A sphere of radius 2m is made of a non-conducting material that has a uniform volume charge density p = 2.655 × 10-1ºC/m³. A spherical cavity of radius Im is then carved out from the sphere. As measured from the center of the large sphere, the center of the spherical cavity is at the position i = cos30°i + sin30°j. Find the electric field at a point P within the cavity. As measured from the center of the cavity, the point P is at the position = 0.5cos60°i + 0.5sin60°j.

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Hello, our professor asked this question during class but he explained it in a way I wasn't able to follow. Do you mind showing me how you'd solve it? Please handwrite if you could, just helps me follow. Thank you very much. Its attached down below. 

A sphere of radius 2m is made of a non-conducting material that has a uniform
volume charge density p = 2.655 x 10-1ºC/m³. A spherical cavity of radius Im is
then carved out from the sphere. As measured from the center of the large sphere,
the center of the spherical cavity is at the position ĩ= cos30°i + sin30°j.
Find the electric field at a point P within the cavity. As measured from the center
of the cavity, the point P is at the position ř = 0.5cos60ºi + 0.5sin60°j.
Transcribed Image Text:A sphere of radius 2m is made of a non-conducting material that has a uniform volume charge density p = 2.655 x 10-1ºC/m³. A spherical cavity of radius Im is then carved out from the sphere. As measured from the center of the large sphere, the center of the spherical cavity is at the position ĩ= cos30°i + sin30°j. Find the electric field at a point P within the cavity. As measured from the center of the cavity, the point P is at the position ř = 0.5cos60ºi + 0.5sin60°j.
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