The test statistic of z = 2.25 is obtained when testing the claim that p> 0.1. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a = 0.10, should we reject Ho or should we fail to reject Ho
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- Test the claim that the mean GPA of night students is larger than 3.1 at the 0.10 significance level.The null and alternative hypothesis would be: H0:p=0.775H0:p=0.775H1:p≠0.775H1:p≠0.775 H0:p=0.775H0:p=0.775H1:p>0.775H1:p>0.775 H0:μ=3.1H0:μ=3.1H1:μ>3.1H1:μ>3.1 H0:μ=3.1H0:μ=3.1H1:μ<3.1H1:μ<3.1 H0:p=0.775H0:p=0.775H1:p<0.775H1:p<0.775 H0:μ=3.1H0:μ=3.1H1:μ≠3.1H1:μ≠3.1 The test is: right-tailed two-tailed left-tailed Based on a sample of 75 people, the sample mean GPA was 3.14 with a standard deviation of 0.03The test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we fail to reject the null hypothesis. reject the null hypothesis.Test the claim that the mean GPA of night students is significantly different than 3.2 at the 0.2 significance level.The null and alternative hypothesis would be: (multiple choice) H0:p=0.8H0:p=0.8H1:p>0.8H1:p>0.8 H0:μ=3.2H0:μ=3.2H1:μ>3.2H1:μ>3.2 H0:p=0.8H0:p=0.8H1:p<0.8H1:p<0.8 H0:μ=3.2H0:μ=3.2H1:μ≠3.2H1:μ≠3.2 H0:μ=3.2H0:μ=3.2 H1:μ<3.2H1:μ<3.2 H0:p=0.8H0:p=0.8H1:p≠0.8H1:p≠0.8 The test is: (multiple choice) left-tailed right-tailed two-tailed Based on a sample of 30 people, the sample mean GPA was 3.17 with a standard deviation of 0.07The test statistic is: (to 2 decimals)The positive critical value is: (to 2 decimals)Based on this we: (multiple choice) Reject the null hypothesis Fail to reject the null hypothesisTest the claim that the mean GPA of night students is smaller than 2.3 at the .005 significance level. The null and alternative hypothesis would be: Ho:p = 0.575 Ho:u = 2.3 Ho:4 = 2.3 Ho:p = 0.575 Ho:p = 0.575 Ho:4 = 2.3 H1:p > 0.575 H : u> 2.3 H1:4 < 2.3 H1:p < 0.575 H :p + 0.575 H1:4 # 2.3 The test is: right-tailed two-tailed left-tailed Based on a sample of 60 people, the sample mean GPA was 2.25 with a standard deviation of 0.04 The test statistic is: {to 2 decimals) The critical value is: {to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
- Find the P-value for the indicated hypothesis test with the given standardized test statistic, z. Decide whether to reject H0 for the given level of significance α. Two-tailed test with test statistic z=−1.86 and α=Test the claim that the mean GPA of night students is larger than 2.5 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:µ > 2.5 Ho:µ = 2.5 H:µ 0.625 H:p=0.625 H:µ 2.5 H :p > 0.625 H:p< 0.625 H:p 0.625 The test is: right-tailed left-tailed two-tailed Based on a sample of 35 people, the sample mean GPA was 2.52 with a standard deviation of 0.08 The p-value is: (to 2 decimals). Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis Question Help: DVideo Message instructor メ NThe test statistic of z = 2.47 is obtained when testing the claim that p > 0.8. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of a = 0.05, should we reject Ho or should we fail to reject Ho? A. Fail to reject Ho. There is not sufficient evidence to support the claim that p > 0.8. B. Reject Ho. There is not sufficient evidence to support the claim that p > 0.8 C. Fail to reject Ho. There is sufficient evidence to support the claim that p > 0.8. D. Reject Ho. There is sufficient evidence to support the claim that p > 0.8.
- Find the P-value that corresponds to the given standard score, and determine whether to reject the null hypothesis at the 0.05 significance level. Is the alternative hypothesis supported? z=3.5 for H₁: μ=124.5 kilograms and H₂: μ# 124.5 kilograms The P-value is (Round to four decimal places as needed.) Determine whether the alternative hypothesis is supported at a 0.05 significance level. O A. The P-value is more than the significance level. Do not reject Ho. The alternative hypothesis is not supported. OB. The P-value is more than the significance level. Reject Ho. The alternative hypothesis is supported. OC. The P-value is less than or equal to the significance level. Reject Ho. The alternative hypothesis is supported. O D. The P-value is less than or equal to the significance level. Do not reject Ho. The alternative hypothesis is not supported.Find the P-value for the indicated hypothesis test with the given standardized test statistics z. Decide whether to reject H0 for the given level of significance α. Left-tailed test, z=-1.32, α=0.10 Right-tailed test, z=2.46, α=0.01 Two-tailed test, z=-1.68, α=0.05Test the claim that the mean GPA of night students is smaller than 2.5 at the .05 significance level.The null and alternative hypothesis would be: H0:p=0.625H0:p=0.625H1:p>0.625H1:p>0.625 H0:p=0.625H0:p=0.625H1:p<0.625H1:p<0.625 H0:μ=2.5H0:μ=2.5H1:μ≠2.5H1:μ≠2.5 H0:p=0.625H0:p=0.625H1:p≠0.625H1:p≠0.625 H0:μ=2.5H0:μ=2.5H1:μ>2.5H1:μ>2.5 H0:μ=2.5H0:μ=2.5H1:μ<2.5H1:μ<2.5 The test is: right-tailed two-tailed left-tailed Based on a sample of 55 people, the sample mean GPA was 2.49 with a standard deviation of 0.05The test statistic is: (to 2 decimals)The critical value is: (to 2 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
- Test the claim that the proportion of people who own cats is smaller than 60% at the 0.025 significance level. The null and alternative hypothesis would be: Ho: p=0.6 Ho:μ ≥ 0.6 Ho: p 0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 600 people, 53% owned cats The test statistic is: The p-value is: Based on this we: Ho:p>0.6 Ho: 0.6 Ho: μ 0.6 Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals) (to 2 decimals) =Test the claim that the proportion of men who own cats is larger than 20% at the .01 significance level. The null and alternative hypothesis would be: Ho: P 0.2 Hop 0.2 Hoμ = 0.2 H₁: p0.2 H₁ : μ 0.2 (to 2 decimals) (to 2 decimals) Ho: p = 0.2 0 H₁: p < 0.2Test the claim that the mean GPA of night students is larger than 2.8 at the .10 significance level. The null and alternative hypothesis would be: Ho: p=0.7 Ho: p = 0.7 Ho:μ = 2.8 Ho: H₁:p> 0.7 H₁:p 2.8 H₁: The test is: left-tailed two-tailed right-tailed o The test statistic is: 2.8 Ho:p = 0.7 Ho:μ = 2.8 0 <2.8 H₁:p 0.7 H₁: 2.8 Based on a sample of 40 people, the sample mean GPA was 2.83 with a standard deviation of 0.02 (to 2 decimals) The critical value is: = (to 2 decimals)