The null and alternative hypothesis would be: Но: и — 2.8 Нo:p 2 0.7 Но:р < 0.7 Но:р — 0.7 Но:д 2 2.8 Но:Д < 2.8 Hi:р + 2.8 Ні:р< 0.7 Hі:p > 0.7 Hi:р +0.7 Hi:д < 2.8 Ні:д > 2.8 The test is:

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### Hypothesis Testing for Mean GPA

In this exercise, we are testing the claim that the mean GPA of night students is smaller than 2.8 at the 0.025 significance level. Here's the process to follow:

#### Step 1: Define Hypotheses
The null and alternative hypotheses are defined as follows:

- Null Hypothesis (H₀): \( \mu = 2.8 \)
- Alternative Hypothesis (H₁): \( \mu < 2.8 \)

These hypotheses are designed to test if the mean GPA (\( \mu \)) of night students is less than 2.8.

#### Step 2: Determine the Test Type
We need to decide on the direction of the test. Since the alternative hypothesis states that the mean GPA is "less than" 2.8, this is a left-tailed test.

- **Select the test type:** 
  - Left-tailed (checked)
  - Right-tailed
  - Two-tailed

#### Step 3: Sample Data
In this case, we have the following sample data based on 30 students:
- Sample Mean GPA (\( \bar{x} \)): 2.79
- Standard Deviation (s): 0.03

#### Step 4: Calculate Test Statistic
We will use the sample data to calculate the test statistic. The formula for the test statistic (t) is:

\[ t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}} \]

Where:
- \( \bar{x} \) is the sample mean
- \( \mu \) is the population mean under the null hypothesis
- \( s \) is the sample standard deviation
- \( n \) is the sample size

#### Step 5: Find p-value
Using the test statistic calculated, we can then find the p-value. 

- **The Test Statistic is:** (input box for two decimal places)
- **The p-value is:** (input box for two decimal places)

#### Step 6: Make a Decision
Based on the p-value and the significance level (0.025), we will make a decision:

- If the p-value is less than 0.025, we **reject the null hypothesis**.
- If the p-value is greater than or equal to 0.025, we **fail to reject the null hypothesis**.

- **
Transcribed Image Text:### Hypothesis Testing for Mean GPA In this exercise, we are testing the claim that the mean GPA of night students is smaller than 2.8 at the 0.025 significance level. Here's the process to follow: #### Step 1: Define Hypotheses The null and alternative hypotheses are defined as follows: - Null Hypothesis (H₀): \( \mu = 2.8 \) - Alternative Hypothesis (H₁): \( \mu < 2.8 \) These hypotheses are designed to test if the mean GPA (\( \mu \)) of night students is less than 2.8. #### Step 2: Determine the Test Type We need to decide on the direction of the test. Since the alternative hypothesis states that the mean GPA is "less than" 2.8, this is a left-tailed test. - **Select the test type:** - Left-tailed (checked) - Right-tailed - Two-tailed #### Step 3: Sample Data In this case, we have the following sample data based on 30 students: - Sample Mean GPA (\( \bar{x} \)): 2.79 - Standard Deviation (s): 0.03 #### Step 4: Calculate Test Statistic We will use the sample data to calculate the test statistic. The formula for the test statistic (t) is: \[ t = \frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}}} \] Where: - \( \bar{x} \) is the sample mean - \( \mu \) is the population mean under the null hypothesis - \( s \) is the sample standard deviation - \( n \) is the sample size #### Step 5: Find p-value Using the test statistic calculated, we can then find the p-value. - **The Test Statistic is:** (input box for two decimal places) - **The p-value is:** (input box for two decimal places) #### Step 6: Make a Decision Based on the p-value and the significance level (0.025), we will make a decision: - If the p-value is less than 0.025, we **reject the null hypothesis**. - If the p-value is greater than or equal to 0.025, we **fail to reject the null hypothesis**. - **
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