Step 1 SOL:>, Forr AISI 304 stainless steel. density , P = 8000 kg mo Speci fic heat cppacity, Thermal Conductiritg C = 500 J =K= 16.2 W. mk. Given. h= 2.2X 0.5 = 2 2 X 43 2x10-3 = 322. 583 m2 K . = h Le K Biot num ber ; where Le-charactenistic length. Le = A =322·583 x 1X10-3 16.2 X 3 066

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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The problem was solved to verify the performance by doing the calculations in the image. Redo the same problem, but by changing the material to a cheaper one or one that will make it more efficient. Please include where you got the price of the material if you chose cheaper material or type of material if it will make it more efficient. Please show the work more clear with full steps

Step 1
SOL:>, For
AISI 304 stainless steel.
density , P = 8000 kg mo
Cppacity,
Thermal Conductivity
Specific heat
C = 500 J
=K= 16.2 W
Given.
h= 2,2X
V 10'5
0.5
= 2 2 x / 43
2x10-3
ニ
322. 583
m² K.
= h Lc
K.
Biot mum ber
; where Le-charactenistic leng th.
iLe= V
%3D
=322 583 x 1X10-3
16.2 X 3
= 0.0066
So, Lumped System approximalion applicable
Step 2
T- Too
hA
て、
= e Pev
T; - To
Ln (too)
て.
pev
99 % of Too .;
or,
4.60517 xP xex v
h x A
4. 60517X 8 000 × 500 X IX 10"
322.583 × 3
or,
t= 19.03 sec.
or,
+ 5% eror, the time o in limit.
with an approximation of
So, Hrermocouple vis comect,
Transcribed Image Text:Step 1 SOL:>, For AISI 304 stainless steel. density , P = 8000 kg mo Cppacity, Thermal Conductivity Specific heat C = 500 J =K= 16.2 W Given. h= 2,2X V 10'5 0.5 = 2 2 x / 43 2x10-3 ニ 322. 583 m² K. = h Lc K. Biot mum ber ; where Le-charactenistic leng th. iLe= V %3D =322 583 x 1X10-3 16.2 X 3 = 0.0066 So, Lumped System approximalion applicable Step 2 T- Too hA て、 = e Pev T; - To Ln (too) て. pev 99 % of Too .; or, 4.60517 xP xex v h x A 4. 60517X 8 000 × 500 X IX 10" 322.583 × 3 or, t= 19.03 sec. or, + 5% eror, the time o in limit. with an approximation of So, Hrermocouple vis comect,
The existing thermocouple has the following design data:
• Material: AISI 304 Stainless Steel
• Shape: Spherical (2 mm diameter)
• Heat transfer coefficient: h =
2.2(V/D)0.5
• Time to 0.99 A T: 18 seconds
• Minimum flow velocity: 43 m/s
Verify the performance of the existing thermocouple
• Check that for a minimum velocity of 43 m/s you can reach 99% of the T value at the center of the
thermocouple in 18 seconds
Transcribed Image Text:The existing thermocouple has the following design data: • Material: AISI 304 Stainless Steel • Shape: Spherical (2 mm diameter) • Heat transfer coefficient: h = 2.2(V/D)0.5 • Time to 0.99 A T: 18 seconds • Minimum flow velocity: 43 m/s Verify the performance of the existing thermocouple • Check that for a minimum velocity of 43 m/s you can reach 99% of the T value at the center of the thermocouple in 18 seconds
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