Suppose a 250. mL flask is filled with 1.2 mol of Cl₂ and 0.60 mol of HCl. The following reaction becomes possible: H₂(g) + Cl₂(g) 2HCl(g) The equilibrium constant K for this reaction is 0.409 at the temperature of the flask. Calculate the equilibrium molarity of H₂. Round your answer to two decimal places. M X S
Suppose a 250. mL flask is filled with 1.2 mol of Cl₂ and 0.60 mol of HCl. The following reaction becomes possible: H₂(g) + Cl₂(g) 2HCl(g) The equilibrium constant K for this reaction is 0.409 at the temperature of the flask. Calculate the equilibrium molarity of H₂. Round your answer to two decimal places. M X S
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![### Kinetics and Equilibrium: Calculating Equilibrium Composition from an Equilibrium Constant
**Problem Statement:**
Suppose a 250. mL flask is filled with 1.2 mol of Cl₂ and 0.60 mol of HCl. The following reaction becomes possible:
\[ \text{H}_2(g) + \text{Cl}_2(g) \rightleftharpoons 2\text{HCl}(g) \]
The equilibrium constant \( K \) for this reaction is 0.409 at the temperature of the flask.
**Task:**
Calculate the equilibrium molarity of \( \text{H}_2 \). Round your answer to two decimal places.
**Input Box:** [ \[ \text{M} \] ]
**Buttons:**
- Explanation
- Check
**Note:**
This problem involves calculating how the concentrations of reactants and products change until they reach equilibrium, using the provided equilibrium constant.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9be9a090-f726-46c3-84a4-96616934014f%2F8bced42a-7363-44c2-9900-fa4f8bce378b%2F7md8av_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Kinetics and Equilibrium: Calculating Equilibrium Composition from an Equilibrium Constant
**Problem Statement:**
Suppose a 250. mL flask is filled with 1.2 mol of Cl₂ and 0.60 mol of HCl. The following reaction becomes possible:
\[ \text{H}_2(g) + \text{Cl}_2(g) \rightleftharpoons 2\text{HCl}(g) \]
The equilibrium constant \( K \) for this reaction is 0.409 at the temperature of the flask.
**Task:**
Calculate the equilibrium molarity of \( \text{H}_2 \). Round your answer to two decimal places.
**Input Box:** [ \[ \text{M} \] ]
**Buttons:**
- Explanation
- Check
**Note:**
This problem involves calculating how the concentrations of reactants and products change until they reach equilibrium, using the provided equilibrium constant.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Step 1
Given ->
H2(g) + Cl2(g) <-----> 2HCl(g)
Mole of Cl2 = 1.2 mole
Mole of HCl = 0.60 mole
Equilibrium constant (Keq) = 0.409
Volume= 250 ml = 0.250 L (1L = 1000ml)
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