Problem 22.47 8 of 10 <> A flat slab of nonconducting material has thickness 2d, which is small compared to its height and breadth. Define the z axis to be along the direction of the slab's thickness with the origin at the center of the slab (see the figure (Figure 1)). Constants | Periodic Table Part A If the slab carries a volume charge density pE (2) = -po in the region -d
Problem 22.47 8 of 10 <> A flat slab of nonconducting material has thickness 2d, which is small compared to its height and breadth. Define the z axis to be along the direction of the slab's thickness with the origin at the center of the slab (see the figure (Figure 1)). Constants | Periodic Table Part A If the slab carries a volume charge density pE (2) = -po in the region -d
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This is one qurstion, i need parts A,B, and D
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1
<Ch 22 HW
Problem 22.47
8 of 10
<>
Constants | Periodic Table
A flat slab of nonconducting material has
thickness 2d, which is small compared to its
height and breadth. Define the a axis to be
along the direction of the slab's thickness with
the origin at the center of the slab (see the figure
(Figure 1)).
Part A
If the slab carries a volume charge density pE (1) = -po in the region -d <a <0 and
PE (2) = +po in the region 0 < a <+d, determine the electric field E as a function of r in
the region outside the slab. Let po be a positive constant.
Figure
<
1 of 1>
y|
Eo =
Submit
Request Answer
+d
Part B
Determine the magnitude of the electric field E as a function of x in the region 0 <x<+d.
Express your answer in terms of the variables po, d, x, and appropriate constants.
Doongen
8:59 AM
66°F Sunny
4/5/2022
lp"
Transcribed Image Text:Tel#1000
1
<Ch 22 HW
Problem 22.47
8 of 10
<>
Constants | Periodic Table
A flat slab of nonconducting material has
thickness 2d, which is small compared to its
height and breadth. Define the a axis to be
along the direction of the slab's thickness with
the origin at the center of the slab (see the figure
(Figure 1)).
Part A
If the slab carries a volume charge density pE (1) = -po in the region -d <a <0 and
PE (2) = +po in the region 0 < a <+d, determine the electric field E as a function of r in
the region outside the slab. Let po be a positive constant.
Figure
<
1 of 1>
y|
Eo =
Submit
Request Answer
+d
Part B
Determine the magnitude of the electric field E as a function of x in the region 0 <x<+d.
Express your answer in terms of the variables po, d, x, and appropriate constants.
Doongen
8:59 AM
66°F Sunny
4/5/2022
lp

Transcribed Image Text:Home
A openvellum.ecollege.com/course.html?courseld3D171885608OpenVellumHMAC=cd77cb689785677ab4e844e1c830f1ef# 10001
akmarks
31
<Ch 22 HW
ome
Problem 22.47
8 of 10
>
A flat slab of nonconducting material has
thickness 2d, which is small compared to its
height and breadth. Define the r axis to be
along the direction of the slab's thickness with
the origin at the center of the slab (see the figure
(Figure 1)).
Constants| Periodic Table
Part D
Sharing
Determine the magnitude of the electric field E as a function of z in the region -d <a < 0.
Express your answer in terms of the variables po, d, z, and appropriate constants.
Figure
1 of 1
>
ΑΣΦ
?
+
Submit
Request Answer
+
-d
+d
Part E
Determine the direction of the electric field E in the region -d < I< 0.
to the left
Deensen
9:00 AM
66°F Sunny
4/5/2022
ere to search
lyp
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