Suppose a 500. mL flask is filled with 1.0 mol of O₂ and 0.80 mol of NO. This reaction becomes possible: N₂(g) + O₂(g) 2NO(g) Complete the table below, so that it lists the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use x to stand for the unknown change in the molarity of N₂. You can leave out the M symbol for molarity. N₂ 0₂ NO initial 0 ? change x equilibrium

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### Chemical Equilibrium for the Reaction between Nitrogen and Oxygen

Suppose a 500 mL flask is filled with 1.0 mol of \( \text{O}_2 \) and 0.80 mol of \( \text{NO} \). The following reaction becomes possible:

\[ \text{N}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{NO}(g) \]

Complete the table below to list the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium.

Use \( x \) to stand for the unknown change in the molarity of \( \text{N}_2 \). You can leave out the \( \text{M} \) symbol for molarity.

|              | \( \text{N}_2 \) | \( \text{O}_2 \) | \( \text{NO} \) |
|--------------|------------------|------------------|-----------------|
| initial      |                  |                  |                 |
| change       |         \( x \)        |                  |                 |
| equilibrium  |                  |                  |                 |

> **Note:** The initial molarity of each compound is calculated using the number of moles and the volume of the flask.

#### Table Explanation
- **Initial**: Represents the starting molarity of each reactant (\( \text{N}_2 \) and \( \text{O}_2 \)) and product (\( \text{NO} \)) before the reaction starts.
- **Change**: Indicates the change in molarity of each compound as the reaction proceeds towards equilibrium. Here, \( x \) symbolizes the change in molarity for \( \text{N}_2 \).
- **Equilibrium**: Shows the molarity of each compound once the reaction has reached equilibrium.
Transcribed Image Text:### Chemical Equilibrium for the Reaction between Nitrogen and Oxygen Suppose a 500 mL flask is filled with 1.0 mol of \( \text{O}_2 \) and 0.80 mol of \( \text{NO} \). The following reaction becomes possible: \[ \text{N}_2(g) + \text{O}_2(g) \rightleftharpoons 2\text{NO}(g) \] Complete the table below to list the initial molarity of each compound, the change in molarity of each compound due to the reaction, and the equilibrium molarity of each compound after the reaction has come to equilibrium. Use \( x \) to stand for the unknown change in the molarity of \( \text{N}_2 \). You can leave out the \( \text{M} \) symbol for molarity. | | \( \text{N}_2 \) | \( \text{O}_2 \) | \( \text{NO} \) | |--------------|------------------|------------------|-----------------| | initial | | | | | change | \( x \) | | | | equilibrium | | | | > **Note:** The initial molarity of each compound is calculated using the number of moles and the volume of the flask. #### Table Explanation - **Initial**: Represents the starting molarity of each reactant (\( \text{N}_2 \) and \( \text{O}_2 \)) and product (\( \text{NO} \)) before the reaction starts. - **Change**: Indicates the change in molarity of each compound as the reaction proceeds towards equilibrium. Here, \( x \) symbolizes the change in molarity for \( \text{N}_2 \). - **Equilibrium**: Shows the molarity of each compound once the reaction has reached equilibrium.
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