CAN YOU PLEASE SOLVE PART D ON A PIECE OF PAPER, THANKS. A small marble (MA = 13.0 g ) slides to the left with avelocity of magnitude 20.0 cm/s on the frictionless,horizontal surface of an icy New York sidewalk and has ahead-on, elastic collision with a larger marble (MB = 33.0g) sliding to the right with a velocity of magnitude 54.0cm/s. Let +x be to the right. (Since the collision ishead-on, all the motion is along a line.) (Figure 1)Part C%3DWhat is the magnitude of the smaller marble's velocity after the collision?V A2 86.2 cm/sSubmitPrevious Answers>CorrectCorrect answer is shown. Your answer 86.15cm/swas either rounded differently or used a different number of significant figures than required for this part.Part D>What is the magnitude of the larger marble's velocity after the collision?Figure1 of 1?VB1V B2cm/sVA1=ColaMBSubmitRequest AnswerMANext >Provide Feedback

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A small marble (MA = 13.0 g ) slides to the left with a Part C velocity of magnitude 20.0 cm/s on the frictionless, horizontal surface of an icy New York sidewalk and has a head-on, elastic collision with a larger marble (Mg = 33.0 g) sliding to the right with a velocity of magnitude 54.0 cm/s. Let +æ be to the right. (Since the collision is head-on, all the motion is along a line.) (Figure 1) What is the magnitude of the smaller marble's velocity after the collision? VA2 86.2 cm/s Submit Previous Answers Correct Correct answer is shown. Your answer 86.15 cm/s was either rounded differently or used a different number of significant figures than required for this part. Part D Figure 1 of 1> What is the magnitude of the larger marble's velocity after the collision? VB1 ? VA1 VB2 cm/s MB Request Answer MA Submit Provide Feedback Next >

A small marble (MA = 13.0 g ) slides to the left with a Part C velocity of magnitude 20.0 cm/s on the frictionless, horizontal surface of an icy New York sidewalk and has a head-on, elastic collision with a larger marble (Mg = 33.0 g) sliding to the right with a velocity of magnitude 54.0 cm/s. Let +æ be to the right. (Since the collision is head-on, all the motion is along a line.) (Figure 1) What is the magnitude of the smaller marble's velocity after the collision? VA2 86.2 cm/s Submit Previous Answers Correct Correct answer is shown. Your answer 86.15 cm/s was either rounded differently or used a different number of significant figures than required for this part. Part D Figure 1 of 1> What is the magnitude of the larger marble's velocity after the collision? VB1 ? VA1 VB2 cm/s MB Request Answer MA Submit Provide Feedback Next >

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter11: Collisions

Section: Chapter Questions

Problem 73PQ: Three runaway train cars are moving on a frictionless, horizontal track in a railroad yard as shown...

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A 2-kg object moving to the right with a speed of 4 m/s makes a head-on, elastic collision with a 1-kg object that is initially at rest. The velocity of the 1-kg object after the collision is (a) greater than 4 m/s, (b) less than 4 m/s, (c) equal to 4 m/s, (d) zero, or (e) impossible to say based on the information provided.
From what might be a possible scene in the comic book The X-Men, the Juggernaut (mJ) is charging into Colossus (mC) and the two collide. The initial speed of the Juggernaut is vJi and the initial speed of Colossus is vCi. After the collision, the final speed of the Juggernaut is vJf and the final speed of Colossus is vCf as they each bounce off of the other, heading in opposite directions. a. What is the impulse experienced by the Juggernaut? b. What is the impulse experienced by Colossus? c. In your own words, explain how these impulses must compare with each other and how they are related to the average force each superhero experiences during the collision.
Initially, ball 1 rests on an incline of height h, and ball 2 rests on an incline of height h/2 as shown in Figure P11.40. They are released from rest simultaneously and collide elastically in the trough of the track. If m2 = 4 m1, m1 = 0.045 kg, and h = 0.65 m, what is the velocity of each ball after the collision?
What exhaust speed is required to accelerate a rocket in deep space from 800 m/s to 1000 m/s in 5.0 s if the total rocket mass is 1200 kg and the rocket only has 50 kg of fuel left?
You hold a slingshot at arms length, pull the light elastic band back to your chin, and release it to launch a pebble horizontally with speed 200 cm/s. With the same procedure, you fire a bean with speed 600 cm/s. What is the ratio of the mass of the bean to the mass of the pebble? (a) 19 (b) 13 (c) 1 (d) 3 (e) 9
A hockey puck of mass 150 g is sliding due east on a frictionless table with a speed of 10 m/s. Suddenly, a constant force of magnitude 5 N and direction due north is applied to the puck for 1.5 s. Find the north and east components of the momentum at the end of the 1.3-s interval.
Initially, ball 1 rests on an incline of height h, and ball 2 rests on an incline of height h/2 as shown in Figure P11.40. They are released from rest simultaneously and collide in the trough of the track. If m2 = 4 m1 and the collision is elastic, find an expression for the velocity of each ball immediately after the collision. FIGURE P11.40 Problems 40 and 41.
Pendulum bob 1 has mass m1. It is displaced to height h1 and released. Pendulum bob 1 elastically collides with pendulum bob 2 of mass m2 (Fig. P11.43). FIGURE P11.43 a. Find an expression for the maximum height h2 of pendulum bob 2. b. If m2 = 2.5m1 and h1 = 5.46 m, what is h2?
A rocket has total mass Mi = 360 kg, including Mfuel = 330 kg of fuel and oxidizer. In interstellar space, it starts from rest at the position x = 0, turns on its engine at time t = 0, and puts out exhaust with relative speed ve = 1 500 m/s at the constant rate k = 2.50 kg/s. The fuel will last for a burn time of Tb = Mfuel/k = 330 kg/(2.5 kg/s) = 132 s. (a) Show that during the burn the velocity of the rocket as a function of time is given by v(t)=veln(1ktMi) (b) Make a graph of the velocity of the rocket as a function of time for times running from 0 to 132 s. (c) Show that the acceleration of the rocket is a(t)=kveMikt (d) Graph the acceleration as a function of time. (c) Show that the position of the rocket is x(t)=ve(Mikt)ln(1ktMi)+vet (f) Graph the position during the burn as a function of time.
Three runaway train cars are moving on a frictionless, horizontal track in a railroad yard as shown in Figure P11.73. The first car, with mass m1 = 1.50 103 kg, is moving to the right with speed v1 = 10.0 m /s; the second car, with mass m2 = 2.50 103 kg, is moving to the left with speed v2 = 5.00 m/s, and the third car, with mass m3 = 1.20 103 kg, is moving to the left with speed v3 = 8.00 m /s. The three railroad cars collide at the same instant and couple, forming a train of three cars. a. What is the final velocity of the train cars immediately after the collision? b. Would the answer to part (a) change if the three cars did not collide at the same instant? Explain. FIGURE P11.73
A space probe, initially at rest, undergoes an internal mechanical malfunction and breaks into three pieces. One piece of mass ml = 48.0 kg travels in the positive x-direction at 12.0 m/s, and a second piece of mass m2 = 62.0 kg travels in the xy-plane at an angle of 105 at 15.0 m/s. The third piece has mass m3 = 112 kg. (a) Sketch a diagram of the situation, labeling the different masses and their velocities, (b) Write the general expression for conservation of momentum in the x- and y-directions in terms of m1, m2, m3, v1, v2 and v3 and the sines and cosines of the angles, taking to be the unknown angle, (c) Calculate the final x-components of the momenta of m1 and m2. (d) Calculate the final y-components of the momenta of m1 and m2. (e) Substitute the known momentum components into the general equations of momentum for the x- and y-directions, along with the known mass m3. (f) Solve the two momentum equations for v3 cos and v3 sin , respectively, and use the identity cos2 + sin2 = 1 to obtain v3. (g) Divide the equation for v3 sin by that for v3 cos to obtain tan , then obtain the angle by taking the inverse tangent of both sides, (h) In general, would three such pieces necessarily have to move in the same plane? Why?