fast, wavy627wavy231fast, broad207fast207wavy, broad229fast, wavy, broadwild typeBased on this data, select the order of the three genes.O bfwfbwロwfbロfwbロbwf| w bf Attempt 2Suppose a geneticist is using a three-point testeross to map three linked Drosophila recessive mutations called f, w, and b,where fis associated with abnormally fast movement, w is associated with wavy movement pattern, and b is associatedwith broad wings. The geneticist first crosses homozygous broad flies to homozygous fast, wavy flies. Next, he testerossesthe Fi progeny to fast, wavy, and broad parents and obtains the results in the table.Fi testcross progeny phenotypeNumberbroad627fast, wavy627wavy231fast, broad207fast207wavy, broadfast, wavy, broad229wild typeBased on this data, select the order of the three genes.bfwO fb wOwfh

Answered: Image /qna-images/answer/143cf916-676d-440f-b406-667a7710bc07.jpg

Suppose a geneticist is using a three-point where f is associated with abnormally fast with broad wings. The geneticist first cros the Fi progeny to fast, wavy, and broad pa Fi testcross progeny phenoty broad fast, wavy wavy fast, broad fast wavy, broad hroad

Suppose a geneticist is using a three-point where f is associated with abnormally fast with broad wings. The geneticist first cros the Fi progeny to fast, wavy, and broad pa Fi testcross progeny phenoty broad fast, wavy wavy fast, broad fast wavy, broad hroad

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter19: Genomes And Proteomes

Section: Chapter Questions

Problem 16TYK

See similar textbooks

Similar questions

Flies homozygous for recessive null mutations in thesevenless (sev) or bride-of-sevenless (boss) genes have the same mutant phenotype: Every ommatidium(facet) in their eyes lacks photoreceptor cell 7 (R7).The R7 cells enable flies to detect UV light.a. Given that flies normally move toward light, suggest a screening method that would enable you toidentify mutations in additional genes required forR7 determination.b. Would you be able to recover mutations in everygene required for R7 development with yourmethod? Explain.c. How could you tell whether any of the new mutationsyou found in your screen are alleles of sev or boss?d. Suppose you found one recessive mutant allele ofa gene not previously known to be involved in eyedevelopment. How could you use this allele in anew mutagenesis screen to find additional allelesof this gene? Why might you want additional mutant alleles to study the process?
5.5
The Drosophila gene Sex lethal (Sxl) is deserving of itsname. Certain alleles have no effect on XY animals butcause XX animals to die early in development. Other alleles have no effect on XX animals but cause XY animals to die early in development. Thus, some Sxl allelesare lethal to females, while others are lethal to males.a. Would you expect a null mutation in Sxl to causelethality in males or in females? b. Why do Sxl alleles of either type cause lethality ina specific sex?The gene transformer (tra) gets its name from sexualtransformation, as some tra alleles can change XXanimals into morphological males, while other traalleles can change XY animals into morphologicalfemales.c. Which of these sex transformations would becaused by null alleles of tra and which would becaused by constitutively active alleles of tra?d. In contrast with Sxl, null tra mutations do notcause lethality either in XX or in XY animals.However, the Sxl protein regulates the productionof the Tra protein. Why…
. The human IGF2 gene is autosomal and maternallyimprinted. Copies of the gene received from themother are not expressed, but copies received fromthe father are expressed. You have found two allelesof this gene that encode two different forms of theIGF2 protein distinguishable by gel electrophoresis.One allele encodes a 60K (Kilodalton) blood protein;the other allele encodes a 50K blood protein. In ananalysis of blood proteins from a couple named Billand Joan, you find only the 60K protein in Joan’sblood and only the 50K protein in Bill’s blood. Youthen look at their children: Jill is producing only the50K protein, while Bill Jr. is producing only the 60Kprotein.a. With these data alone, what can you say about theIGF2 genotype of Bill Sr. and Joan?b. Bill Jr. and a woman named Sara have two children, Pat and Tim. Pat produces only the 60K protein and Tim produces only the 50K protein. Withthe accumulated data, what can you now say aboutthe genotypes of Joan and Bill Sr.?
Hello, i understand the question, but i only need to know which option is right, no need for explanation. I mean jsut say which option, thanks in advance.
Drosophila geneticists have isolated many mutationsthat modify position-effect variegation. Dominantsuppressors of variegation [Su(var)s] cause less frequent inactivation of genes brought near heterochromatin by chromosome rearrangements, whiledominant enhancers of variegation [E(var)s] causemore frequent inactivation of such genes.a. What effects would each of these two kinds of mutations have on position-effect variegation of thewhite gene in Drosophila (that is, would the eyesbe more red or more white)?b. Assuming that these Su(var) and E(var) mutationsare loss-of-function (null) alleles in the corresponding genes, what kinds of proteins do youthink these genes might encode?
Concerning the Tools of Genetics Box Analysis ofCell-Cycle Mutants in Yeast:a. Describe how you would use replica plating ofmutagenized, haploid yeast cells to identifytemperature-sensitive (ts) mutations in essentialgenes needed for yeast growth and survival.b. Among the many ts mutations you found in part(a), how would you distinguish mutations in genesneeded for cell-cycle progression from those ingenes needed for other aspects of the life of yeasts?c. If you had a large collection of yeast cell-cyclemutants, how would you determine which of themutations are in the same gene and which are indifferent genes?
You are interested in studying position effect variegation in Drosophila using the chromosome depicted below: Deactivation of the w+ gene gives a white eye phenotype and deactivation of the rst+ gene gives a rough eye phenotype; the normal phenotypes are red and smooth. Because the rst+ and w+ genes have now been placed close to a heterochromatic domain, some sections (or sectors) of the eye display mutant phenotypes due to gene deactivation while others display the normal, wild type phenotype. Which phenotype would you not expect to see rst w Inverted X chromosome white smooth eye sectors white rough eye sectors red smooth eye sectors red rough eye sectors
Researchers have exploited Minute mutations in orderto study the phenotypes associated with recessive lethal mutations (l−) that decrease the rate of cell divisionand thus make only very tiny homozygous mutant clones that are difficult to analyze. Many differentstrains of Drosophila carry dominant loss-of-functionMinute (M) mutations in a variety of genes encodingribosomal protein subunits. The M genes are haploinsufficient; flies with only one wild-type M+ gene copyhave a slower pace of cell division, and thus prolongeddevelopment and subtle morphological abnormalities.To circumvent the tiny clone problem, researchersgenerate GFP-marked homozygous l−/ l− clones thatare also M+/ M+, in flies that are l−/ l+ and M−/ M+.The loss of the Minute mutation only in cells withinthe clone gives the l−/ l− cells a growth advantageover their neighbors, enabling the mutant clone togrow large enough to study. Diagram chromosomesthat could be used to generate such clones
Recalling the eye pigment pathway in Drosophila, identify the phenotypes of the flies with the following genotypes. (w=white, bw=brown, cn=cinnabar red, st=scarlet red, se=sepia brown)
I need help please
5. please match each of the following