The test statistic of z = 0.51 is obtained when testing the claim that p>0.3.a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed.b. Find the P_value.c. Using a significance level of a 0.10, should we reject H, or should we fail to reject H,?Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.a. This is atest.b. P-value =(Round to three decimal places as needed.)C. Choose the correct conclusion belowO A Fail to reject H, There is sufficient evidence to support the clainm that p> 0 3OB. Reject H There is not sufficient evidence to support the claim that p>0.3O C. Reject H, There is sufficient evidence to support the claim that p> 0 3O D. Fail to reject H There is not sufficient evidence to support the claim that p >03

Solution: a. State the hypotheses. Null hypothesis: H0: p≤0.3 Alternative hypothesis: H1: p>0.3

Answered: The test statistic of z = 0.51 is…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Areas under the Normal Curve .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 0.5040 0.5438 0.5832 0.5199 0.5596 0.5239 0,5636 0.6026 0.5279 0,5675 0.6064 0.0 0.5000 0.5080 0.5120 0.5319 0.5714 0.6103 0.5160 0.5359 0.0 0.5753 0.1 0.2 0.5398 0.5478 0.5517 0.5557 0.1 0.5793 0.5871 0.5910 0.5948 0.5987 0.6141 0.2 0.6331 0.6700 0.6368 0.6480 0.6517 0.6879 0.6179 0.6217 0.6255 0.6628 0.6293 0.6664 0.6406 0.6443 0.6808 0.3 0.4 0.3 0.4 0.6554 0.6591 0.6736 0.6772 0.6844 0.6985 0.7324 0.7642 0.7224 0.7549 0.7852 0.5 0.6915 0.6950 0.7019 0.7054 0.7088 0.7123 0.7157 0.7190 0.5 0.6 0.7257 0.7291 0.7357 0.7389 0.7422 0.7734 0.7454 0.7486 0.7794 0.8078 0.7517 0.7823 0.6 0.7 0.7580 0.7611 0.7673 0.7704 0.7764 0.7 0.7995 0.8264 0.7939 0.8 0.9 0.8051 0.8315 0.8133 0.8389 0.7881 0.7910 0.7967 0.8023 0.8106 0.8 0.8159 0.8186 0.8212 0.8238 0.8289 0.8340 0.8365 0.9 1.0 0.8413 0.8485 0.8554 0.8770 0.8962 0.8599 0.8810 0.8438 0.8461 0.8508 0.8531 0.8577 0.8621 1.0 1.1 0.8643 0.8665 0.8686 0.8708 0.8830 0.8729 0.8925…
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reject Ho or should we fail to reject Ho? distribution table distribution table as needed.) support the clain ce to support the d ence to support the evidence to suppo 1 6 Y H N tv C FO & Standard Normal Distribution Table (Page 1) 7 9 MacBook Air U NEGATIVE z Scores J z -3.50 and lower -3.4 -3.3 -3.2 -3.1 -3.0 -2.9 -2.8 F7 e S74 M * Standard Normal (2) Distribution: Cumulative Area from the LEFT .00 .01 .02 .03 .04 .05 0001 8 0003 .0005 0007 0010 0013 .0019 0026 1 K DII FB 0003 .0005 .0007 .0009 .0013 0018 0025 V & a ( 6. 9 O 0003 0005 .0006 0009 0013 0018 0024 DD FO L ) O. V .0003 .0004 0006 .0009 0012 0017 0023 P F10 I command option .0003 .0004 .0006 .0008 .0012 0016 0023 - 0003 .0004 .0006 .0008 .0011 .0016 .0022 N fro { 4 [ ? 1 F11 +11 = 11 .06 0003 .0004 .0006 .0008 .0011 .0015 .0021 z F12 } 1 0 07 .0003 .0004 .0005 .0008 .0011 .0015 .0021 08 .0003 .0004 .0005 .0007 .0010 0014 0020 delete 38 return shi
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