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A projectile is launched in such a way that its maximum height is one-half its total range. At what angle was it launched? (Hint: Sin(20) = 2 Sin(0)Cos(0)

A projectile is launched in such a way that its maximum height is one-half its total range. At what angle was it launched? (Hint: Sin(20) = 2 Sin(0)Cos(0)

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Question:** A projectile is launched in such a way that its maximum height is one-half its total range. At what angle was it launched? **Hint:** \[ \sin(2\theta) = 2 \sin(\theta)\cos(\theta) \]
Transcribed Image Text:**Question:** A projectile is launched in such a way that its maximum height is one-half its total range. At what angle was it launched? **Hint:** \[ \sin(2\theta) = 2 \sin(\theta)\cos(\theta) \]
Expert Solution
Step 1

Expression for maximum height of the projectile - 

hmax=vi2sin2θ2g

Expression for total range of the projectile-

R=vi2sin2θg

Given that , 

Maximum height is one-half its total range. Means 

hmax=12R .....(1)

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