Hello! I've been trying to figure out this question and I still seem to be coming up with the wrong answer. Any help would be appreciated ! **Magnetic Fields and Wire Interaction**---**Question Overview:**Suppose in the drawing that \( I_1 = I_2 = 54.1 \, \text{A} \) and that the separation between the wires is \( 0.0390 \, \text{m} \). By applying an external magnetic field (created by a source other than the wires), it is possible to cancel the mutual repulsion of the wires. This external field must point along the vertical direction. **Questions:**- **(a)** Does the external field point up or down?- **(b)** What is the magnitude of the external field?**User's Response:**- **(a)** The external field points: *downward*- **(b)** Number: *220.776* Units: *T***Diagram Explanation:**The diagram illustrates two parallel wires, labeled as Wire 1 and Wire 2. Each wire carries a current (\( I_1 \) and \( I_2 \)) flowing in the same direction. The wires experience a mutual repulsion because of the magnetic fields they create. An external magnetic field is needed to counterbalance this repulsion. The diagram likely shows the direction of the external field and the repulsive forces.---**Note:**Ensure that you understand the principles of magnetic fields and how they interact with current-carrying wires. This setup demonstrates how an external field can be used to negate forces between wires, a crucial concept for electrical engineering and physics.---*Educational resources and additional reading materials can be found in the eTextbook and Media section. Assistance is available by following the provided hints and attempting additional exercises.*

Given: Current flowing in wire 1 I1=54.1 A Current flowing in wire 2 I2=54.1 A Where I=I1=I2…

Suppose in the drawing that = 12 = 54.1 A and that the separation between the wires is 0.0390 m. By applying an external magnetic field (created by a source other than the wires) it is possible to cancel the mutual repulsion of the wires. This external field must point along the vertical direction. (a) Does the external field point up or down? (b) What is the magnitude of the external field? Wire 1 Wire 2 12 Repution

Suppose in the drawing that = 12 = 54.1 A and that the separation between the wires is 0.0390 m. By applying an external magnetic field (created by a source other than the wires) it is possible to cancel the mutual repulsion of the wires. This external field must point along the vertical direction. (a) Does the external field point up or down? (b) What is the magnitude of the external field? Wire 1 Wire 2 12 Repution

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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