Sulfur, S8, and oxygen, O2, react to form sulfur trioxide, SO3, in the (unbalanced) chemical reaction below. In a laboratory experiment, you begin with 20.1 g S8 and 29.6 g 02. You produce 43.2 g of pure SO3. What is the % yield for this reaction? S8 + 02 → SO3 + O2 SO3

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Sulfur, S8, and oxygen, O2, react to form sulfur trioxide, SO3, in the
(unbalanced) chemical reaction below. In a laboratory experiment,
you begin with 20.1 g Sg and 29.6 g 02. You produce 43.2 g of
pure SO3. What is the % yield for this reaction?
S8 + 02 → SO3
Use the following steps to answer this question:
1. Balance the chemical reaction
2. Determine the limiting reactant (using mass to mole
conversions & actual to theoretical mole comparison,
considering the stoichiometric ratios in the balanced reaction)
3. Determine the theoretical yield (in grams) of product (based
on the moles of the limit reactant and stoichiometric ratios in
the balanced reaction)
4. Calculate % yield using the actual mass and theoretical mass
of product
Transcribed Image Text:Sulfur, S8, and oxygen, O2, react to form sulfur trioxide, SO3, in the (unbalanced) chemical reaction below. In a laboratory experiment, you begin with 20.1 g Sg and 29.6 g 02. You produce 43.2 g of pure SO3. What is the % yield for this reaction? S8 + 02 → SO3 Use the following steps to answer this question: 1. Balance the chemical reaction 2. Determine the limiting reactant (using mass to mole conversions & actual to theoretical mole comparison, considering the stoichiometric ratios in the balanced reaction) 3. Determine the theoretical yield (in grams) of product (based on the moles of the limit reactant and stoichiometric ratios in the balanced reaction) 4. Calculate % yield using the actual mass and theoretical mass of product
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