### Progeny Analysis and Gene MappingA cross is made between a heterozygote, +++/abc, and a recessive homozygote, abc/abc. Analysis of the progeny gave the following results:| Genotype | Progeny Count ||---------|----------------|| + + + | 450 || + + c | 10 || a + + | 70 || + b c | 210 || + b + | 65 || a + + | 200 || a b c | 460 || a b + | 15 |**Question: What is the map distance between the a and c genes?****Options:**- 25.12 map units- 27.71 map units- 29.39 map units- 32.53 map units- None of the above**Explanation of the Calculation:**Map distance between genes is calculated using the formula:\[ \text{Map Distance} = \left( \frac{\text{Number of Recombinants}}{\text{Total Number of Offspring}} \right) \times 100 \]For genes a and c, the recombinants are:- + + c = 10- a + + = 70- + b + = 65- a b + = 15Thus, the number of recombinants is \(10 + 70 + 65 + 15 = 160\).The total number of offspring is the sum of all progeny counts:\[ 450 + 10 + 70 + 210 + 65 + 200 + 460 + 15 = 1480 \]Now, applying the formula:\[ \text{Map Distance} = \left( \frac{160}{1480} \right) \times 100 \approx 10.81 \text{ map units} \]Since 10.81 map units is not an option provided, there's an oversight or error in given choices. Please review the progeny counts and sequences for a more accurate map distance.

Name: ### Progeny Analysis and Gene MappingA cross is made between a hetero
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: ### Progeny Analysis and Gene MappingA cross is made between a heterozygote, +++/abc, and a recessive homozygote, abc/abc. Analysis of the progeny gave the following results:| Genotype | Progeny Count ||---------|----------------|| + + + | 450