Suppose a computer using direct mapped cache has 2 32  bytes of byte-addressable main memory, and a cache size of 512 bytes, and each cache block contains 64 bytes. How many blocks of main memory are there? What is the format of a memory address as seen by cache, i.e. what are the sizes of the tag, block, and offset fields? To which cache block will the memory address 0x13A4498A map?

Q: A cache memory system with capacity of N words and block size of B words is to be designed. If it is…

A: For a 4-way set associative cache, the length of the TAG field is given below:

Q: 17 18 19 21 26 28 29 30 31 25 32 33 35 38 40 45 46 47 63 64 68 128 158 222 Cache C B E S t 1. 32…

A: As per the guidelines, solving the first 3 sub question 1. Memory bits = 32 Cache size = 1KB Block…

Q: Suppose a computer using direct mapped cache has 4M byte of byte-addressable main memory, and a…

A: Computer memory is a device that stores data and allows us to retrieve it when needed. Primary…

Q: 1. For a direct-mapped cache design with a 32-bit address, the following bits of address are used to…

A: Cache Design Analysis: Cache is a hardware component that is used to store frequently accessed data…

Q: Suppose a byte-addressable computer using set associative cache has 2^24 bytes of main memory and a…

A: In a set-associative cache,  it can be defined in such a way that the cache is divided into units,…

Q: In general, a cache is named according to the amount of data it contains (i.e., a 4 KiB cache can…

A: In questions with many questions we must answer the first.

Q: A cache is set up with a block size of 32 words. There are 16 blocks in cache and set up to be…

A: Block size = 32 words  Block Offset = 5 bits Total # of blocks inside cache = 16 So index bits = 4…

Q: 5. Suppose a byte-addressable computer using set-associate cache has 2^21 bytes of main memory and a…

A: If the number of address bits are n then, the size of the cache is 2n words. Since, the size of the…

Q: 3. Suppose a computer using direct mapped cache has 2^32 byte of byte-addressable main memory and a…

A: Solution:   a) It is given that the size of the main memory= 232 bytes Cache size = 1024 bytes = 210…

Q: Suppose a computer using direct mapped cache has 23232 bytes of byte-addressable main memory, and a…

A: I have answered this question in step 2.

Q: Here is the question:  A direct-mapped cache consists of 8 blocks. A byte-addressable main memory…

A: Calculate the misses and hits for the given program that loops 3 times from addresses 0 to 75 (base…

Q: Suppose a computer using fully associative cache has 4 Gbytes of byte-addressable main memory and a…

A: By "cache mapping," we mean the process by which data is transferred from the main memory into the…

Q: Suppose a byte-addressable computer using 8-way set associative cache has 256MB of main memory and a…

A: Solution ;   Main memory = 256MB Main memory in bits = log2(256M) = log2(228) = 28 bits

Q: Suppose a computer using fully associative cache has 4G bytes of byte-addressable main memory and a…

A: Cache mapping refers to the technique used for bringing content from the main memory into the cache…

Q: A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory…

A: A 64-bit word means 8 byte.Line size: 8 words in a line, means 8 x 8 bytes = 64 bytes in a line = 26…

Q: If each of the following addresses were accessed in sequence, identify if they would be a "hit" or a…

A: Solution is in Step 2.

Q: Suppose a byte-addressable computer using set associative cache has 4Mbyes of main memory and a…

A: Set-associative caches are an essential component of modern computer systems, aiming to improve data…

Q: A cache is set up with a block size of 32 words. There are 64 blocks in cache and set up to be 4-way…

A: Each block has 32 words, so the block offset = 25 words. So Block offset field can be represented by…

Q: 1. Suppose a computer using direct mapped cache has 2^20 bytes of byte-addressable main memory, and…

A: Given:- Size of main memory = 220 bytes           Size of blocks   = 24 bytes…

Q: 1. Suppose a computer has 2³2 bytes of byte-addressable main memory and a cache size of 2¹5 bytes,…

A: a) The total number of bytes of main memory is 232 bytes. Since each memory block contains 64 bytes,…

Q: 2. 2. Suppose a computer using direct-mapped cache has 2³2 bytes of byte-addressable main memory and…

A: Given Data Main Memory Size = 232 Bytes Number of Cache Blocks = 1024 = 210 Block Size = 32 Bytes =…

Q: By convention, a cache is named according to the amount of data it contains (i.e., a 4 KiB cache can…

A: To implement a 32 KiB cache with two-word blocks, we need to calculate the number of blocks and the…

Q: Cache Mapping Technique 1. Suppose a computer using direct-mapped cache has 2 bytes of…

A:

Q: Suppose a computer using direct mapped cache has 4G Bytes of main memory and a cache of 256 Blocks,…

A: refer to step 2 for the answer.

Q: Suppose a byte-addressable computer using set associative cache has 216 bytes of main memory and a…

A: Answer 1. 16 bits in an address cache contain 2^5 block. but each set must have 2 blocks so we have…