list you can obtain…
Higher-order function foldr: (X Y --> Y) Y ListOfX --> Y Which of the below is true? (select two) A) X and Y must be of different types B) X and Y must be of the same type C) The return type of foldr is a function that takes two arguments D) foldr takes a function as an input argument E) Y can't be a list F) The base case of the implicit recursion is of type Y
] ] get_nhbr In the cell below, you are to write a function called "get_nhbr(Ist, graph)" that takes in two inputs: a list of vertices and a graph. The function is to return a list that contains the neighborhood of the vertices in 'Ist' (remember that this means you are finding the union of the individual vertices' neighborhoods). + Code + Markdown After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (get_nhbr(["A", "D"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]}), get_nhbr(["B", "C", "F"], {"A" : ["B"], "B" : ["A", "D", "E"], "C" : ["E"], "D":["B"], "E":["B","C","F"], "F":["E"]})) This should return ["B"] ["A", "D", "E"] Python Python
Q1: Assignment Difficulty Dan has a list of problems suitable for Assignment 4. The difficulties of these problems are stored in a list of integers . The problem’s difficulty is represented by (the higher the integer, the more difficult the problem).ai-tha[i] Dan is too busy eating saltines to worry about Assignment 4 decisions, so he asks Michael the TA to select at least two problems from the list for the assignment. Since there are many possible subsets of the problems to consider and Michael has a life, he decides to consider only sublists (definition follows) of the list of problems. To make grading the assignment easier, Michael wants to pick problems that don’t vary too much in difficulty. What is the smallest difference between the difficulties of the most difficult selected problem and the least difficult selected problem he can achieve by selecting a sublist of length at least 2 of the original list of problems? Definition: A sublist of a list is any list you can obtain by…
T/F 25) If a is an ArrayList, we can say a.add(5); to add an integer to a.
Question 9 #include using namespace std; struct ListNode { string data; ListNode *next; }; int main() { ListNode *ptr, *list; list = new ListNode; list->data = "New York"; ptr = new ListNode; ptr->data = "Boston"; list->next = ptr; ptr->next = new ListNode; ptr->next->data = "Houston"; ptr->next->next = nullptr; // new code goes here Which of the following code correctly deletes the last node of the list when added at point of insertion indicated above? O delete ptr->next; ptr->next = nullptr;; O ptr = list; while (ptr != nullptr) ptr = ptr->next; delete ptr; O ptr = last; delete ptr; list->next->next = nullptr; delete ptr; O None of these
def distinct_last_name(full_names): ''' Question 5 You are given a large string that contains a list of full names separated by commas, you are asked to retrieve all distinct last names and store them in a set. Args: full_names (string) Returns: list >>> distinct_last_name('Harry Sharp, Chen Zhou, Tong Zhou, Dey Santanu') {'Sharp, Zhou, Santanu'} ''' # print(distinct_last_name('Harry Sharp, Chen Zhou, Tong Zhou, Dey Santanu'))